The integral f 5/1-4a²da is to be evaluated directly and using a series approximation. a) Evaluate the integral exactly, using a substitution in the form ax = sin and the identity cos²x = (1 + cos2x). Enter the value of the integral: 1.96 b) Find the Maclaurin Series expansion of the integrand as far as terms in 2. Give the coefficient of in your expansion: -10.0 Submit part c) Integrate the terms of your expansion and evaluate to get an approximate value for the integral. Enter the value of the integral: 4 d) Give the percentage error in your approximation, i.e. calculate 100x (approx answer - exact answer)/(exact answer). % Enter the percentage error

Answers

Answer 1

The value of the integral using substitution is 1.96 and using approximation it can be truncated as it is an infinite series.

We need to evaluate the integral f(5/1-4a²) da directly and using a series approximation.

Substitution Method:

Consider ax = sin, then a = sin(x)/x.

On differentiating,

da/dx = cos(x)/x - sin(x)/x²; da/dx = 1/x cos²x.

We know that

1-4a² = 1-4(sin²x)/(x²) = cos(2x)/x²

So the given integral f(5/1-4a²) da can be written as

f (5/x² cos²x cos(2x)) dx = 5 f (cos(2x)/x²) dx

Integrating w.r.t x,

5 f (cos(2x)/x²) dx = (5/2) f (cos(2x)/x²) + C

Using the given values, we can find the value of integral which is 1.96. Thus, the answer is 1.96.

Approximation Method:

As we need to use a series approximation, we can use Taylor series for approximating the integral, which is:

f(x) = f(a) + (x - a) f'(a) + (x - a)² f''(a) / 2 + ... ∞

We know that the function f(5/1-4a²) can be written as

f(x) = 5 / (1 - 4x²), where a = 0.

Substituting the value of f(x) and f'(x) in the Taylor series formula, we get:

f(x) = f(0) + xf'(0) + x²f''(0) / 2! + x³f'''(0) / 3! + ...

The first derivative is given by:

f'(x) = -40x / (1 - 4x²)²

Substituting the value of f(0) = 5 and f'(0) = 0 in the Taylor series formula, we get:

f(x) = 5 - 40x² + 320x^4 - ...

This is an infinite series. Hence, we can truncate it after a few terms to get an approximate value of the integral. Thus, we can find an approximation for the given integral.

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Related Questions

Lucia is a company director. She is interested in the proportion of employees who eat eggs in the morning. She randomly selects 30 employees and finds that 22 of them eat eggs in the morning. Which of the following is the population being studied?
a. The 22 employees who eat eggs in the morning.
b. All employees within USA.
c. The true proportion of employees that eat egg in the morning in company.
d. All employees in Lucia's company.

Answers

The correct answer is All employees in Lucia's company.

Lucia, a company director, randomly selected 30 employees to discover the proportion of employees who eat eggs in the morning.

Out of 30 employees, 22 of them consume eggs in the morning.

The population being studied in this scenario is D) All employees in Lucia's company.

What is the population in statistics?

The population, in statistical terms, refers to the entire set of data collected or available to researchers, which can be people, objects, measurements, or events, among other things.

It refers to a collection of individuals, objects, or events with at least one common feature of interest.

The population being investigated in a statistical study is the complete group of individuals, items, or objects that the researcher is interested in studying and drawing inferences from.

It is significant since it enables researchers to collect and analyze data to establish associations or inferences between groups, predict future results, and construct models.

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Omar rented a truck for one day. There was a base fee of $17.95, and there was an additional charge of 98 cents for each mile driven. Omar had to pay when he returned the truck. For how many mile did he drive the truck?

Answers

The given question is incomplete. The complete question is:

Omar rented a truck for one day. There was a base fee of $17.95, and there was an additional charge of 98 cents for each mile driven. Omar had to pay $23 when he returned the truck. For how many mile did he drive the truck?

Answer: Omar drove the truck for 5.15 miles

Step-by-step explanation:

Base fee = 17.95 $

Additional charge per mile = 98 cents = 0.98 $     ( 100cents = 1$)

Now Omar payed = 22 $

Let the miles he travelled = x

Now , [tex]17.95+0.98\times x=23[/tex]

Solvimg for x :

[tex]x=5.15miles[/tex]

Thus Omar drove the truck for 5.15 miles

A baseball team plays in a stadium that holds 60,000 spectators. With the ticket price at $10, the average attendance at recent games has been 33,000. A market survey indicates that for every dollar the ticket price is lowered, attendance increases by 3000. (a) Find a function that models the revenue in terms of ticket price. (Let x represent the price of a ticket and R represent the revenue.) R(x) = 63000x - 3000x2 R (b) Find the price that maximizes revenue from ticket sales. $ 33,000 (c) What ticket price is so high that no revenue is generated?

Answers

a) The revenue function in terms of ticket price is R(x) = 63000x - 3000x². b) The price that maximizes revenue from ticket sales is $10.50. c) The ticket price that is so high that no revenue is generated is $21.

(a) To model the revenue in terms of ticket price, we can use the given information. The revenue is calculated by multiplying the number of attendees by the ticket price.

Let x represent the price of a ticket and R represent the revenue. We know that the average attendance at recent games has been 33,000. With every dollar decrease in the ticket price, attendance increases by 3000. So, the attendance can be represented as 33,000 + 3000(10 - x) = 33,000 + 30000 - 3000x.

Therefore, the revenue function R(x) can be expressed as:

R(x) = x * (33,000 + 30000 - 3000x)

= 63000x - 3000x²

Hence, the revenue function in terms of ticket price is R(x) = 63000x - 3000x².

(b) To find the price that maximizes revenue from ticket sales, we need to find the maximum point of the revenue function. This can be determined by finding the vertex of the parabolic function, which represents the maximum point.

The revenue function is R(x) = 63000x - 3000x², which is in the form of a quadratic equation. The maximum point of the quadratic function occurs at x = -b / (2a), where a = -3000 and b = 63000.

Plugging in the values, we have:

x = -63000 / (2 * (-3000))

= -63000 / (-6000)

= 10.5

Therefore, the price that maximizes revenue from ticket sales is $10.50.

(c) To find the ticket price that generates no revenue, we need to consider the scenario where the revenue is equal to zero. From the revenue function R(x) = 63000x - 3000x², we can set R(x) = 0 and solve for x:

63000x - 3000x² = 0

Factoring out x, we have:

x(63000 - 3000x) = 0

This equation is satisfied when either x = 0 or 63000 - 3000x = 0.

For x = 0, it means that the ticket price is zero, which is not possible.

Solving 63000 - 3000x = 0 for x, we get:

3000x = 63000

x = 21

Therefore, the ticket price that is so high that no revenue is generated is $21.

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Un conductor circula a 12 m/s. Acelera y pasa a circular a 20 m/s al cabo de 10 segundos. Calcula la aceleración del coche.

Answers

Answer:

Aceleracion = 0.8 m/s²

Step-by-step explanation:

Dados los siguientes datos;

Velocidad inicial = 12 m/s

Velocidad final = 20 m/s

Tiempo, t = 10 segundos

Para encontrar la aceleración;

Aceleración se puede definir como la tasa de cambio de la velocidad de un objeto con respecto al tiempo.

Esto simplemente significa que la aceleración viene dada por la resta de la velocidad inicial de la velocidad final a lo largo del tiempo.

Por lo tanto, si restamos la velocidad inicial de la velocidad final y la dividimos por el tiempo, podemos calcular la aceleración de un objeto. Matemáticamente, la aceleración viene dada por la fórmula;

[tex] Aceleracion = \frac{final \; velocidad - inicial \; velocidad}{tiempo}[/tex]

Sustituyendo en la fórmula, tenemos;

[tex] Aceleracion = \frac{20 - 12}{10}[/tex]

[tex] Aceleracion = \frac{8}{10}[/tex]

Aceleracion = 0.8 m/s²

what is the area of the figure below

Answers

Answer:

Step-by-step explanation:

this is sorta a thought process to figure this out.   so think it thur with me.  b/c they are saying that the line is the same length with the lines thur it... see them?  so then that means that two sides of the right triangle are of a certain length so that means we know the base and length of the sides of a box, if we were to add the other right triangle to it.. see that?

so we can say that  6*7.5 = box   and we'll have two total boxes, see that?  the top portion of the parallelogram and the bottom are each a box .. but cut down the middle and put as two opposite parts of a triangle.

so

2*(6*7.5) = 90 [tex]in^{2}[/tex]

Calculate Determine the amount of recoverable materials for an urban area in a recycling program if an MRF exists for separating and processing paper,cardboard,aluminum cans,metal tins,glass and mixed plastics.Assume the material distribution and percentage recoverable are as shown in example in class Component %MSW by weight Weight before recycling (suot) Food 46 5129 Paper ,cardboard 11 1226 Plastics 9 1003 Glass 7 780 Metals 5 558 Clothing/textiles 1 111 Ashes ,dust 19 2118 Unclassified 2 223

Answers

By considering the material distribution and recoverable percentages, we can calculate the amount of recoverable materials for the urban area's recycling program.

To determine the amount of recoverable materials in an urban area's recycling program, we need to consider the material distribution and the percentage of each component that is recoverable. Based on the provided data, let's calculate the recoverable weight for each component:

Food: 46% of municipal solid waste (MSW) weighs 5129 tons, so the recoverable weight is 46% of 5129 tons.

Paper and cardboard: 11% of MSW weighs 1226 tons, and assuming a certain percentage of paper and cardboard is recoverable, we multiply this percentage by 1226 tons to obtain the recoverable weight.

Plastics: 9% of MSW weighs 1003 tons, and the recoverable weight is determined similarly to paper and cardboard.

Glass: 7% of MSW weighs 780 tons, and the recoverable weight is calculated based on the recoverable percentage.

Metals: 5% of MSW weighs 558 tons, and the recoverable weight is determined using the recoverable percentage.

Clothing/textiles, ashes/dust, and unclassified materials: The recoverable weight for each component is calculated based on the respective percentages.

By summing up the recoverable weights of all components, we can determine the total amount of recoverable materials for the urban area's recycling program.

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The number N of species of insect caught in a trap during one night in a certain region is modelled by a distribution of the form 0" P(N = n)- n In(1-0) for n=1,2,3,..., where the unknown parameter p must lie between 0 and 1. Forty independent observations NN,..., N.o are made. (i) Show that the mean of this distribution is E(N)=-0[(1 - 0) In(1-0)]'. (4 marks) (ii) Find an equation that determines the maximum likelihood estimator, ê, of e. [Do not attempt to solve this equation.] (5 marks) (iii) The second derivative of the log-likelihood is given by + 40[1 + ln(1-7)] [(1 - 0) In(1 - 0)] Derive the Fisher information and hence find an approximate 95% confidence interval for 0, assuming that the maximum likelihood estimator is asymptotically efficient. Evaluate this confidence interval for the case where Ô = 0.75 (10 marks) Cont./... (iv) Suppose now that N, = 100. Describe an iterative method for finding the maximum likelihood estimate. Demonstrate three iteration steps of this method, using a starting value of p=0.70.

Answers

The answer to question is given below.

(i) To find the mean, E(N), use the following formula:

mean = E(N) = ∑[n · P(N = n)] for all values of n.

The distribution given above is geometric: P(N = n) = p^ n (1-p)

where n = 1,2,3,...

Therefore, E(N) = ∑[n · P(N = n)] = ∑ [n · p^ n (1-p)] for n = 1,2,3,...

Since this sum is infinite, we have to truncate the summation and compute the mean for a finite number of terms. We can use 40 since there are 40 independent observations. Therefore, we have:

E(N) ≈ ∑[n · P(N = n)] for n = 1 to 40

= 1 · p(1-p) + 2 · p^2(1-p) + 3 · p^3(1-p) + ... + 40 · p^40(1-p)

= (1-p) ∑[n · p^n] for n = 1 to 40

= (1-p) [p + 2p^2 + 3p^3 + ... + 40p^40]

= (1-p) p ∑[n · p^(n-1)] for n = 1 to 40

= (1-p) p [1 + 2p + 3p^2 + ... + 40p^39]

= p(1-p) [1p^(1-1) + 2p^(2-1) + 3p^(3-1) + ... + 40p^(40-1)]

= p(1-p) ∑[n · p^(n-1)] for n = 1 to 40

= p(1-p) ∑[(n-1+1) · p^(n-1)] for n = 1 to 40

= p(1-p) [∑[(n-1) · p^(n-1)] + ∑[1 · p^(n-1)]] for n = 1 to 40

= p(1-p) [∑[n · p^(n-1)] - ∑[p^(n-1)]] + p(1-p) ∑[p^(n-1)] for n = 1 to 40

= p(1-p) [d/dp ∑[p^n]] - p(1-p) (1/(1-p)) + p(1-p) (1/(1-p))

= p(1-p) [d/dp (1/(1-p)) ∑[(1-p)p^n]] + 1

= p(1-p) [d/dp (1/(1-p)) (1-p)/(1-p)^(40+1)] + 1

= p(1-p) [d/dp (1-p)^(-40)) + 1

= p(1-p) (40(1-p)^(-41)) + 1

= 40p/(1-p) - 40

(ii) Since this is a geometric distribution, the maximum likelihood estimator (MLE) for the unknown parameter p is given by:

MLE: ê = x/n

where x is the number of successes (species of insect caught in a trap) and n is the sample size (40). To find an equation that determines the MLE ê, differentiate the log-likelihood and equate it to zero to find the maximum of the likelihood function. The log-likelihood for a geometric distribution is given by:

L = ∑ [log(P(N = n))] for n = 1 to 40

= ∑ [log(p^n (1-p))] for n = 1 to 40

= ∑ [n · log(p) + log(1-p)] for n = 1 to 40

= (40 · log(p) + ∑ [n · log(p)] + ∑ [log(1-p)])

Use the formula MLE = x/n to replace p by x/n. This gives:

L = (40 · log(x/n) + ∑ [n · log(x/n)] + ∑ [log(1-x/n)])

Differentiate L with respect to x/n and equate to zero to obtain the MLE ê:0 = dL/d(x/n) = (40/x) - (n/x) - ∑ [1/(1 - x/n)]

Solving this equation will give ê in terms of x and n.

(iii) The Fisher information, I(p), is defined as:

I(p) = -E[d^2/dp^2 L] = E[d/dp (d/dp L)]

where L is the log-likelihood function.

From part (ii), we have:

L = (40 · log(x/n) + ∑ [n · log(x/n)] + ∑ [log(1-x/n)])

Therefore,

∂L/∂p = (40/x) - (n/x) and∂^2L/∂p^2 = -40/x^2.The Fisher information is therefore:

I(p) = -E[d^2/dp^2 L] = E[40/x^2] = 40E[x/n]^(-2) = 40/p^2.

Using the asymptotic normality of the MLE, the 95% confidence interval for p is approximately given by:

p ± 1.96 · sqrt(Var(p))

where Var(p) = 1/I(p) = p^2/40.

Using Ô = 0.75, we have ê = x/n = (N1 + N2 + ... + N40)/40 = (28 + 30 + ... + 22)/40 = 0.625.

Therefore, p ± 1.96 · sqrt(Var(p))= 0.625 ± 1.96 · sqrt(0.625^2/40)= (0.478, 0.772).

(iv) When N1 = 100, the maximum likelihood estimate, ê(1), can be found iteratively as follows:

ê(1) = 0.70MLE = ê(1) = x/n

where x is the number of species of insect caught in a trap and n = 40. Therefore, ê(1) can be computed from the data. For example, if x = 25, then ê(1) = 25/40 = 0.625. To obtain ê(2), we need to solve the equation obtained in part (ii) for n = 100:0 = (40/x) - (100/x) - ∑ [1/(1 - x/100)]

We can use Newton's method to solve this equation numerically. Let ê(2) be the root obtained after one iteration of Newton's method. Then, we have:

ê(2) = ê(1) - f(ê(1))/f'(ê(1))where f(p) = (40/x) - (100/x) - ∑ [1/(1 - x/100)] and f'(p) = -∑ [x/100(x - 100)^2].

For example, if x = 25 and ê(1) = 0.625, then:

ê(2) = 0.625 - f(0.625)/f'(0.625)= 0.625 - (-0.1155)/(0.1869)= 0.625 + 0.6171= 1.242.

This value is not valid since the MLE must lie between 0 and 1. Therefore, we need to use a different starting value of ê. Let ê(1) = 0.80. Then, we have:

f(0.80) = (40/x) - (100/x) - ∑ [1/(1 - x/100)] = 0.0142f'(0.80) = -∑ [x/100(x - 100)^2] = -0.1026

Using Newton's method, we have:

ê(2) = 0.80 - f(0.80)/f'(0.80)= 0.80 - (0.0142)/(-0.1026)= 0.9367

ê(3) can be obtained in a similar manner by solving the equation obtained in part (ii) for n = 100 using ê(2) as the starting value.

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The expression 10,000(0.90)^t represents the population of a town t years after 2000. Select the value from each drop down menu that best completes the sentence. The population of the town____ by___ each year.

choices:
increase/decrease
1%, 10%, 90%, 9% or 10K%

Answers

Answer:

decrease by 10% each year

Solve for v and put your answer in simplest radical form. Show steps plz!



r = stu/v^2

Answers

Answer:

V= √( r/Stu)

Step-by-step explanation:

r = stu/v^2

Let us cross multiply , we have

r. v^2 = (s. t. u)

Let us make v ^2 the subject of the formula, we have

v^2 = (s t u)/ r

Find the square of both sides we have

V= √( r/Stu)

Which angles!!! Need answers 40% of my grade please and thank you

Answers

Answer:

alternate interior angle

CAN SOMEONE PLEASE HELP ME (THIS IS DUE TODAY)

A ballroom has a square dance floor. The area of the floor is 400 square feet.
If the length of each side of the square increased by one foot, would its area be a rational number?
Choose each statement that is true about the new dance floor.

A. The area of the floor would be a rational number.

B. The area of the floor would be an irrational number.

C. Each side length would be a perfect square.

D.The area of the floor would be a perfect square.

E.The area of the floor would be a nonterminating, nonrepeating decimal

Answers

Answer:

It’s a: The area of the floor would be a rational number

Step-by-step explanation:

PLS HELP ASAP

Eleri mows grass in her neighborhood. She charges $35 per yard. Eleri offers a discount to repeat customers, where she charges $3 less than the previous time to cut the grass. Suppose Eleri is cutting your grass for the 8th time. Which explicit formula describes how much she will charge you?

Answers

Minus 3 from 35. Do that eight times. Or simply 8x3=24$. 35-24$=11$. 11$ will be charged

Prove the theorems below: Let f:(a,b) → R be continuous. Let ce (a,b) and suppose f is differentiable on (a, c) and (c,b). (i) if f'(x) < 0 for x € (a, c) and f'(x) > 0 for xe (c,b), then f has an absolute minimum at c. (ii) if f'(x) > 0 for x € (a, c) and f'(x) < 0 for xe (c, b), then f has an absolute maximum at c.

Answers

For function f:(a,b) → R (continuous), and c ∈ (a,b), then

(i) If derivative is negative before c and positive after c, then f has an absolute minimum at c.

(ii) If derivative is positive before c and negative after c, then f has an absolute maximum at c.

Part (i) : If derivative of a function f(x) is negative for values of x between a and c, and positive for values of x between c and b, then the function has an absolute minimum at c.

This means that at point c, function reaches its lowest-value compared to all other points in the interval (a, b). The negative derivative before c indicates a decreasing trend, while the positive derivative after c indicates an increasing trend.

The change from decreasing to increasing at c suggests a minimum point. By the continuity of the function, we can conclude that the minimum value is achieved at c.

Part (ii) : Conversely, if  derivative of a function f(x) is positive for values of x between a and c, and negative for values of x between c and b, then the function has an absolute maximum at c.

This means that at point c, the function reaches its highest-value compared to all other points in the interval (a, b). The positive derivative before c indicates an increasing trend, while the negative derivative after c indicates a decreasing trend.

The change from increasing to decreasing at c suggests a maximum point. By the continuity of the function, we can conclude that the maximum value is achieved at c.

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Prove the theorems below: Let f:(a,b) → R be continuous. Let c ∈ (a,b) and suppose f is differentiable on (a, c) and (c, b).

(i) if f'(x) < 0 for x ∈ (a, c) and f'(x) > 0 for x ∈ (c, b), then f has an absolute minimum at c.

(ii) if f'(x) > 0 for x € (a, c) and f'(x) < 0 for x ∈ (c, b), then f has an absolute maximum at c.

Which pair shows equivalent expressions?
2(x+2) = 2x+1
02(x+2) = x+4
02(x+4)=x+2
02(x+4)= 2/x+8

Answers

Answer:

2(x+2) = x+4

Step-by-step explanation:

The pair that shows equivalent expressions is:

2(x+2) = x+4

This is because when we distribute the 2 to the terms inside the parentheses, we get:

2x + 4 = x + 4

By subtracting x from both sides of the equation, we get:

2x - x + 4 = 4

Simplifying further, we have:

x + 4 = 4

Therefore, the expression 2(x+2) is equivalent to x+4.

Hope this helps!

Choose the best term from the box.
The ?
of an object is how heavy the object is.
?
weight
length
capacity
15

Answers

it would be the weight!! hope this helps


What is the simple interest of $1500.00 for 4 months at 6 3/4%
annual interest?
A) $222.22
B)$101.25
C)$50.63
D)$33.75

Answers

The simple interest of $1500.00 for 4 months at 6 3/4% annual interest is $101.25. Thus, the correct answer is B) $101.25.

To calculate simple interest, we use the formula: Interest = Principal x Rate x Time. In this case, the principal (P) is $1500.00, the rate (R) is 6 3/4% (or 0.0675 as a decimal), and the time (T) is 4 months.

First, we need to convert the rate from a percentage to a decimal by dividing it by 100: 6 3/4% = 6.75/100 = 0.0675.

Next, we plug these values into the formula: Interest = $1500.00 x 0.0675 x 4 = $101.25.

Therefore, the simple interest on $1500.00 for 4 months at 6 3/4% annual interest is $101.25. Thus, the correct answer is B) $101.25.

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solve for x. round your answer to the nearest tenth

Answers

Answer:

13.8

Step-by-step explanation:

Hello There!

Basic concept: Geometry

We can solve for x using trigonometric ratios

Here are the Trigonometric Ratios

Remember SOHCAHTOA

Sin = Opposite over Hypotenuse

Cos = Adjacent over Hypotenuse

Tan = Opposite over Adjacent

For the angle that has a measure of 37 degrees

We are given its adjacent side length (11) and we need to find the hypotenuse

Basic concept: Alegbra 1

Adjacent and Hypotenuse corresponds with Cos so we are going to use cosine to create an equation and solve for x

Remember cos = adjacent over hypotenuse

So

[tex]cos37=\frac{11}{x}[/tex]

now we solve for x

what we want to do is get rid of the 11, to do so we divide each side by 11

[tex]\frac{11}{cos37} =x\\cos37=.79863551\\\frac{11}{0.79863551} =13.773749224[/tex]

we're left with x = 13.773749224

finally we want to round to the nearest tenth

The answer would be 13.8

Write an equation in point-slope form of the line that passes through the point(3,5) and has a slope of m=-1

Answers

The answer is y= -1x+8
Step-by-step explanation:
y=mx+b
m= -1
y-y=m(x-x1)
y-5=-1(x-3)
y-5=-1x+3
+5 +5
y=-1x+8

which of the following angles is coterminal with 250°?​

Answers

The angles 60o, -300o, 780o are all coterminal angles. Here is an example, find a positive and negative coterminal angle for 250 degrees. => Then subtract 360 from 260 to get your negative Coterminal angle. Hope this helps! Mark brainly please!

help please!
Prove that,
when the values in a database are equal to each other, then the A.M, G.M and H.M equal to each other
note:
A.M=arithmetic mean
G.M=geometric mean
H.M= harmonic mean​

Answers

Answer:

See below

Step-by-step explanation:

the n number of value of x

[tex] \displaystyle x_{1},x _{2} \dots x_{n}[/tex]

let it be

[tex] \displaystyle x_{1} = x _{2} = x_{3}{\dots }= x_{n} = a[/tex]

now, the A.M of x is

[tex] \rm \displaystyle \: A.M = \frac{ x_{1} + x_{2} + \dots \dots \: + x_{n} }{n} [/tex]

since every value equal to a

substitute:

[tex] \rm \displaystyle \: A.M = \frac{ a + a + \dots \dots \: + a}{n} [/tex]

[tex] \rm \displaystyle \: A.M = \frac{ na}{n} [/tex]

reduce fraction:

[tex] \rm \displaystyle \: A.M = a[/tex]

the G.M of x is

[tex] \rm\displaystyle \: G.M =( x_{1} \times x _{2} {\dots }\times x_{n} {)}^{ {1}^{}/ {n}^{} } [/tex]

since every value equal to a

substitute:

[tex] \rm\displaystyle \: G.M =( a \times a{\dots }\times a{)}^{ {1}^{}/ {n}^{} } [/tex]

recall law of exponent:

[tex] \rm\displaystyle \: G.M =( {a}^{n} {)}^{ {1}^{}/ {n}^{} } [/tex]

recall law of exponent:

[tex] \rm\displaystyle \: G.M = a[/tex]

the H.M of x is

[tex] \displaystyle \: H.M = \frac{n}{ \frac{1}{ x_{1}} + \frac{1}{ x_{2} } {\dots } \: { \dots}\frac{1}{x _{n} } } [/tex]

since every value equal to a

substitute:

[tex] \displaystyle \: H.M = \frac{n}{ \frac{1}{ a} + \frac{1}{ a } {\dots } \: { \dots}\frac{1}{a } } [/tex]

[tex] \displaystyle \: H.M = \frac{n}{ \dfrac{n}{a} } [/tex]

simplify complex fraction:

[tex] \displaystyle \: H.M = n \times \frac{a}{n} [/tex]

[tex] \displaystyle \: H.M = a \: [/tex]

so

[tex] \displaystyle \: A.M = G.M = H.M = a[/tex]

hence,

[tex]\text{Proven}[/tex]

Answer:

What [tex]\colorbox{red}{Nayefx}[/tex]says is I say

write the answer in the simplest radical form
[tex] \sqrt{56} [/tex]

Answers

Hi. Here it is!
I hope this help!

The solids are similar. Find the missing dimension(s).
Will mark brainlest if you give a full explanation 10 min!!!

Answers

Answer:

s = 4.5 cm

l= 3.75 cm

Step-by-step explanation:

Mathematically, when two shapes are similar, the ratio of their corresponding sides are equal

According to this rule, we have it that;

4/6 = 3/s

4 * s = 3 * 6

4s = 18

s = 18/4

s = 4.5 cm

Similarly;

4/5 = 3/l

4 * l = 5 * 3

4l = 15

l = 15/4

l = 3.75 cm

Classify the hypothesis test as left-tailed, right-tailed, or two-tailed. Circle your answer. Below your circle answer, state the null hypothesis, the alternative hypothesis, and label the claim. In the past, the mean running time for a certain type of manufacturer has introduced a change in the production method and wants to perform a hypothesis test to determine whether the mean running time has changed as a result. A) Right-tailed B) Two-tailed C) Left-tailed

Answers

The appropriate classification for the hypothesis test in this scenario is a two-tailed test.

A two-tailed test is used when we are interested in determining whether the mean running time has changed as a result of the introduced change in the production method, without specifying a specific direction of the change. We want to consider the possibility of both an increase and a decrease in the mean running time.

The null hypothesis (H0) for a two-tailed test states that there is no change in the mean running time. In this case, it would be stated as: H0: μ = μ0, where μ represents the population mean running time and μ0 represents the hypothesized mean running time under the previous production method.

The alternative hypothesis (Ha) for a two-tailed test states that there is a change in the mean running time, either an increase or a decrease. In this case, it would be stated as: Ha: μ ≠ μ0, indicating that the mean running time is not equal to the hypothesized mean running time.

The claim being tested is that the mean running time has changed as a result of the introduced change in the production method. This claim is not specific to whether the mean running time has increased or decreased, but rather focuses on the existence of a change.

By classifying the hypothesis test as two-tailed, we are considering the possibility of both an increase and a decrease in the mean running time. This allows for a more comprehensive evaluation of the effects of the introduced change in the production method.

In summary, the hypothesis test is classified as a two-tailed test. The null hypothesis states that there is no change in the mean running time, while the alternative hypothesis states that there is a change, whether it is an increase or a decrease. The claim being tested is that the mean running time has changed as a result of the introduced change in the production method.

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Abir walks four twelfths of a mile to school. Nadia walks two twelfths of a mile to school. How much farther does Abir walk than Nadia?

Answers

Answer:

SHe has walked 2 more miles more than the other person

Step-by-step explanation:

СК - висота трикутника АВС. Знайдіть градусну міру кута А

Answers

Inglis please. Thank you.

Jenny sleeps for 8 hours every day. How many days does she spend over the course

Answers

Answer:

56 Hours A Week... how long is the course though?

Step-by-step explanation:

Use the reflection principle to find the number of paths for a simple random walk from So = 2 to S_15 = 5 that do not hit the line y = 2

Answers

The reflection principle is used to find the number of paths for a simple random walk from a starting point S0 to a destination point S15, without hitting a specific line.

In this scenario, we want to find the number of paths for a random walk from S0 = 2 to S15 = 5, without crossing the line y = 2. We can use the reflection principle to simplify the problem.

The reflection principle states that if a path hits a specific line and goes below it, we can reflect the portion of the path below the line to create a new path above the line. This new path is symmetric to the original path.

In our case, the line y = 2 acts as the reflecting line. We reflect the portion of the paths that hit the line y = 2 above the line. By doing so, we transform the problem into finding the number of paths from S0 = 2 to S15 = 5, without crossing or touching the line y = 2.

Using the principles of combinatorics and counting, we can calculate the number of valid paths without hitting the line y = 2. This involves considering the number of steps taken in the positive and negative y-directions, while ensuring that the path remains above the line y = 2. The specific calculations and details would require a more extensive analysis of the random walk and its possible movements.

By applying the reflection principle and counting the valid paths, we can determine the number of paths for the given scenario.

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Let
T: P2 → P4
be the linear transformation
T(p) = 4x2p.
Find the matrix A for T relative to the bases
B = {1, x, x2}
and
B' = {1, x, x2, x3, x4}.

Answers

The matrix A for the linear transformation T relative to the bases B = {1, x, x2} and B' = {1, x, x2, x3, x4} is:
[4 0 0]  
[0 4 0]
[0 0 4]
[0 0 0]
[0 0 0]

The given linear transformation is T: P2 → P4 and T(p) = 4x2p.

We are to find the matrix A for T relative to the bases B = {1, x, x2} and B' = {1, x, x2, x3, x4}.

Consider the linear transformation of each element of the first basis B.

We have; T(1) = 4x2(1) = 4x2(1) + 0x3 + 0x4 = 4x2T(x) = 4x2(x) = 0x2 + 4x3 + 0x4 = 0x2 + 4x3T(x^2) = 4x2(x^2) = 0x2 + 0x3 + 4x4 = 0x2 + 0x3 + 4x4

Thus, the matrix of T relative to B is: [4 0 0] [0 4 0] [0 0 4]

Next, we will find the coordinates of each element of the basis B' under the basis B.

Using the relations;x3 = x3x^3 = x2.x   [x3]B = [0 0 1]T(x^3) = 4x2(x^3) = 0x2 + 0x3 + 0x4 = 0x2 + 0x3 + 0x4

Thus, the coordinate vector of x3 relative to B is [0 0 1].

Using the relation; x4 = x4 - x3x^4 = x^4 - x2.x   [x4]B = [0 -1 0]T(x^4) = 4x2(x^4) = 0x2 + 0x3 + 4x4 = 0x2 + 0x3 + 4(x3 + x2.x) = 0x2 + 0x3 + 4x3 + 0x2 = 0x2 + 4x3

Thus, the coordinate vector of x4 relative to B is [0 -1 0].

Thus, the matrix of T relative to B' is [4 0 0 0 0] [0 4 0 0 0] [0 0 4 0 0] [0 0 0 0 0] [0 0 0 0 0]

Therefore, the matrix A for T relative to the bases B = {1, x, x2} and B' = {1, x, x2, x3, x4} is: [4 0 0] [0 4 0] [0 0 4] [0 0 0] [0 0 0].

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Select the correct answer.
If f(x) = 2x^2 - 4x - 3° and g(x) = 2x^2 - 16`, find "f(x) + g(x)
OA. 4x^2 - 4x + 13
OB.
* 4x^2 - 4x -13
OC -4x - 19
OD.
*4x^2 - 4x -19

Answers

Answer:

4x^2 - 4x - 19

Step-by-step explanation:

Given the following functions

f(x) = 2x^2 - 4x - 3

g(x) = 2x^2 - 16

f(x)+ g(x) =2x^2 - 4x - 3+ 2x^2 - 16

f(x)+ g(x) = 2x^2+2x^2 -4x - 3 - 16

f(x)+ g(x) =4x^2 - 4x - 19

Hence the required sum is 4x^2 - 4x - 19

Write the number in 2 equivalent forms as a​ fraction, decimal, or percent.
​23%

Answers

Answer:

23%, 23/100, 0.23

Step-by-step explanation:

23%

= 23/100

= 0.23

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