The Mavericks football team was losing when they got
control of the ball at midfield in the last minute of a game.
They lost 17 yards on the first play they ran. Then they
gained 3 yards on the second play. On the third play, the
Mavericks lost 21 yards, and on the fourth play, they lost
8 yards. What was the position of the ball relative to its
starting point after those four plays?
A 33 yd
B -50 yd
C 9 yd
D- 43 yd

Pls help I’m doing a renaissance test

Answer:

._. ;

._. ;

._. ;

Answer:

If I'm correct I think its answer B

Step-by-step explanation:

I'm not sure but i hope this help

Answer:

second option

-∞ < x < 1

Step-by-step explanation:

Answer : i) The probability of finding the first case in 4 trials is 0.1024                        ii) The probability that the team must select more than 6 people before finding one who has a corona virus is 0.4095.

Explanation : Given information:Let p is the probability that he succeeds in finding such a person, is 0.2 and X denote the number of people asked until the first success.

(i) What is the probability that the team must select 4 people until he finds one who has a corona virus?  

The number of trials required until the first success follows geometric distribution.          

The probability of finding the first case in 4 trials is: P(X = 4) = q^3p, where q = 1 - p.                                                                                                                                     We have p = 0.2 and q = 0.8. So, P(X = 4) = 0.8^3 × 0.2 = 0.1024

(ii) What is the probability that the team must select more than 6 people before finding one who who has a corona virus?                                                                                                                                                                        P(X > 6) = 1 - P(X ≤ 6)                                                                                          The probability of finding the first case in the first 6 trials is:P(X ≤ 6) = 1 - q^6p= 1 - 0.8^6 × 0.2= 0.59049P(X > 6) = 1 - P(X ≤ 6)= 1 - 0.59049= 0.4095                                                                                                                Therefore, the probability that the team must select more than 6 people before finding one who has a corona virus is 0.4095.

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Answer:

The solution is the point (3, -1)

Step-by-step explanation:

We have the system of equations:

x = 3

y + 1 = 0

To solve this graphically, we need to graph these two lines and see in which point the lines intersect.

To graph the line x = 3, we need to draw a vertical line that passes through x = 3.

To graph y + 1 = 0

First we should isolate y.

y = -1

This is graphed as a horizontal line that passes through y = -1

The graph of these two lines can be seen in the image below.

Where the green line is x = 3, and the blue line is y = -1

Now, looking at the graph we can see that the lines do intersect in the point (3, -1)

Then the solution of the system is the point (3, -1)

Answer: C. K= 2.5

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Answer:

[tex]\Huge\boxed{k=2.5}[/tex]

Step-by-step explanation:

Given -2.1k + 13 + 6.5k = 24 we need to isolate the variable using inverse operations

step 1 combine any like terms

sometimes there are not like terms but in this case there are. When there are like terms (must be on the same side of the = ) you add them together

-2.1k + 6.5k = 4.4k

now we have

4.4k + 13 = 24

Now we want to get rid of the 13

To do so we subtract 13 from each side

13 - 13 cancels out

24 - 13 = 11

now we have 4.4k=11

now we want to get rid of the 4.4

To do so we divide each side by 4.4

4.4k/4=k

11/4.4=2.5

we're left with k - 2.5

Answer:

1. 36

2. Second

Step-by-step explanation:

- For the first ball, we can see the given function:

[tex]f(x)=-16(t^{2}-3t )[/tex]

[tex]=-16[t^{2} -3t+(3/2)^{2}-(3/2)^{2} ][/tex]

[tex]=-16(t-\frac{3}{2} )^{2} +(-\frac{3}{2} )^{2} *(-16)[/tex]

[tex]-16(t-\frac{3}{2} )^{2} +36[/tex]

So the vertex is ([tex]\frac{3}{2}[/tex], 36), it means when the ball was hit by the [tex]\frac{3}{2}[/tex] seconds, it arrived at the highest height of 36 feet.

- For the second ball, we can see the given graph: the vertex is (2,64), it means when the ball was hit by the 2 seconds, it arrived at the highest height of 64 feet.

- Compare to the two heights, 36 (first ball) is less than 64 (second ball), so the second ball went higher.

The congruent 10 - labeled color spinner isn't attached and could not be found.

However, we could solve the problem hypothetically.

Answer:

Kindly check explanation

Step-by-step explanation:

The events here are independent events :

Probability = required outcome / Total possible outcomes

Total possible outcomes = number of divisions on spinner = 10

Required outcome = number of specified color

Therefore, Probability that first spin lands on yellow :

Number of yellow divisions on spinner / total number of divisions

Let number of yellow divisions = 3

Therefore. Probability that first spin lands in yellow = 3 / 10

Probability that second spin lands on green :

Number of green divisions on spinner / total number of divisions

Let number of green divisions = 2

Therefore. Probability that first spin lands on green = 2 / 10

P(first) * P(second)

3/10 * 2/10 = 3/10 * 1/5 = 3/50

Recall ; this is an hypothetical situation and not the original problem.

The probability that the first spin will land on yellow and the second spin will land on green is; 2/5

The spinner is missing but from online search, it is discovered that from the 10 congruent sections labeled, the colors are as follows;

Yellow - 2 sections

Green - 2 sections

Red - 3 sections

Blue - 3 sections

Thus, probability of getting yellow on first spin is;

P(yellow on first spin) = 2/10

Probability of getting green on second spin is;

P(green on second spin) = 2/10

Thus, probability that the first spin will land on yellow and the second spin will land on green is;

P(1st on yellow and 2nd on green) = 2/10 + 2/10

P(1st on yellow and 2nd on green) = 2/5

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The events A and B are not independent. The occurrence of event B affects the probability of event A.

To determine whether events A and B are independent,

we need to check if the probability of event A occurring is affected by the occurrence of event B, and vice versa.

Probability of event A: Since we are flipping two coins,

the probability of getting heads on each flip is 1/2.

Therefore, the probability of getting two consecutive heads is

[tex](1/2) \times (1/2) = 1/4[/tex]

Probability of event B: The first or last flip yielding tails means there are two possibilities:

either the first flip is tails and the second flip is any outcome,

or the first flip is any outcome and the second flip is tails.

Each of these individual possibilities has a probability of

[tex](1/2) \times (1/2) = 1/4[/tex]

Hence, theprobability of event B is 1/4 + 1/4 = 1/2.

Since the probability of event A is 1/4 and the probability of event B is 1/2, and 1/4 ≠ 1/2,

we can conclude that events A and B are not independent.

The occurrence of event B (first or last flip yielding tails) affects the probability of event A (two consecutive flips yielding heads).

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Answer:

.........

it is -7

Answer:

Fr. It’s annoying. My mom yells at me for not passing lolz.

Step-by-step explanation:

Answer:

Ignore them and re-upload the questions. The links are very bad.

Step-by-step explanation:

Required correct option is Since the two confidence intervals overlap, neither gender appears to be substantially more successful in their challenges.

a) In order to find the 99% confidence interval for the percentage of successful challenges, the formula is given below: Lower limit of CI: upper limit of CI: The confidence interval for the percentage of successful challenges is (19.68%, 34.97%).b) In part (a), we found the confidence interval for the percentage of successful challenges among women playing singles matches. 99% confidence interval for the percentage of successful challenges made by the men playing singles matches is 21.7%± 4.93%.Here, the two confidence intervals overlap, therefore, neither gender appears to be substantially more successful in their challenges.Therefore, option (C) is the correct answer.

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The probability that none of the 5 randomly selected individuals are part of a couple is 0.016.

A probability means the branch of math which deals with finding out the likelihood of the occurrence of an event. Its measures the chance of an event happening.

We will know total number of possible outcomes when selecting 5 individuals from a group of 20. This can be calculated using the combination formula:

C(20, 5) = 20! / (5! * (20 - 5)!)

C(20, 5) = 15,504

We know that when we select an individual, we are removing their corresponding partner from the pool of available choices. This means that for each individual we choose, the number of available choices decreases by 1.

The number of favorable outcomes can be calculated as follows:

= 20 * 18 * 16 * 14 * 12

= 967,680

The probability will be:

= Outcomes / Favorable outcomes

= 15,504 / 967,680

= 0.01602182539

= 0.016.

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Answer:

From greatest to least it would be 3.66666,[tex]\sqrt{11}[/tex],2(1/4),-2.5,-3.97621

Step-by-step explanation:

Just type in a calc

Answer:

[tex]\sqrt{11}=3.31[/tex], -2.5, [tex]2\frac{1}{2}= 2.25[/tex], 3.6, -3.97621...

Step-by-step explanation:

Greatest to least would be:

3.6,  [tex]\sqrt{11}[/tex], [tex]2\frac{1}{4}[/tex], -2.5, -3.97621...

Least to greatest would be:

-3.97621, -2.5, [tex]2\frac{1}{4}[/tex], [tex]\sqrt{11}[/tex], 3.6

Hopefully, that helps.

The solution to the given initial value problem [tex]cos2x sin x dy + (cos?x)y = 5, 7(7/3) = 4 dx[/tex]  is [tex]y(x) = (5/6) * (cos^2(x) - 1) + (28/9) * sin(x) + (40/9) * cos(x)[/tex].

To solve the initial value problem, we can use the method of integrating factors. The integrating factor is found by taking the exponential of the integral of the coefficient of y with respect to x. In this case, the coefficient is cos(x). So, the integrating factor is [tex]e^(^\int ^{ cos(x)} \, ^d^x^) = e^s^i^n^(^x^))[/tex].

Multiplying the given differential equation by the integrating factor, we obtain:

[tex]e^{sin(x)} * [cos^{2x} sin(x) dy + cos(x) y] = 5e^{sin(x)} dx[/tex]

By using the product rule and simplifying, we have:

[tex]d/dx [e^{sin(x)} * y * cos^{2x}] = 5e^{sin(x)}[/tex]

Integrating both sides with respect to x, we get:

[tex]e^{sin(x)} * y * cos^{2(x)} = \int {5e^{sin(x)}} \, dx = 5e^{sin(x)} + C,[/tex]

where C is the constant of integration.

Simplifying and solving for y, we obtain:

[tex]y(x) = [(5/6) * (cos^{2x} - 1) + (28/9) * sin(x) + (40/9) * cos(x)] / (e^{sin(x)} * cos^{2(x)} + Ce^{-sin(x)},[/tex]

where C is the constant of integration.

To find the value of C, we can use the initial condition y(7/3) = 4. Substituting this into the equation and solving for C, we can determine the specific solution.

In conclusion, the solution to the given initial value problem is [tex]y(x) = (5/6) * (cos^{2x} - 1) + (28/9) * sin(x) + (40/9) * cos(x)[/tex], subject to the specified initial condition.

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Knowing the roots first write the equation in factored form:

(X - 3/4)(x +5) = 0

Now use the FOIL method ( multiply each term in one set of parentheses by each term the other set:

X•x + x•5 -3/4•x -3/4•5

Simplify:

X^2 + 5x -3/4x -3 3/4

Combine like terms:

X^2+ 4 1/4x - 3 3/4

The value of K is given as follows:

K = 1/12.

A probability is calculated as the division of the number of desired outcomes by the number of total outcomes.

For a distribution, we have that the sum of all the probabilities in the distribution must be of 1.

This means that the cumulative distribution at the least value is of 1, hence the equation is given as follows:

17/12 - 5K = 1

Then the value of K is obtained as follows:

5K = 17/12 - 1

5K = 17/12 - 12/12

5K = 5/12

K = 1/12.

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6πa² is the flux of F across the upper hemisphere.

The problem requires us to compute the flux of the given vector field F across the upper hemisphere x² + y² + z² = a², z ≥ 0. We are to orient the hemisphere with an upward-pointing normal. The four vector fields are:

F = yj

F = yi - xj

F = -yi + xj - kz

F = x²i + xyj + xzk

To begin with, we'll make use of the Divergence Theorem, which states that the flux of a vector field F across a closed surface S is equivalent to the volume integral of the divergence of the vector field over the region enclosed by the surface, V, that is:

F · n dS = ∭V (div F) dV

where n is the outward pointing normal unit vector at each point of the surface S, and div F is the divergence of F.

We'll need to write the vector fields in terms of i, j, and k before we can compute their divergence. Let's start with the first vector field:

F = yj

We can rewrite this as:

F = 0i + yj + 0k

Then, we compute the divergence of F:

div F = d/dx (0) + d/dy (y) + d/dz (0)

= 0 + 0 + 0 = 0

So, the flux of F across the upper hemisphere is 0. Now, let's move onto the second vector field:

F = yi - xj

We can rewrite this as:

F = xi + (-xj) + 0k

Then, we compute the divergence of F:

div F = d/dx (x) + d/dy (-x) + d/dz (0)

= 1 - 1 + 0 = 0

So, the flux of F across the upper hemisphere is 0. Let's move onto the third vector field:

F = -yi + xj - kz

We can rewrite this as:

F = xi + y(-1j) + (-1)k

Then, we compute the divergence of F:

div F = d/dx (x) + d/dy (y(-1)) + d/dz (-1)

= 1 - 1 + 0 = 0

So, the flux of F across the upper hemisphere is 0. Lastly, let's consider the fourth vector field:

F = x²i + xyj + xzk

We can compute the divergence of F directly:

div F = d/dx (x²) + d/dy (xy) + d/dz (xz)

= 2x + x + 0 = 3x

Then, we express the surface as a function of spherical coordinates:

r = a, 0 ≤ θ ≤ 2π, 0 ≤ φ ≤ π/2

Note that the upper hemisphere corresponds to 0 ≤ φ ≤ π/2.

We can compute the flux of F over the hemisphere by computing the volume integral of the divergence of F over the region V that is enclosed by the surface:

r² sin φ dr dφ dθ

= ∫[0,2π] ∫[0,π/2] ∫[0,a] 3r cos φ dr dφ dθ

= ∫[0,2π] ∫[0,π/2] (3a²/2) sin φ dφ dθ

= (3a²/2) ∫[0,2π] ∫[0,π/2] sin φ dφ dθ

= (3a²/2) [2π] [2] = 6πa²

Therefore, the flux of F across the upper hemisphere is 6πa².

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Answer:

first add the numbers that have the same variable s x7+8x=15x

then the numbers first add and then you subtract

1+7=8

3-8= -5

15x-5

Answer:

8x+x7+9

Step-by-step explanation:

subtracted one term from another

subtracted 1 from 3 to get 2

x7=+8x+2+7

add two terms together

add 2 and 7 toget 9

x7+8x+9

Answer: c

Step-by-step explanation:

Answer:

7.07106781187

Step-by-step explanation:

Let us use the  distance formula:

[tex]d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}[/tex]

x2=2

x1=7

y2=4

y1=9

[tex]d = \sqrt{(2 - 7)^{2} + (4-9)^2}[/tex]

[tex]d = \sqrt{(-5)^2 + (-5)^2}[/tex]

[tex]d = \sqrt{25 + 25}[/tex]

[tex]d = \sqrt{50}[/tex]

d=7.07106781187 (round to whatever digit neccesary)

Hope this helps!!

a. The volume of the solid is 24 cubic units.

b. The volume of the solid is 4π cubic units.

a. Volume = Area of Base * Height

The base is a right triangle with base length of 3 units and height of 4 units. The area of the base can be calculated as:

Area of Base = (1/2) * base * height

= (1/2) * 3 * 4

= 6 square units

The height of the solid is 4 units.

Volume = Area of Base * Height

= 6 * 4

= 24 cubic units

b) Any cross section of the solid, taken parallel to the y-axis and perpendicular to the x-axis, is a semicircle.

Volume = (1/2) * π * radius² × height

Volume = (1/2) * (1/2) * π * 2² * 4

= (1/4) * π * 4 * 4

= π * 4

Therefore, the volume of the solid is 4π cubic units.

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The calculated t-value is greater than 1.734, we reject the null hypothesis; otherwise, we fail to reject the null hypothesis.

An engine additive is being tested to see whether it can effectively increase gas mileage for a number of vehicles. Twenty assorted vehicles had their gas mileage, in miles per gallon, measured. Then, the engine additive was placed into each of the engines, and the gas mileage was measured again. Let µd be the true mean difference in the gas mileage before and after the engine additive is placed into the engines. We want to test the hypothesis that the engine additive has no effect. The null hypothesis is: H0: µd = 0The alternative hypothesis is: Ha: µd > 0 (one-tailed test)Assuming that the difference in gas mileage before and after the engine additive is approximately normally distributed, we can use a one-sample t-test. The test statistic is given by: $$t=\frac{\bar{x}-\mu}{s/\sqrt{n}}$$Where, $\bar{x}$ is the sample mean difference in gas mileage, μ is the hypothesized population mean difference, s is the sample standard deviation of the differences, and n is the sample size. We can use a significance level of α = 0.05.To determine the critical value of the t-distribution, we need to find the degrees of freedom (df). Since we have a sample size of n = 20, we have n - 1 = 19 degrees of freedom. Using a t-distribution table with 19 degrees of freedom and a significance level of 0.05 for a one-tailed test, we get a critical value of t = 1.734. If the calculated t-value is greater than 1.734, we reject the null hypothesis; otherwise, we fail to reject the null hypothesis.

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The given information allows us to find the values of trigonometric ratios involving angle θ. Given that tan θ = -7/24 and cos θ > 0, we can determine the following trigonometric ratios: sin θ, csc θ, sec θ, and cot θ

We are given that tan θ = -7/24. Using this information, we can determine the values of sin θ and csc θ.

Since tan θ = sin θ / cos θ, we can write -7/24 = sin θ / cos θ. Rearranging the equation, sin θ = -7 and cos θ = 24.

Now, we can find the values of csc θ, sec θ, and cot θ.

csc θ is the reciprocal of sin θ, so csc θ = 1 / sin θ = 1 / (-7) = -1/7.

To find sec θ, we use the fact that sec θ = 1 / cos θ. So, sec θ = 1 / (24) = 1/24.

Lastly, to calculate cot θ, we know that cot θ = 1 / tan θ. Thus, cot θ = 1 / (-7/24) = -24/7.

In summary, given tan θ = -7/24 and cos θ > 0, we have sin θ = -7, csc θ = -1/7, sec θ = 1/24, and cot θ = -24/7.

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The intersection of N(x) and N'(x), denoted by N(x)∩N'(x), is an open neighborhood of x. Since N(x)∩N'(x) ⊆ N(x) ⊆ U and N(x)∩N'(x) ⊆ N'(x) ⊆ X\U, we can conclude that N(x)∩N'(x) ⊆ UA.

Since N(x)∩A is a non-empty set contained in A\U, we have shown that every point in (A\U)' has a neighborhood contained in A\U. Therefore, (A\U)' is open in X, which implies that A\U is closed in X.

To show that if U is open in X and A is closed in X, then UA is open in X and A\U is closed in X, we need to prove two statements:

Let's prove these statements one by one:

Let x be an arbitrary point in UA. Since x is in UA, it must belong to U as well as A. Since U is open in X, there exists an open neighborhood N(x) of x that is completely contained within U. Now, since x is in A, it is also in X\U (complement of U in X). As A is closed in X, X\U is closed in X, which means its complement, U, is open in X. Therefore, there exists an open neighborhood N'(x) of x that is completely contained within X\U.

Now, consider the intersection of N(x) and N'(x), denoted by N(x)∩N'(x). This intersection is an open neighborhood of x. Since N(x)∩N'(x) ⊆ N(x) ⊆ U and N(x)∩N'(x) ⊆ N'(x) ⊆ X\U, we can conclude that N(x)∩N'(x) ⊆ UA.

Since N(x)∩N'(x) is an open neighborhood of x completely contained within UA, we have shown that UA is open in X.

Let x be an arbitrary point in (A\U)'. Since x is not in A\U, it means that x must either be in A or in U (or both). If x is in A, then x is not in A\U. Therefore, x is in U.

Since x is in U and U is open in X, there exists an open neighborhood N(x) of x that is completely contained within U. Now, consider the intersection of N(x) and A. Since x is in A, N(x)∩A is a non-empty set. Let y be any point in N(x)∩A.

We know that N(x)∩A ⊆ U∩A ⊆ A\U, because if y was in U, it would contradict the assumption that y is in A. Therefore, N(x)∩A is a subset of A\U.

Since N(x)∩A is a non-empty set contained in A\U, we have shown that every point in (A\U)' has a neighborhood contained in A\U. Therefore, (A\U)' is open in X, which implies that A\U is closed in X.

Hence, we have shown that if U is open in X and A is closed in X, then UA is open in X, and A\U is closed in X.

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Answer:

What I think it might be is 62.3

(i)  When using three classifiers with a majority decision, the probability of correctly classifying the new object is 0.973.

(ii) The probability of correct classification increases as the number of classifiers increases

(i) All three classifiers make the correct classification: p * p * p = 0.7 * 0.7 * 0.7 = 0.343.

Two classifiers make the correct classification and one classifier makes an error:

(p * p * q) + (p * q * p) + (q * p * p) = 3 * (0.7 * 0.7 * 0.3) = 0.441.

One classifier makes the correct classification and two classifiers make errors:

(p * q * q) + (q * p * q) + (q * q * p) = 3 * (0.7 * 0.3 * 0.3)

= 0.189.

The probability of the new object being correctly classified is the sum of these probabilities:

0.343 + 0.441 + 0.189

= 0.973.

(ii)  The probability of correct classification increases as the number of classifiers increases. This is because the probability of a majority decision being correct is the probability that at least two of the classifiers make the correct decision. The more classifiers there are, the more likely it is that at least two of them will make the correct decision.

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Answer:

HEHEHEHEHEH

I've been waiting for this moment

Feels good to be alive right about now

Good, good, good, good to be alive right about now

Good, good, good, good to be alive right about now

Hallelujah, let that bass line move ya, say hey

Step-by-step explanation:

Have fun