The price of entrées at fast food restaurants in the area have an unknown distribution with a mean price of $6.75 and a standard deviation of $1.08. If you randomly select 45 combo meals around town, what is the probability that their average price will be less than $6.50?

Answer:

the height is 14m

Step-by-step explanation:

[tex]h=2*\frac{A}{a+b} =2 *\frac{126}{8+10} =14[/tex]

30 students needs to be added for the food to be enough for 75 days

A hostel contains 150 students

They have food that will last them for 90 days

If the food is supposed to last for 75 days, the number of students that will be added can be calculated as follows

150= 90

1= x

cross multiply

x= 150×90

x= 13,500

= 13500/75

= 180

180 students will be fed for 75 days

We initially had 150 students, subtract 150 from 180

180-150

= 30

Hence 30 students needs to be added so the food lasts for 75 days

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The most likely true statement is that the median is greater than the mean because the data is skewed to the left.

Based on the information provided, Indira makes a box-and-whisker plot of her data and finds that the distance from the minimum value to the first quartile is greater than the distance between the third quartile and the maximum value. Which is most likely true? The answer is: the median is greater than the mean because the data is skewed to the left.

Here's a step-by-step explanation,

1. The distance from the minimum value to the first quartile being greater than the distance between the third quartile and the maximum value indicates that there is more data spread out on the left side of the plot.

2. This spread causes the data to be skewed to the left.

3. When data is skewed to the left, the median (Q2) is typically greater than the mean (average), as the mean gets pulled towards the longer tail on the left side.

So, the most likely true statement is that the median is greater than the mean because the data is skewed to the left.

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Therefore, the standard deviation of the data set is approximately 4.14.

The standard deviation is calculated by taking the square root of the variance, which is the sum of the squared deviations divided by the sample size minus 1.

So, first we need to calculate the variance:

variance = sum of squared deviations / (sample size - 1)

variance = 103 / (7 - 1)

variance = 17.17

Now we can find the standard deviation:

standard deviation = √(variance)

standard deviation = √(17.17)

standard deviation = 4.14 (rounded to two decimal places)

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The value of the definite integral ∫(4 - 4√(16 - x^2)) dx, as determined by the area under the graph of the integral from x = -4 to x = 4, is 8π.

To evaluate the definite integral ∫(4 - 4√(16 - x^2)) dx:

We will first graph the integrand and then find the area under the curve.

Step 1: Graph the integrand
The integrand function is f(x) = 4 - 4√(16 - x^2).

This represents a semicircle with a radius of 4 and centered at the origin (0, 4).

The function is transformed from the standard semicircle equation by subtracting 4 from the square root term.

Step 2: Determine the limits of integration
The given integral is a definite integral with limits -4 to 4.

This means that we will find the area under the curve of the function f(x) from x = -4 to x = 4.

Step 3: Calculate the area under the curve
Since the function represents a semicircle, we can find the area of the whole circle and then divide by 2.

The area of a circle is given by A = πr^2, where r is the radius. In our case, r = 4.

A = π(4^2) = 16π

Now, we'll divide the area by 2 to get the area of the semicircle.

Area of semicircle = (1/2) * 16π = 8π

Step 4: Determine the value of the definite integral
The value of the definite integral ∫(4 - 4√(16 - x^2)) dx, as determined by the area under the graph of the integral from x = -4 to x = 4, is 8π.

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Answer:

14.1mm² (to 1 d.p)

Step-by-step explanation:

area of a circle = πr²

so therefore the area of a semicircle is πr²/2 (because a semicircle is half of a circle)

radius = 3mm

area = π×3²/2

=9/2π

=14.13716....

=14.1mm² (to 1 d.p)

The first and second representation shows y as a function of x.

Explain function

An equation in mathematics is a statement that shows the equality between two expressions. It comprises one or more variables and can be solved to determine the value(s) of the variable(s) that satisfy the equation. Equations are widely used to represent relationships between quantities and solve problems in many fields, such as physics, engineering, and finance.

According to the given information

The first and second representation shows y as a function of x.

In the table and graph, for each value of x, there is only one corresponding value of y. This means that there is a well-defined rule that maps each x-value to a unique y-value, which is the definition of a function. Therefore, y is a function of x in this representation.

The other two representations are not functions of x.

In the equation x² + y² = 144, for each value of x, there are two possible values of y that satisfy the equation (one positive and one negative). Therefore, y is not a function of x in this representation.

In the set {(0, 4), (1, 6), (2, 8), (0, 9)}, there are two points with x-coordinate 0, which means that there are multiple y-values associated with the same x-value. Therefore, this set does not represent y as a function of x

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Answer: m∠V = 28°

Step-by-step explanation:

     We know that a triangle's angles add up to 180. We will create an equation to solve for x. Then, we will substitute it back into the expression for angle V and simplify.

Given:

(9x - 8) + (2x + 2) + (3x + 4) = 180°

Simplify:

9x - 8 + 2x + 2 + 3x + 4 = 180°

Reorder:

9x + 2x + 3x - 8 + 2 + 4 = 180°

Combine like terms:

14x - 2 = 180°

Add 2 to both sides of the equation:

14x = 182°

Divide both sides of the equation by 13:

x = 13

---

m∠V = 2x + 2

m∠V = 2(13) + 2

m∠V = 28°

The different combinations of fudge that Silas can purchase are:

8 pounds of peanut butter fudge and 0 pounds of chocolate fudge

6 pounds of peanut butter fudge and 4 pounds of chocolate fudge

4 pounds of peanut butter fudge and 8 pounds of chocolate fudge

2 pounds of peanut butter fudge and 12 pounds of chocolate fudge

0 pounds of peanut butter fudge and 16 pounds of chocolate fudge

Chocolate (x)  Peanut Butter (y)         Cost

0                              8                                  $24

4                              6                                  $24

8                              4                                  $24

12                              2                                  $24

16                               0                                  $24

We can see that there are five different combinations of fudge that Silas can purchase if he only buys whole pounds of fudge:

8 pounds of peanut butter fudge and 0 pounds of chocolate fudge

6 pounds of peanut butter fudge and 4 pounds of chocolate fudge

4 pounds of peanut butter fudge and 8 pounds of chocolate fudge

2 pounds of peanut butter fudge and 12 pounds of chocolate fudge

0 pounds of peanut butter fudge and 16 pounds of chocolate fudge

We can also verify that the cost of each combination is $24.

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If a cylindrical can of cocoa has the dimensions radius of 4 in , height of 3 in then the area of label is 75.36 square inches

We have a cylindrical can of cocoa.

The radius of the can R = 4 in

The height of the can H = 3 in

We know the formula for finding the lateral surface area of the cylinder is given by:

A = 2πRH

A = 2π×4×3

A = 24π

A=24×3.14

A=75.36 square inches

Hence, the approximate area available for the label is 75.36 square inches

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$400 will yield an interest of $78 in 1/2 years at the rate of 39%  per annum. We can use the formula for simple interest to calculate the rate.

Simple interest is calculated based on the initial amount (principal) and time period, without considering any additional interest on the accumulated interest.

Using the formula for simple interest:

Given:

Principal amount (P) = $400

Simple interest (I) = $78

Time (T) = 1/2 years

To calculate the rate (R):

Simple Interest (I) = (Principal amount (P) × Rate (R) × Time (T)) / 100

Plugging in the given values:

$78 = ($400 × R × 1/2) / 100

Multiplying both sides by 100 to get rid of the fraction:

$78 * 100 = $400 * R * 1/2

7800 = $200 * R

Dividing both sides by $200 to isolate R:

R = 7800 / 200

R = 39

Thus, the rate of interest per annum is 39%.

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If your opponent goes first, you are guaranteed to win with 8 gems if

your opponent takes 1, 2, or 3 gems on their first turn.

In general, if there are n gems, you can guarantee a win if your opponent

takes n/2 or fewer gems on their first turn when you go second.

Let's consider the starting configuration of gems with 8 gems total.

If you go first, the maximum number of gems you can take on your first

turn is 4 (either 4 diamonds or 4 rubies or 2 of each).

If you take 4 diamonds, your opponent can take all 4 rubies, leaving you

with no choice but to take the remaining 4 diamonds on your next turn,

which means your opponent will take the last 4 rubies and win. Similarly,

if you take 4 rubies on your first turn, your opponent can take all 4

diamonds and win.

If you take 2 diamonds and 2 rubies on your first turn, your opponent can

mirror your move and take 2 diamonds and 2 rubies, leaving you with 2

diamonds and 2 rubies left. At this point, no matter what you do, your

opponent can take the remaining gems and win.

So, if you go first, there is no way to guarantee a win with 8 gems.

Now let's consider the case where your opponent goes first. If your

opponent takes 1, 2, or 3 gems on their first turn, you can mirror their

move and take the same number of gems, leaving 4, 5, or 6 gems left

respectively.

At this point, no matter what your opponent does, you can take enough

gems to ensure that you take the last gem and win. For example, if there

are 4 gems left, you can take 2 diamonds (or 2 rubies) to leave 2 gems,

and then take the remaining 2 gems on your next turn. Similarly, if there

are 5 gems left, you can take 1 diamond and 1 ruby to leave 3 gems, and

then take the remaining 3 gems on your next turn. And if there are 6

gems left, you can take 2 diamonds and 2 rubies to leave 2 gems, and

then take the remaining 2 gems on your next turn.

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a. 150 families in the sample earned less than $45,000.

b. We can nοt determine hοw many families earned mοre than $ 55,000 exactly.

The term “incοme” generally refers tο the amοunt οf mοney, prοperty, and οther transfers οf value received οver a set periοd οf time in exchange fοr services οr prοducts.

Here, we have

Given:

Suppοsed yοu study family incοme in a randοm sample οf 300 families. Yοu find that the mean family incοme is $55,000; the median is $45,000; and the highest and lοwest incοmes are $250,000 and $2400, respectively.

a. 150 families in the sample earned less than $45,000 because the median is the middle value in the οrdered data.

Median = 45,000/300

=  150

b. We can nοt determine hοw many families earned mοre than $ 55,000 exactly. It will be less than half. Because $55,000 is the mean value, it is nοt based οn the οrder.

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Answer:

4

Step-by-step explanation:

The correct answer is: A s is a function of r as the thickness of the paper currency depends on its denomination.

Based on the given information, s is a function of r.

The thickness (s) of any piece of U.S. paper currency is determined by its denomination (r). This means that for a given denomination (r), there is a specific thickness (s) associated with it. However, the reverse may not be true as different denominations of U.S. paper currency can have the same thickness. For example, a $1 bill and a $100 bill may have the same thickness, but they have different denominations.

Therefore, s is a function of r as the thickness of the paper currency depends on its denomination.

Therefore, the correct answer is: A. s is a function of r.

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By Limit comparison test the series ∞∑n=11n√n²+5 converges.

To use the limit comparison test, we need to find a series whose convergence or divergence is known and that is similar to the given series.

Let's consider the series ∞∑n=11n√n²+5 and choose a series that we know converges, such as ∞∑n=1 1/n².

We can now take the limit as n approaches infinity of the ratio of the nth term of the given series to the nth term of the chosen series:

limₙ→∞ (n√(n²+5))/(1/n²)

Simplifying the expression inside the limit, we get:

limₙ→∞ (n√(n²+5))/(1/n²) = lim(n→∞) n³√(1+5/n²)/1 = lim(n→∞) n³/√(n⁶+5n⁴)

Using L'Hopital's rule, we can take the derivative of the numerator and denominator separately with respect to n to get:

limₙ→∞n³/√(n⁶+5n⁴) = lim(n→∞) 3n²/3n⁵/²= lim(n→∞) 3n¹/²)/3n⁵/²) = 0

Since the limit is finite and nonzero, the given series and the chosen series have the same convergence behavior. Therefore, since we know that ∞∑n=1 1/n² converges (by the p-series test with p=2),

we can conclude that the given series ∞∑n=11n√n²+5 also converges.

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the length of the repel line needed is approximately 44 feet (rounded to the nearest whole number).

what is length ?

Length is a physical dimension that describes the extent of an object or distance between two points. In geometry, length refers to the distance between two points, and it is usually measured in units of length such as meters, centimeters, feet, inches,

In the given question,

(a) The correct trigonometric ratio to use in this problem is the sine ratio, which relates the opposite side to the hypotenuse in a right triangle. In this case, we are given the angle A and we want to find the length of the opposite side, which is the distance from the top of the ravine to Lucy. Therefore, we can use the sine ratio as follows:

sin(A) = opposite/hypotenuse

(b) We can set up the equation using the given information as follows:

sin(17°) = opposite/150

where opposite is the length of the repel line that we want to find.

(c) To solve for the length of the repel line, we can rearrange the equation as follows:

opposite = sin(17°) x 150

opposite = 0.2924 x 150

opposite ≈ 44

Therefore, the length of the repel line needed is approximately 44 feet (rounded to the nearest whole number).

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t2 as a linear combination of the In P2 can be written as:                                 t^2 = (-1/7)(1 - 5t) - (4/7)(-2 + t + t^2). The change-of-coordinates matrix from B to S is: [ -1/35 2/7 -1/7 ]

                        [ -1/35 1/7 -4/7 ]

                          [ -1/35 0 0 ]

Let P1(t) = 1 - 5t and P2(t) = -2 + t + t^2 be the basis polynomials for B.

To write t^2 as a linear combination of P1(t) and P2(t), we need to find constants a and b such that:

t^2 = a P1(t) + b P2(t)

Substituting in the expressions for P1(t) and P2(t), we get:

t^2 = a(1 - 5t) + b(-2 + t + t^2)

Rearranging terms, we get:

t^2 = (b - 5a) t^2 + (t + 5a - 2b)

Equating coefficients of t^2 and t on both sides, we get:

b - 5a = 1

5a - 2b = -2

Solving for a and b, we get:

a = -1/7

b = -4/7

Therefore, we can write t^2 as:

t^2 = (-1/7)(1 - 5t) - (4/7)(-2 + t + t^2)

To find the change-of-coordinates matrix from the basis B to the standard basis S = {1, t, t^2}, we need to express each basis vector of S as a linear combination of the basis polynomials in B.

We have:

1 = -1/35 (9 P1(t) - 20 P2(t))

t = 2/7 P1(t) + 1/7 P2(t)

t^2 = -1/7 P1(t) - 4/7 P2(t)

Therefore, the change-of-coordinates matrix from B to S is:

[ -1/35 2/7 -1/7 ]

[ -1/35 1/7 -4/7 ]

[ -1/35 0 0 ]

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Each subfield of Z, which is the set of integers, contains the field of rational numbers (Q).

To show that each subfield of Z contains Q, we can start by understanding what a subfield is. A subfield of a field is a subset that is also a field, meaning it must satisfy certain properties such as closure under addition, subtraction, multiplication, and division (except for division by zero), among others.

In this case, Z is the set of integers, which includes positive integers, negative integers, and zero. Q, on the other hand, is the set of rational numbers, which includes all numbers that can be expressed as the quotient of two integers, where the denominator is not zero.

Now, let's consider any subfield of Z. Since it is a field, it must contain the integers, including positive integers, negative integers, and zero. Since all integers are rational numbers (they can be expressed as the quotient of themselves divided by 1), any subfield of Z must contain all integers, and therefore it must also contain Q, which is the set of rational numbers.

Therefore, we can conclude that each subfield of Z contains Q, as Q is a subset of Z and is also a field, satisfying the properties of closure under addition, subtraction, multiplication, and division (except for division by zero).

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The expanded form of equations, 3.1 is A11b1 + A12b2 + A13b3 + f1 = 0, A21b1 + A22b2 + A23b3 + f2 = 0, A31b1 + A32b2 + A33b3 + f3 = 0, 3.2 is A11, A12, A13, A21, A22, A23, A31, A32, and A33 and 3.3 is A11δ11 + A22δ22 + A33δ33 = B11m + B22m + B33m, where δ is the Kronecker delta function.

In mathematics and science, equations are frequently expressed in a compact form to represent complicated systems or connections. However, to comprehend their separate components or solve them numerically, these equations must frequently be expanded. To extend the equations and describe them more thoroughly, we substituted the variables i, j, and k with their corresponding values 1, 2, and 3.

We have enlarged the matrix equation Aijbj + fi = 0 in equation 3.1 to reflect three different equations, each corresponding to a row in the matrix. This allows us to separately solve the variables in each row and derive a solution for the full matrix.

We enlarged the equation Aikk = Bij + Ckkδij = Bimm in equation 3.3 to represent three independent equations, each corresponding to a diagonal element in the matrix. Here, δij is the Kronecker delta, which allows us to distinguish between diagonal and off-diagonal components. This is frequently beneficial in solving matrices-based problems since diagonal elements have specific features and can be solved more readily than off-diagonal elements.

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(a) The joint probability mass function of X and Y is:

P(X=3,Y=3) = 1/16; P(X=2,Y=3) = 1/16; P(X=2,Y=2) = 2/16; P(X=2,Y=1) = 1/16

(b) The marginal probability mass functions of X and Y are:

P(X=0) = 6/16, P(X=1) = 5/16, P(X=2) = 4/16, P(X=3) = 1/16

(c) X and Y are not independent.

(d) E(X) = 1.25; Var(X) = 0.9375; E(Y) = 1.25; Var(Y) = 0.9375

(e) P(X=0 | Y=1) = 0.2

(a) To find the joint probability mass function of X and Y, we need to consider all possible outcomes of the first four coin tosses and calculate the probability of each combination of values for X and Y. Let H denote heads and T denote tails. Then the possible outcomes of the first four tosses and their corresponding values of X and Y are:

HHHT: X = 3, Y = 3

HHTH: X = 2, Y = 3

HTHH: X = 2, Y = 2

THHH: X = 2, Y = 1

HHTT: X = 2, Y = 2

HTHT: X = 1, Y = 3

HTTH: X = 1, Y = 2

THHT: X = 1, Y = 1

TTHH: X = 1, Y = 0

HTTT: X = 1, Y = 1

THTH: X = 0, Y = 3

TTHT: X = 0, Y = 2

TTTH: X = 0, Y = 1

TTTT: X = 0, Y = 0

The probability of each outcome can be calculated as (1/2)⁴ = 1/16, since each toss is equally likely to be heads or tails. Therefore, the joint probability mass function of X and Y is:

P(X=3,Y=3) = 1/16

P(X=2,Y=3) = 1/16

P(X=2,Y=2) = 2/16

P(X=2,Y=1) = 1/16

P(X=1,Y=3) = 1/16

P(X=1,Y=2) = 2/16

P(X=1,Y=1) = 1/16

P(X=1,Y=0) = 1/16

P(X=0,Y=3) = 1/16

P(X=0,Y=2) = 1/16

P(X=0,Y=1) = 2/16

P(X=0,Y=0) = 1/16

(b) The marginal probability mass functions of X and Y are:

P(X=x) = ∑y P(X=x, Y=y) for x = 0,1,2,3

P(Y=y) = ∑x P(X=x, Y=y) for y = 0,1,2,3

Using the joint probability mass function from part (a), we get:

P(X=0) = 6/16, P(X=1) = 5/16, P(X=2) = 4/16, P(X=3) = 1/16

P(Y=0) = 6/16, P(Y=1) = 5/16, P(Y=2) = 4/16, P(Y=3) = 1/16

(c) To check if X and Y are independent, we need to compare the joint probability mass function from part (a) to the product of the marginal probability mass functions:

P(X=x, Y=y) ≠ P(X=x) * P(Y=y) for some values of x and y

For example, we have:

P(X=2, Y=2) = 2/16 ≠ (4/16) * (4/16) = P(X=2) * P(Y=2)

Therefore, X and Y are not independent.

(d) The expected value of X is:

E(X) = ∑x x * P(X=x) = 0*(6/16) + 1*(5/16) + 2*(4/16) + 3*(1/16) = 1.25

The variance of X is:

Var(X) = [tex]E(X^2) - (E(X))^2[/tex]

[tex]= \sum x x^2 * P(X=x) - (E(X))^2 = 0^2*(6/16) + 1^2*(5/16) + 2^2*(4/16) + 3^2*(1/16) - 1.25^2 = 0.9375[/tex]

Similarly, the expected value and variance of Y are:

E(Y) = ∑y y * P(Y=y) = 0*(6/16) + 1*(5/16) + 2*(4/16) + 3*(1/16) = 1.25

Var(Y) = [tex]E(Y^2) - (E(Y))^2[/tex] = [tex]\sum y y^2 * P(Y=y) - (E(Y))^2 = 0^2*(6/16) + 1^2*(5/16) + 2^2*(4/16) + 3^2*(1/16) - 1.25^2 = 0.9375[/tex]

(e) If there is one head in the last three tosses, the conditional probability mass function of X is:

P(X=x | Y=1) = P(X=x, Y=1) / P(Y=1) for x = 0,1,2,3

From the joint probability mass function in part (a), we have:

P(X=0, Y=1) = 1/16, P(X=1, Y=1) = 1/16, P(X=2, Y=1) = 1/16, P(X=3, Y=1) = 2/16

P(Y=1) = 5/16

Using these values, we get:

P(X=0 | Y=1) = (1/16) / (5/16) = 0.2

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The eigenvalue with the larger absolute value for the Jacobian matrix at the point (30568, 386008) is approximately 5269.407, which is positive. No need to enter it as a negative number.

The system of equations is

f(x,y) = 9x^2 + 3x + y - 30 = 0

g(x,y) = 3x^2 + xy - 10^6 = 0

The Jacobian matrix J is

J(x,y) = [ df/dx df/dy ]

[ dg/dx dg/dy ]

where

df/dx = 18x + 3

df/dy = 1

dg/dx = 6x + y

dg/dy = x

Evaluated at the point (30568, 386008), we have

df/dx = 18(30568) + 3 = 550149

df/dy = 1

dg/dx = 6(30568) + 386008 = 582216

dg/dy = 30568

So, J(30568, 386008) =

[550149    1]

[582216  30568]

The eigenvalues of J(30568, 386008) are the solutions to the characteristic equation

det(J - λI) = 0

where I is the identity matrix and det denotes the determinant.

The characteristic equation is

(550149 - λ)(30568 - λ) - 582216 = 0

Expanding and simplifying this expression, we get

λ^2 - 855717λ + 166573528 = 0

Using the quadratic formula, we get

λ = (855717 ± √(855717^2 - 4(166573528))) / 2

λ ≈ 5269.4073 or λ ≈ 315.5927

The eigenvalue with the larger absolute value is 5269.4073. Since it is positive, we don't need to enter it as a negative number. Rounding to 4 decimal places, we get

5269.4073 ≈ 5269.407

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--The given question is incomplete, the complete question is given

" When verifying the stability of the potential coexistence points, you calculated the eigenvalues for each requested point. For x = 8.47*10-8 and the point (30568, 386008), choose the eigenvalue with the larger absolute value. Here, f(x,y) = 9x^2 + 3x + y - 30 = 0 and g(x,y) = 3x^2 + xy - 10^6 = 0What is the value of this eigenvalue, entering it as a negative number if it is negative? Round your answer to 4 decimal places. Your Answer:"--

Answer: 21.4%

Step-by-step explanation: Find the decrease in price per share from 2008 to 2016

=$56- $44

=$12 decrease

Divide by the price per share in 2008

=$12/$56

=0.2142

=21.4% decrease

The equivalent expression to show the number of red and white balloons in each bunch is 8(2 + 4)

Number of red balloons = 16

Number of white balloons = 32

Number of bunches of balloons = 8

Red balloons in each bunch = 16/8

= 2

White balloons in each bunch = 32/8

= 4

Where,

a = the number of bunches of balloons.

b = number of red balloons in each bunch

c = number of white balloons in each bunch

Equivalent expression in the form a(b + c)

So therefore, the equivalent expression can be written as;

8(2 + 4)

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Answer:

Step-by-step explanation: There are four possible digits that the code number can begin with: 1, 3, 5, or 7. Since each of these digits is equally likely to be selected, the probability of the code number beginning with a 7 is 1/4 or 0.25. Therefore, the probability that the code number for a new customer will begin with a 7 is 0.25 or 25%.

Answer:

  see attached

Step-by-step explanation:

You want the empty cells of the given table filled in.

The differences between the first In values are ...

  15 -7 = 8

  21 -15 = 6

The corresponding differences between the Out values are ...

  32 -16 = 16

  44 -32 = 12

The ratios of Out differences to In differences are ...

  16/8 = 2

  12/6 = 2

These are constant, so we can conclude the relation is linear with a slope of m = 2.

We can find the y-intercept by ...

  b = y -mx

  b = 16 -2(7) = 2 . . . . . . using (x, y) = (7, 16) and m=2

Then the equation  of the output (y) in relation to the input (x) is ...

  y = mx +b

  y = 2x +2 . . . . . . . . . . . . . . table entry on 4th line from the bottom

Solving for x, we get ...

  y -2 = 2x

  (y -2)/2 = x

This tells us the input needed to give an output of y is (y -2)/2, the entry in the table on the 3rd line from the bottom.

We can use the equation for y when In is given:

And we can use the equation for x when Out is given:

The completed table is attached.

<95141404393>

The interval the value of the function (f - g)(x) is negative is (-∞, 2]

A function is a rule or definition that maps an input variable unto an output such that each input has exactly one output.

The equations on the possible graphs in the question, obtained from a similar question posted online are;

f(x) = x - 3

g(x) = -0.5·x

(f - g)(x) = x - 3 - (-0.5·x) = 1.5·x - 3

(f - g)(x) = 1.5·x - 3

Therefore; The x-intercept of the function (f - g)(x) = 1.5·x - 3 is; (f - g)(x) = 0 1.5·x - 3

1.5·x - 3 = 0

1.5·x = 3

x = 3/1.5 = 2

x = 2

The y-intercept is the point where, x = 0, therefore;

(f - g)(0) = 1.5×0 - 3 = -3

The interval the function is negative is therefore;

The equations of the possible graphs of the function, obtained from a question posted online are;

f(x) = x - 3, g(x) = -0.5·x

The interval the function (f - g)(x) is negative is required

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The area of the shaded region is 36.3  to 3  significant figures

What is the area?

A two-dimensional figure's area is the amount of space it takes up. In other terms, it is the amount that counts the number of unit squares that span a closed figure's surface.

Step one: find the two diagonals of the kite.

The Horizontal diagonal can be obtained using the cosine rule:

AC² = OA²- OC² - 2 *OA*OC* cosθ

       = 10²+ 10² - 2* 10 *10 * cos(120)

AC² = 200

=> AC=√200 = 14.1

The vertical diagonal of the kite can be obtained by Pythagoras' Theorem:

Please note the law in circle geometry which states that a radius and a tangent always meet at right angles.

This implies that triangle OBC is a right-angled triangle, with angle OCB being 90 degrees, and COB being 60 degrees. This is because the diagonal divides the 120-degree angle into half.

cos(60)= 10/OB

=> OB= 10/ cos(60) = 20 m

Step two: Use the dimensions of the two diagonals of the Kite to find the area:

The area of a Kite is obtained using this formula:

area = pq/2, , where p and q are the two diagonals.

area =( 14.1*20)/2 = 141 m²

Step three: Calculate the area of the sector of the circle.

Area of the sector is obtained using this formula

Area =θ/360 * πr²  = 120/360 * 3.14 * 10²  = 104.66 m²

Step Four: Subtract the area of the sector from the area of the kite:

Area of the shaded region will be  141 m²  -  104.66 m²  = 36.34 m²

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The single summation expression in terms of k is:

\sum_[tex]{i=1}^{{m}}[/tex]i(i+1)(i+2) = 2k + 10

What is algebra?

Algebra is a branch of mathematics that deals with mathematical operations and symbols used to represent numbers and quantities in equations and formulas.

We can approach this problem by first expanding the summation expressions on both sides of the equation:

On the left-hand side:

m k Σ m + 1 Σ = ∑[tex]{i=1}^{{m}}[/tex]i{m} i ∑{j=1}^{i+1} j

On the right-hand side:

k + 5 k = 6k

Now, we can combine the two summations on the left-hand side by first fixing the value of i in the inner summation and then summing over all possible values of i:

m k Σ m + 1 Σ = ∑[tex]{i=1}^{{m}}[/tex]i i ∑{j=1}^{i+1} j = ∑_[tex]{i=1}^{{m}}[/tex]i i \left(\frac{(i+1)(i+2)}{2}\right)

Simplifying this expression, we get:

m k Σ m + 1 Σ = \frac{1}{2} \sum_[tex]{i=1}^{{m}}[/tex]ii(i+1)(i+2)

Now, we can express the right-hand side of the equation as a summation in terms of k:

k + 5 k = 6k = \sum_{i=1}^{k+5} 1

Therefore, the original equation can be written as:

\frac{1}{2} \sum_[tex]{i=1}^{{m}}[/tex] i(i+1)(i+2) = \sum_{i=1}^{k+5} 1

Simplifying further, we get:

\frac{1}{2} \sum_[tex]{i=1}^{{m}}[/tex] i(i+1)(i+2) = k + 5

Therefore, the single summation expression in terms of k is:

\sum_[tex]{i=1}^{{m}}[/tex]i(i+1)(i+2) = 2k + 10.

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The general solution for the Cauchy-Euler equation is a linear combination of the two solutions:

[tex]y(t) = C_1 * t^{-9} + C_2 * t^2[/tex]

To find the general solution to the given Cauchy-Euler equation for t > 0, first, we'll rewrite the equation using the given terms:

[tex]t^2 \frac{d^2y}{dt^2}+ 8t(dy/dt) - 18y = 0[/tex]

Now, we'll use the substitution y(t) = t^m, where m is a constant, to transform the equation into a simpler form:

By using this substitution, we get:

[tex]dy/dt = m * t^{m-1}\\d^{2}y/dt^2= m * (m-1) * t^{m-2}[/tex]

Substitute these expressions back into the original Cauchy-Euler equation:

[tex]t^2 * m * {m-1} * t^{m-2}+ 8t * m * t^{m-1} - 18 * t^m = 0[/tex]

Simplify by dividing both sides by t^(m-2):

[tex]m * (m-1) + 8m - 18t^2 = 0[/tex]

Now, we have a characteristic equation in terms of m:

[tex]m^2 + 7m - 18 = 0[/tex]

Factoring this equation gives:

(m+9)(m-2) = 0

This yields two possible values for m: m1 = -9, m2 = 2

Therefore, the general solution for the Cauchy-Euler equation is a linear combination of the two solutions:

[tex]y(t) = C_1 * t^{-9} + C_2 * t^2[/tex]

Where C1 and C2 are constants determined by any initial conditions.

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