The sample mean tip amount for the 20 parties to which the waitress gave her name was $5.44, with a standard deviation of $1.75. These statistics were $3.49 and $1.13, respectively, for the 20 parties to which the waitress did not give her name. The data were not strongly skewed in either group.

Required:
Use appropriate symbols for the six numbers reported in this paragraph.

Answers

Answer 1

Answer:

First sample size, [tex]n_{x}[/tex] = 20

Second sample size, [tex]n_{y}[/tex] = 20

Sample mean of first sample, [tex]\bar{x}[/tex] = 5.44

Sample mean of second sample, [tex]\bar{y}[/tex] = 3.49

Sample Standard deviation of first sample, [tex]\sigma_{x}[/tex] = 1.75

Sample Standard deviation of second sample, [tex]\sigma_{y}[/tex] = 1.13

Step-by-step explanation:

Given - The sample mean tip amount for the 20 parties to which the waitress gave her name was $5.44, with a standard deviation of $1.75. These statistics were $3.49 and $1.13, respectively, for the 20 parties to which the waitress did not give her name. The data were not strongly skewed in either group.

To find - Use appropriate symbols for the six numbers reported in this paragraph.

Proof -

First sample size, [tex]n_{x}[/tex] = 20

Second sample size, [tex]n_{y}[/tex] = 20

Sample mean of first sample, [tex]\bar{x}[/tex] = 5.44

Sample mean of second sample, [tex]\bar{y}[/tex] = 3.49

Sample Standard deviation of first sample, [tex]\sigma_{x}[/tex] = 1.75

Sample Standard deviation of second sample, [tex]\sigma_{y}[/tex] = 1.13


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