The stopper-puncturing needle should be completely pushed into the evacuated tube:__________. A. after the vein is entered. B. while the equipment is being assembled. C. just before the vein is entered. D. prior to anchoring the vein.

Answers

Answer 1

Answer:

The correct answer is:

after the vein is entered (A.)

Explanation:

The procedure in the question describes venopuncture.

Venopuncture is the method of aseptically collecting blood into the right sample containers. Using a stopper-punturing needle and a vacuum tube, the following procedure is followed:

assemble the needle and hub (needle holder)apply the tourniquet and examine the arm for palpable vein, palpate the veinrelease the tourniquet and swab the collection site with 70% alcoholallow the swab to dryreapply the tourniquetinsert the stopper-puncturing needle (attached to hub) into the appropriate veinafter the vein is entered, the stopper-puncturing needle should be completely pushed into the evacuated (vacuum) tubesblood will flow into the tube until vacuum is completely filledpull out the tube and invert gently several times if the tube contains anticoagulantsplace a gauze on the site of puncture (do not press down the gauze)remove the needle and press down the gauze immediatelydispose the needle into the sharps container or appropriatelylabel the tubes.


Related Questions

convert 6.8 × 10^2 to standard notation.

Answers

Answer:

680

Explanation:

Move the decimal 2 to the right.

When a number is written using only the digits of the number, that is considered standard notation. 6.8 × 10²  is converted into standard notation by shifting two decimal to the right side, then it became 680.

What is standard notation ?

A form of writing a certain number, an equation, or an expression in a way that adheres to set norms is known as a standard notation. For instance, 4,500,000,000 years is how 4.5 billion years is written.

When a number is written using only the digits of the number, that is considered standard notation. Since words are not used in conventional number notation, this is the way that numbers are typically written.

The stages to writing a number in its standard form are as follows: Write the first digit of the supplied number in step one. Step 2: After the first number, add the decimal point. Step 3: Next, count how many digits there are in the supplied number after the first one and express that number as a power of 10.

Thus, the standard notation is 680.

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To prepare 100.0 mL of a 0.0525 M solution of NaCl in water, what mass of sodium chloride is needed? The
molar mass of NaCl is 58.44 g/mol.

Answers

Answer:

0.307 g

Explanation:

Step 1: Given data

Volume of solution: 100.0 mL

Molarity of the NaCl solution: 0.0525 M

Molar mass of NaCl: 58.44 g/mol

Step 2: Calculate the moles of NaCl required

The molarity is equal to the moles of solute (NaCl) divided by the liters of solution.

M = moles of NaCl / liters of solution

moles of NaCl = M × liters of solution

moles of NaCl = 0.0525 mol/L × 0.1000 L = 5.25 × 10⁻³ mol

Step 3: Calculate the mass corresponding to 5.25 × 10⁻³ moles of NaCl

5.25 × 10⁻³ mol × 58.44 g/mol = 0.307 g

Enter a balanced equation for the reaction between aqueous lead (II) nitrite and aqueous lithium chloride to form solid lead (II) chloride and aqueous lithium nitrite.

Answers

Answer:

Pb(NO₂)₂(aq) + 2 LiCl(aq) ⇒ PbCl₂(s) + 2 LiNO₂(aq)

Explanation:

Let's consider the reaction between aqueous lead (II) nitrite and aqueous lithium chloride to form solid lead (II) chloride and aqueous lithium nitrite.

Pb(NO₂)₂(aq) + LiCl(aq) ⇒ PbCl₂(s) + LiNO₂(aq)

This is a double displacement reaction. We will start balancing Cl by multiplying LiCl by 2.

Pb(NO₂)₂(aq) + 2 LiCl(aq) ⇒ PbCl₂(s) + LiNO₂(aq)

Now, we have to balance Li by multiplying LiNO₂ by 2.

Pb(NO₂)₂(aq) + 2 LiCl(aq) ⇒ PbCl₂(s) + 2 LiNO₂(aq)

The equation is now balanced.

The balanced chemical reaction equation required is; Pb(NO2)2(aq) + 2 LiCl(aq) -----> PbCl2(s) + 2LiNO2(aq)

In order to write a balanced chemical reaction equation, we must write down the symbols of the compounds involved as follows;

lead (II) nitrite  - Pb(NO2)2

lithium chloride - LiCl

lead (II) chloride - PbCl2

lithium nitrite - LiNO2

Recall that the principle of writing a balanced chemical reaction equation is that the number of atoms of each element on both sides of the reaction equation must be the same. The required balanced chemical reaction equation is;

Pb(NO2)2(aq) + 2 LiCl(aq) -----> PbCl2(s) + 2LiNO2(aq)

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Eric's father asked an engineer to survey the field behind their house. He wanted to plant some apple and pear trees there. According to the survey, the field is 38 meters (m) long and 17 meters (m) wide. What is the perimeter of the field in centimeters?

Answers

Answer:

P=110 m

Explanation:

Length of the field is 38 m

Breadth of the field is 17 m

We need to find the perimeter of this field. It is in the form of a rectangle. The perimeter of a rectangle is given by :

P=2(l+b)

P=2(38+17)

P=110 m

So, the perimeter of this field is 110 m.

which of these substances are most likely crystalline solids?

Answers

Answer:

diamond

sugar

rubber

salt (NaCl)

wood

ice

flour

Answer:

diamond

sugar

salt

ice

Explanation:


A car drives on a road at a constant speed of 50 miles/hour.
The forward force of the car is ________________
the opposing friction and air
resistance forces.
The forward force of the car and the opposing friction and air resistance forces are ____________
( !!

Answers

Answer:

It will take the police car 3.5 hours to travel a distance of 175 miles traveling at a rate of 50 miles/hour.

Explanation:

If you know the force applied to an object and measure its acceleration, which equation would you use to calculate the object’s mass? m = Fa m = a F m = a/F m = F/a

Answers

Answer: m=F/a

Explanation:

Answer:

d

Explanation:

Which statement is false? a) When reactants become products, they do so through an intermediate transition state. b) At equilibrium, equal amounts of products and reactants are present. c) Most biocatalysts are proteins. d) AG is a function of Keq

Answers

Answer:

b) At equilibrium, equal amounts of products and reactants are present.

Explanation:

At equilibrium , the ratio of product of concentration of products  and product of concentration of  reactants is constant .

                                             A + B ⇄ C + D

                                 [C] [ D]  / [ A ] [ B ] = Constant

So, the statement ( b )  is false .

All other statements are true .

The [H+] of a solution can be determined from the pH using the equation: [H+] = 10 - pH ... Where: [H+] = hydrogen ion concentration. Note: Write [H+] as [H+]. Capitalization counts. Use the rules for logarithms and exponents to solve for pH in terms of [H+].

Answers

Answer:

pH = -log₁₀ [H⁺]

Explanation:

pH is a value in chemistry used in to measure solution trying to determine each quality, purity, risks for health of some products, etc.

As you write in the question, [H⁺] = 10^(-pH)

Using logarithm law (log (m^(p) = p log(m):

log₁₀ [H⁺] = -pH

And

pH = -log₁₀ [H⁺]

Answer:

7 (a neutral solution)

Answer: 10-7= 0.0000001 moles per liter

5.6 (unpolluted rainwater)

Answer: 10-5.6 = 0.0000025 moles per liter

3.7 (first acid rain sample in North America)

Answer: 10-3.7 = 0.00020 moles per liter

The concentration of H+ in the Hubbard Brook sample is 0.00020/0.0000025, which is 80 times higher than the H+ concentration in unpolluted rainwater.

Explanation:

plato

How many different elements occur naturally?

Answers

Answer:

94 are naturally made on earth

Explanation:

Answer:

94 or 98, i think.

Explanation:

Classify each substance based on the intermolecular forces present in that substance.A. H2OB. CH4C. CO D. CH3Cl1. Hydrogen bonding, dipole dipole, and dispersion2. Dipole dipole and dispersion only 3. Dispersion only

Answers

Answer:

H2O - Hydrogen bonding, dipole dipole, and dispersion

CH4 - Dispersion only

CO - Dipole dipole and dispersion only

CH3Cl - Dipole dipole and dispersion only

Explanation:

Hydrogen bonding can only exist when hydrogen is bonded to a small highly electronegative atom such as oxygen hence hydrogen bonds, dipole interactions and dispersion by are present in water.

CH4 is a nonpolar molecule hence only dispersion forces are present.

CH3Cl and CO both possess dipoles in the molecule hence both dipole interactions and dispersion forces exist in the molecule.

You are comparing a reaction that produces a chemical
change and one that produces a physical change. What
evidence could you use to determine which type of
change is occurring?

Answers

If the reaction is a chemical change, new substances with different properties and identities are formed. This may be indicated by the production of an odor, a change in color or energy, or the formation of a solid.

Can someone please help me with these questions!!!!!!

Answers

the answer question 2 is a. boiling point

Answer:

1. A. 10°C

2. A. Boiling point

3. A. Less than liquids.

Explanation:

Draw structures for compounds that meet the following descriptions in proton NMR:a) C2H6O; one singletb) C3H7Cl; one doublet and one septetc) C4H8Cl2O; two tripletsd) C4H8O2; one singlet, one triplet, and one quartet

Answers

Answer:

The structures are shown in the attachments.

Explanation:

Please see the attachments below for the structures.

Explanation:

For the structure in (a)

There is only one environment denoted as 'a'.

Using the (n+1) rule to determine the multiplicity, m

where is the number of neighboring Hydrogen, then

Since, n = 0, then

m = 0 + 1 = 1 (which means singlet)

Hence, one singlet

For the structure in (b)

There are two environments denoted as 'a' and 'b'

For 'a' ; n = 6

Hence, m = n + 1

m = 6 + 1  = 7 (this means septet)

For 'b'; n = 1

then, m = n + 1

m = 1 + 1  = 2 (this means doublet)

Hence, one septet, one doublet

For the structure in (c)

There are two environments denoted as 'a' and 'b'

For 'a' ; n = 2

then, m = n + 1

m = 2 + 1  = 3 (this means triplet)

For 'b' ; n = 2

then, m = n + 1

m = 2 + 1  = 3 (this means triplet)

Hence, two triplets

For the structure in (d)

There are three environments denoted as 'a', 'b', and 'c'

For 'a' ; n = 0

Hence, m = n + 1

m = 0 + 1  = 1 (this means singlet)

For 'b' ; n = 3

then, m = n + 1

m = 3 + 1  = 4 (this means quartet)

For 'c' ; n = 2

then, m = n + 1

m = 2 + 1  = 3 (this means triplet)

Hence, one singlet, one triplet, and one quartet

Suppose now that you wanted to determine the density of a small crystal to confirm that it is graphite. From the literature, you know that graphite has a density of 2.25 g/cm^3. How would you prepare 20.0 mL of the liquid mixture having that density from pure samples of CHCl3 (d = 1.492 g/mL) and CHBr3 (d = 2.890 g/mL)? (Note: 1 mL = 1 cm^3.)

Answers

Answer:

The volume of first and second compound are 9.15 ml and 10.85 ml.

Explanation:

Given that,

Density of graphite = 2.25 g/cm³

Volume of mixture = 20.0 mL

Density of first compound = 1.492 g/ml

Density of second compound = 2.890 g/ml

Let the volume of first mixture = x

The volume of second mixture = (20-x)....(I)

We need to calculate the volume of first compound

Using formula of  density of mixture

[tex]\rho=\dfrac{V_{1}\rho_{1}+V_{2}\rho_{2}}{V_{1}+V_{2}}[/tex]

Where, [tex]V_{1}[/tex] = volume of first compound

[tex]V_{2}[/tex] = volume of second compound

[tex]\rho_{1}[/tex] =density of first compound

[tex]\rho_{1}[/tex] = density of first compound

Put the volume into the formula

[tex]2.25=\dfrac{x\times1.492+(20-x)\times2.890}{x+20-x}[/tex]

[tex]45=1.492x+57.8-2.890x[/tex]

[tex]45-57.8=1.492x-2.890x[/tex]

[tex]12.8=1.398x[/tex]

[tex]x=\dfrac{12.8}{1.398}[/tex]

[tex]x=9.15\ ml[/tex]

We need to calculate the volume of second compound

Using equation (I)

[tex]V_{2}=20-x[/tex]

Put the value of x

[tex]V_{2}=20-9.15[/tex]

[tex]V_{2}=10.85\ ml[/tex]

Hence, The volume of first and second compound are 9.15 ml and 10.85 ml.

The solubility of oxygen in water A. allows for a greater concentration of O2 in water than in air. B. is responsible for thermoclines. C. is greater in cool liquid water than in warm liquid water. D. isn't significantly dependent on temperature

Answers

The ans should be C. ( if i'm not wrong )

This is because the solubility of oxygen increases when temperature in the water is cooler. Cold water can hold more dissolved oxygen than warm water, thus having a higher concentration of oxygen.

Answer:

C. is greater in cool liquid water than in warm liquid water.

Explanation:

Which atom is most likely to form a metallic bond?

aluminum (Al)
helium (He)
phosphorus (P)
carbon (C)

Answers

Answer:

I would say it's A just because it's make no sense for the other answers.

Aluminum atom is most likely to form a metallic bond.

METALLIC BONDS:

Metallic bonds are the kind of bonds that forms between metallic atoms. Electrons are shared between the positive ions called cations. These electrons are called localized electrons.

Metallic bonds are responsible for the properties possessed by metals such as conductivity, lustre etc.

Since metallic bonds forms between metal atoms, it is most likely to form between aluminum atom.

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Can someone please help me w these chemistry conversion? 1. The density of Mercury is 13.6 g/mL. What is the volume of mercury, in quarts has a mass of 95.0 ounces? 2. Tetrachloroethylene, also called PERC, has a density of 1.62 g/mL. It was formerly used as a dry cleaning solvent. What is the mass in pounds of PERC contained in a 55.0 gallon drum? 3. Osmium is the most dense element having a density of 22.5 g/cm^3 Calculate the density of osmium in kg/m^3. 4. The density of Iron is 7.50 g/cm^3. What is the mass, in pounds, of a cube of iron that measures 5.00 cm on a side? 5. Lead has a density of 10.5 g/cm^3. What is the diameter of a lead ball that has a mass of 500.0 g? Report answer in cm.

Answers

Answer:

1. 0.209quart

2. 743.6pounds

3. 22500kg/m^3

4. 2.07pounds

5. 4.50cm

Explanation:

Note that, these questions are related to density which can be calculated using the formula:

Density (p) = Mass (m) / Volume (v)

However, the units are different for each questions, hence, must be made the same

1. 1 ounce = 28.35 grams

95 ounces will be 95 × 28.35 = 2693.2g

Volume = mass/density

Volume of Mercury= 2693.2/13.6

Volume= 198ml

1 ml = 0.00106quart

198ml = 198 × 0.00106 = 0.209quart

2. 1 gallon = 3785.4ml

55 gallons = 55× 3785.4 = 208197ml

Mass = density × volume

Mass = 1.62 × 208197

Mass = 337,279.14g

1 pounds = 453.592 g

337279.14 g = 337279.14/453.592

Mass = 743.6pounds

3. 1g/cm^3 = 1000kg/m^3

Hence, a density of 22.5g/cm^3 will be 22.5 × 1000 = 22500kg/m^3

4. Volume of a cube of side 5cm each will be 5×5×5 = 125cm^3

Density = 7.50g/cm^3

Mass = Density×volume

Mass in grams = 7.50 × 125

Mass = 937.5grams

1 pound = 453.592 g

Therefore, 937.5g will be 937.5/453.592 = 2.07pounds.

5. Volume = Mass / density

Volume = 500/10.5

Volume = 47.62cm^3

Since a ball is spherical in shape, volume of a sphere (V) = 4/3πr^3

To find radius, we say;

47.62 = 1.33 × 3.142 × r^3

47.62 = 4.179 × r^3

r^3 = 47.62/4.179

r^3 = 11.395

r = 3√11.395

r = 2.25cm

To get diameter (d), we multiply the radius (r) by 2,

d = 2 × 2.25

d= 4.50cm

the weight of a sack potato in india is 50kgf. will the weight increase or decrease in bhutan. why​

Answers

Answer:

Assume that the sack was initially close to the sea level. Its weight will increase even though its mass stays the same.

Explanation:

The weight of an object typically refers to the size of the planet's gravitational attraction (a force) on this object. That's not the same as the mass of the object. The weight of an object at a position depends on the size of the gravitational field there; on the other hand, the mass of the object is supposed to be same regardless of the location- as long as the object stays intact.

Let [tex]g[/tex] denote the strength of the gravitational field at a certain point. If the mass of an object is [tex]m[/tex], its weight at that point will be [tex]m \cdot g[/tex].

Indeed, [tex]g \approx 9.81\; \rm N \cdot kg^{-1}[/tex] on many places of the earth. However, this value is accurate only near the sea level. The equation for universal gravitation is a more general way for finding the strength of the gravitational field at an arbitrary height. Let [tex]G[/tex] denote the constant of universal gravitation, and let [tex]M[/tex] denote the mass of the earth. At a distance [tex]r[/tex] from the center of the earth (where

[tex]\displaystyle g \approx \frac{G \cdot M}{r^2}[/tex].

The elevation of many places in Bhutan are significantly higher than that of many places in India. Therefore, a sack of potato in Bhutan will likely be further away from the center of the earth (larger [tex]r[/tex]) compared to a sack of potato in India.

Note, that in the approximation, the value of [tex]g[/tex] is (approximately, because the earth isn't perfectly spherical) inversely proportional to the distance from the center of the planet. The gravitational field strength

On the other hand, the weight of an object of fixed mass is proportional to the gravitational field strength. Therefore, the same bag of potatoes will have a smaller weight at most places in Bhutan compared to most places in India.

Choose all the answers that apply.
Which of the following statements are true?
Ethical scientists make unbiased conclusions.
A dishonest scientst has a lot of integrity.
Confirmation bias is the most common type of bias in science.
Science is based on opinion and subjective evidence.
Bias can be ruled out when similar results are obtained from repeated experiments.

Answers

Explanation:

A dishonest scientst has a lot of integrity.

Confirmation bias is the most common type of bias in science.

Answer: ethical scientists make unbiased conclusions, science is based on opinion and subjective evidence, and bias can be ruled out if similar results are obtained from repeated experiments.

Explanation: If you’re a dishonest scientist you don’t have integrity and confirmation bias isn’t the most common type of bias in science

I need help ASAP!! Plzz

Answers

Answer:

0.1

tenth

hundredth (0.01)

1.05 (can be anywhere from 1.00 to 1.10)

11.42 (can be anywhere from 11.40 to 11.50)

yes, it falls within reasonable doubt

How is it possible for water to be polar but uncharged?

Answers

Water is polar in that the hydrogen atoms bear a partial positive charge, whereas the oxygen atom bears a partial negative charge, due to the electronegativity of oxygen. ... Water disrupts ionic bonds and hydrogen bonds.

Which of the following pairs exhibit an ion-dipole interaction? a. CH_3OH and Na^+ b. Cl^- and K^+ c. CH_3CH_2CH_2CH_2CH_3 and CH_3CH_2CH_2CH_2COOH d. CH_3CH_2OH and H_2O

Answers

Answer:

a. CH_3OH and Na^+

Explanation:

Ion-dipole interaction is the forces of attraction existing between a polar compound and an ion. This particular type of ion-dipole attraction occurs between an electrostatic attraction of an ion and a dipole molecule.

From the given example, CH3OH is a polar compound, and Na^+ is an ion. Therefore, that is the only pair that exhibit the characteristics of an ion-dipole interaction.

For the following, identify the most likely value for x.a. BHx b. CHx c. NHx d. CH2Clx

Answers

Given :

a. [tex]BH_x[/tex] b. [tex]CH_x[/tex] c. [tex]NH_x[/tex] d. [tex]CH_2Cl_x[/tex] .

To Find :

Find the most likely vale of x for each one .

Solution :

a . [tex]BH_x[/tex]

Because boron have valency of 3 .

So , x = 3 .

b . [tex]CH_x[/tex]

Valency of carbon is 4 .

x = 4 .

c . [tex]NH_x[/tex]

Valency of nitrogen is 3 .

Therefore , x = 3 .

d . [tex]CH_2Cl_x[/tex]

Now ,we know valency of carbon is 4 and hydrogen is 1 .

Also , two hydrogen are already there .

So , only 2 electrons left to share .

Since , chlorine have valency of 1 .

Therefore , only 2 electrons of chlorine can connect .

x = 2 .

Hence , this is the required solution .

Monobromination of toluene gives a mixture of three bromotoluene products. Draw and name them.

Answers

Answer:

o-bromotoluene, m-bromotoluene  and p-bromotoluene.

Explanation:

Hello,

In this case, on the attached picture you will find the reaction which yields o-bromotoluene as the first product, m-bromotoluene as the second product and p-bromotoluene as the last one since the substitution could be done at the second (ortho), third (meta) or fourth (para) carbons on the toluene.

Regards.

Calculate the mass in grams of 8.35 × 1022 molecules of CBr4.

Answers

Answer: 45.983 g CBr₄

Explanation:

To convert from moles to grams, you know that we will need molar mass and Avogadro's number.

Avogadro's number: 6.022×10²³ molecules/mol

Molar mass: 331.627 grams/mol

Now that we have what we need, you can use these to solve for grams. [tex]8.35*10^2^2molecules CBr_{4} *\frac{1mol}{6.022*10^2^3molecules} *\frac{331.627 g}{1 mol} =45.983 g[/tex]

Our final answer is 45.983 g CBr₄.

hey can anyone help me with organic chemestry?​

Answers

Organic chemistry is

How would replacing many amino groups with carboxyl groups change the properties of the compound?

Answers

Answer:

This replacements will make the compound less basic and more acidic

Explanation:

Replacing amino groups (-NH₂) which act as bases [because of there ability to accept hydrogen ion (H⁺)] with carboxyl group (-COOH) which acts as acid [because of it's ability to donate hydrogen ion (H⁺)] in a compound changes the property of the compound to be less basic and more acidic.

The diameter of an atom is approximately 1 * 10 ^ - 10 * m . What is the diameter in decimeters?

Answers

Answer:

[tex]d=1x10^{-9}dm[/tex]

Explanation:

Hello,

In this case, considering that 1 m equals 10 dm, the required diameter of the atom in decimetres is:

[tex]d=1x10^{-10}m*\frac{10dm}{1m} \\\\d=1x10^{-9}dm[/tex]

Best regards.

The oxides of nitrogen are very important ingredients in determining urban air pollution. Name each of the following compounds.(a) N2O(b) NO(c) NO2(d) N2O5(e) N2O4

Answers

Answer:

(a) N₂O - Dinitrogen monoxide or Dinitrogen (I) oxide

(b) NO - Nitrogen monoxide or Nitrogen (II) oxide

(c) NO₂ - Nitrogen dioxide or Nitrogen (IV) oxide

(d) N₂O₅ - Dinitrogen pentoxide

(e) N₂O₄ - Dinitrogen tetraoxide.

Explanation:

To name each of the compounds,

(a) N2O; It is properly written as N₂O. N₂O is a colorless, sweet tasting gas also known as "laughing gas".

N₂O - Dinitrogen monoxide OR Dinitrogen (I) oxide.

(b) NO; NO is a colorless gas.

NO - Nitrogen monoxide OR Nitrogen (II) oxide.

(c) NO2; It is properly written as NO₂

NO₂ is a reddish-brown gas.

NO₂ - Nitrogen dioxide or Nitrogen (IV) oxide.

(d) N2O5; It is properly written as N₂O₅

N₂O₅ is a white solid.

N₂O₅ - Dinitrogen pentoxide.

(e) N2O4; It is properly written as N₂O₄;

N₂O₄ is a red-brown liquid with an unpleasant smell.

N₂O₄ - Dinitrogen tetraoxide.

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