What is the chemical formula for ammonium sulfide?
(NH4)2S
2.
(NH4)2SO3
3.
(NH4)2SO4
4.
(NH4)2S203

Answers

Answer 1

Answer:

Sulphide ion(S-²) has a -2 charge

Ammonium (NH4+¹) has a +1 charge

When Exchange of Radicals Occur..

The compound formed is

(NH4)2S.

OPTION A IS YOUR ANSWER!

Answer 2

Answer:

NH4)2S

So it is A

Explanation:


Related Questions

If only 0.225 g of Ca(OH)2 dissolves in enough water to give 0.100 L of aqueous solution at a given temperature, what is the Ksp value for calcium hydroxide at this temperature

Answers

Answer: The [tex]K_{sp}[/tex] value for calcium hydroxide at this temperature is [tex]1.08 \times 10^{-4}[/tex].

Explanation:

Given: Mass of [tex]Ca(OH)_{2}[/tex] = 0.225 g

Volume = 0.100 L

As moles is the mass of substance divided by its molar mass.

So, moles of [tex]Ca(OH)_{2}[/tex] (molar mass = 74 g/mol) is calculated as follows.

[tex]Moles = \frac{mass}{molar mass}\\= \frac{0.225 g}{74 g/mol}\\= 0.003 mol[/tex]

Molarity is the number of moles of substance present in a liter of solution.

Hence, molarity of given solution will be as follows.

[tex]Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.003 mol}{0.1 L}\\= 0.03 M[/tex]

The equation for dissociation of  [tex]Ca(OH)_{2}[/tex] is as follows.

[tex]Ca(OH)_{2} \rightarrow Ca^{2+} + 2OH^{-}[/tex]

This means that [tex][Ca^{2+}] = 0.03[/tex] and [tex][OH^{-}] = 2 \times 0.03 = 0.06[/tex]. Hence, [tex]K_{sp}[/tex] value for this reaction is calculated as follows.

[tex]K_{sp} = [Ca^{2+}][OH^{-}]^{2}\\= (0.03) \times (0.06)^{2}\\= 1.08 \times 10^{-4}[/tex]

Thus, we can conclude that the [tex]K_{sp}[/tex] value for calcium hydroxide at this temperature is [tex]1.08 \times 10^{-4}[/tex].

Which of these is an ion with a charge of 1+?

Answers

The answer is going to be 1 because sodium atom has one electron in its outer shell

HELP PLS HELP i rlly need help omg

Answers

I think g (sorry if it’s wrong)

4. Are there any solutions that have the measure of -3
? Briefly explain why.

Answers

yes for example : 1 x -3

If an atomic number of an element is 24, the number of protons the Atom has is

A. 24
B. 12
C. 189
D.51.996

Answers

Explanation:

i think the answer is A ........ hope this helps

What caused carbon dioxide to decrease in the air (abiotic matter) of the biodome?

Answers

Answer:

As organisms release energy during cellular respiration, carbon dioxide is produced from the carbon in energy storage molecules. ... Carbon dioxide in the biodome decreased because decomposers decreased which means there was a decrease in cellular respiration overall.

Explanation:

Carbon dioxide is "a colorless, odorless gas that is present in the atmosphere and is formed when any fuel containing carbon is burned".

What is atmosphere?

Atmosphere is "a mixture of gases that includes about 78% nitrogen and 21% oxygen at Earth's surface".

What is fuel?

Fuel is "a substance which upon combustion produces a usable amount of energy".

When the population of decomposer decreased, the amount of carbon dioxide in the biodome decreased drastically. The carbon dioxide that used to be in the air (abiotic matter) is now in another part of the ecosystem and the carbon remained constant.

Hence, Carbon dioxide decreased in the air (abiotic matter) of the biodome.

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i. Complete the chemical reaction to show this. Make sure your equation is balanced. (2 points)
C6H12O6 + 02 →

Answers

C6H12O6 + O2 = CO2 + H2O
Balanced Equation:
1 = C6H12O6
6 = O2
6 = CO2
6 = H2O

This is the reaction of respiration. Hence, the complete reaction is:

C₆H₁₂O₆ + O₂ → 6CO₂ + 6H₂O

What is respiration?

Respiration is defined as a metabolic process wherein the living cells of an organism obtain energy (in the form of ATP) by taking in oxygen and releasing carbon dioxide from the oxidation of complex organic compounds. There are two forms of respiration: aerobic and anaerobic.

Aerobic respiration occurs in the presence of oxygen, while anaerobic respiration occurs in the absence of oxygen.

Because it generates the energy required for body function, respiration is significant. It gives the cells oxygen and releases harmful carbon dioxide. Hence, the reaction of cellular respiration is:

                           C₆H₁₂O₆ + O₂ → 6CO₂ + 6H₂O

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Limitations of Pearson rule

Answers

Hope this helps!!
Pearson correlation limitations
Limit: Coefficient values can range from +1 to -1, where +1 indicates a perfect positive relationship, -1 indicates a perfect negative relationship, and a 0 indicates no relationship exists..
Please mark brainliest <3

How many moles of zinc are in 0.535 g ?*

Answers

Answer:

0.00818 moles

Explanation:

In Atom, what is a heavier sub-atomic particle than the others and explain why​

Answers

The nucleons are havier in sub atomic particle like neutrons and protons.

fun fact i read in a book even 1cm³ of nucleons are around 2 million Kg which you can't pick up by hand even by machines like buldozer.

Convert 2.0 micrometer to centimeters and to inches

Answers

Answer:

2x10⁻⁴cm and 7.9x10⁻⁵ inches

Explanation:

Micrometer, μm, is an unit of length. Could be related with another units of lenght as, for example:

1.0μm = 1x10⁻⁴cm

1.0μm = 3.93701x10⁻⁵ inches

That means, 2.0μm are:

2.0μm * (1x10⁻⁴cm / 1μm) = 2x10⁻⁴cm

And:

2.0μm * (3.93701x10⁻⁵ inches / 1μm) = 7.9x10⁻⁵ inches

2) A 0.77 mg sample of nitrogen gas reacts with chlorine gas to form 6.61 mg of a nitrogen
chloride compound. What is the empirical formula of the nitrogen chloride compound?

Answers

Answer:

NCl₃

Explanation:

From the question given above, the following data were obtained:

Mass of nitrogen (N) = 0.77 mg

Mass of chlorine (Cl) = 6.61 mg

Empirical formula =?

The empirical formula of the compound can be obtained as follow:

N = 0.77 mg

Cl = 6.61 mg

Divide by their molar mass

N = 0.77 / 14 = 0.055

Cl = 6.61 / 35.5 = 0.186

Divide by the smallest

N = 0.055 / 0.055 = 1

Cl = 0.186 /0.055 = 3

Therefore, the empirical formula of the compound is NCl₃

in some applications nickel-cadmium batteries have been replaced by nickel-zinc batteries a single nickel-cadmium cell has a voltage of 1.30 V. Based on the idfference in the standard reduction potentials of CD2 and ZN2_, what votlage would you estimate a nickel-zinc a battery would produce

Answers

Larger nickel–zinc battery systems have been known for over 100 years. Since 2000, development of a stabilized zinc electrode system has made this technology viable and competitive with other commercially available rechargeable battery systems.

Please help, any and all is very much appreciated!

Answers

1. True
2. False
3. False
4. True
5. True
6. True
7. All of the above
8. According to their reactivity with other substances
9. Standard temp and pressure
10. Flush your eyes in the eye flush for 15-20 minutes

what does litmus do when it is put into sodium hydroxide?
PLEASE ANSWER ME FAST PLEASE

Answers

Answer:

The red litmus turns to blue

Explanation:

Hope it helps

(1.21 x 10^-3 + 1.3 x 10^-3) x 6.453 x 10^2 =

Answers

Answer:

1.61

Explanation:

Which atom has the smallest atomic radius between cesium, potassium, rubidium, and francium?

Answers

Ur answer is going to be francium

As the diagram model the processo se reproduction lomon) formand change formation Sexual reproduction results in a child that is different from its parents because

A. the child receives all of is genetic information from its mother

B. the child produces its own genetic information once it is formed

C. the child receives half of is genetic information from each parent

D. the child receives all of it's genetic information from it's father there ​

Answers

Answer:

The answer is C. the child receives half of is genetic information from each parent

Explanation:

hope this helps enjoy

If the Bunsen burner gave a luminous flame and some soot was deposited on
the tube, what effect would this situation have on the calculated % of oxygen ?​

Answers

Explanation:

If bunsen burner gave a luminous flame then there will deposition of soot at the bottom of the test tube which is actually pure carbon.

This deposition of soot actually depicts that there is incomplete combustion reaction that has taken place.

Also, the deposition of soot will provide a limited supply of oxygen to the reaction that has been calculated.

Therefore, in order to avoid any formation of soot it is advisable to adjust the burner flame till it produces a blue flame.

If 23.6 mL of 0.200 M NaOH is required to neutralize 10.00 mL of a H3PO4 solution , what is the concentration of the phosphoric acid solution

Answers

Answer:

The correct answer is 0.157 M.

Explanation:

The chemical equation of the mentioned reaction is, 3NaOH + H₃PO₄ ⇄ Na₃PO₄ + 3H₂O The molarity of NaOH given is 0.2 M, the volume of NaOH given is 23.6 ml or 23.6 × 10⁻³ L. The moles of NaOH can be determined by using the formula, Moles of NaOH = Volume of NaOH × Molarity Moles of NaOH = 23.66 × 10⁻³ L × 0.2 M = 0.00472 moles Based on the reaction, 3 moles of NaOH needs 1 mole of H₃PO₄. So, 0.00472 moles of NaOH will require, 0.00472/3 = 0.0015733 moles.

The concentration or molarity of the H₃PO₄ will be, [H₃PO₄] = Moles of H3PO4/Volume of H₃PO₄ in liters (Volume of H₃PO₄ given is 10 ml of 10 × 10⁻³L) = 0.0015733 moles/ (10 × 10⁻³ L) = 0.157 M

10. What is the molarity of a solution containing 20 moles of NaCl dissolved in 10 liters of water?
0.5 mol/L
2 mol/L
5 mol/L
10 mol/L

Answers

Answer:

2 mol/L

Explanation:

M=Mol of solute/L. of solution

M=20mol/10L of H2O= 2mol/L

Answer:

2mol/L

Explanation:

got it correct on my quiz

If the specific heat capacity of copper is 387 J/kg/°C, then how much energy is needed to raise the temperature of 400 g of copper from 30°C to 55°C?

Answers

Answer:

Explanation:

mass = 400 grams * [1 kg/1000 grams] = 0.400 kg

c = 387 Joules / (oC * kg)

Δt = 55 - 30 = 25 oC

E = m*c * Δt

E = 0.4 * 387 * 25

E = 3870 Joules

Each of the following models represents particles present before and after a
chemical reaction which correctly shows conservation of mass during a
reaction?

Answers

Answer:

D

Explanation:

According to the law of conservation of mass, matter can neither be created nor destroyed. The implication of this is that the total mass of reactants should be equal to the total mass of products.

There should be equal masses of reactants and products on both sides of the reaction equation. This most important condition is only satisfied by option D.

Choose the group that corresponds to each element.
Alkali Metal
Alkali earth metal
Halogen
Noble gas

Answers

The group corresponding to alkali metal, alkali earth metal, halogen, and noble gas is IA,IIA, 17, 18 group respectively.

Alkali metals have one outermost electron in their valence shell. They are kept under oil and are in the group IA of the periodic table.Alkaline earth metals have two outermost electrons in their valence shell. Examples are beryllium, magnesium, etc.Halogens have seven electrons in their outermost shells. They are in the periodic table in group 17 naming fluorine to iodine.Noble gas is the one that has fulfilled electronic configuration and doesn't react with any other compound.This is present in group 18 of periodic table.

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What is the mass of 25.5 L of water assuming it is at 4 degrees Celsius?

Answers

Answer:

25.5kg or about 56.2lbs

Explanation:

At 4°C pure water has a mass of about 1 kg/​liter.

So, if there was 25.5 L of water it would be 25.5kg or about 56.2lbs.

Draw the major organic product(s) for the reaction. The starting material is a benzene ring with one substituent. The substituent is a nitrogen bonded to a hydrogen and a carbonyl that is bonded to a methyl group. THis reacts with tert butyl bromide and A l b r 3 to give the product.

Answers

Answer:

See Explanation

Explanation:

In electrophilic aromatic substitution, the benzene ring undergoes substitution when it is reacted with suitable electrophiles.

The products of electrophilic aromatic substitution depends on the substituents already present on the benzene ring. Some substituents activate the ring towards electrophilic substitution and direct the incoming electrophile to the ortho and para positions on the ring while some substituents deactivate the benzene ring towards electrophilic substitution and direct the incoming electrophlle to the meta position on the ring.

The amide substituent is moderately activating and is an ortho, para director hence the products shown in the mage attached to this answer.

an organic compound that contains only carbon and hydrogen and a triple bond (all the other bonds are single bonds) is classified as:
a. alkane
b. alkene
c. alkyne
d. arene

Answers

Answer:

c. alkyne.

Explanation:

Hello there!

In this case, according to the attached file, it turns out possible for us to say that alkanes have only single-bonded carbon atoms, alkenes have two double-bonded carbon atoms and alkynes have two triple-bonded carbon atoms.

In such a way, according to the aforementioned definition, we infer that that an organic compound that contains only carbon and hydrogen and a triple bond (all the other bonds are single bonds) is classified as c. alkyne.

Regards!

) Dinitrogen Tetroxide partially decomposes according to the following equilibrium: N2O4 (g) 2NO2 (g) A 1.00-L flask is charged with 0.400 mol of N2O4. At equilibrium at 373 K, 0.0055 mol of N2O4 remains. Keq for this reaction is __________.

Answers

Answer: The value of [tex]K_{eq}[/tex] for this reaction is 1.578.

Explanation:

Given: Initial moles of [tex]N_{2}O_{4}[/tex] = 0.4 mol

Volume = 1.00 L

Therefore, initial concentration of [tex]N_{2}O_{4}[/tex] is calculated as follows.

[tex]Concentration = \frac{moles}{volume}\\= \frac{0.4}{1.0 L} mol\\= 0.4 M[/tex]

Now, ICE table for the given reaction equation is as follows.

                     [tex]N_{2}O_{4}(g) \rightleftharpoons 2NO_{2}[/tex]

Initial:               0.4               0

Change:           -x                +2x

Equib:  0.4 - x = 0.0055       2x

Hence, the value of x is calculated as follows.

0.4 - x = 0.0055

x = 0.4 - 0.0055

= 0.3945

Now, the [tex][NO_{2}][/tex] is calculated as follows.

2x = [tex][NO_{2}][/tex] = [tex]2 \times 0.3945 = 0.789[/tex]

Therefore, [tex]K_{eq}[/tex] for the given reaction is calculated as follows.

[tex]K_{eq} = \frac{[NO_{2}]^{2}}{[N_{2}O_{4}]}\\= \frac{(0.789)^{2}}{(0.3945)}\\= 1.578[/tex]

Thus, we can conclude that [tex]K_{eq}[/tex] for this reaction is 1.578.

Pea plants have green seeds only if a plant receives an allele for green seeds from each of its parents. What kind of allele produces green seeds in pea plants?

Your answer:


Hybrid

Dominant

Recessive

Mutated

Answers

Answer:If two heterozygous parents with a genotype of Yy are crossed, the possible combination of genotypes in their offspring would be YY, Yy, Yy, and yy. Therefore, the genotypic ratio of the offspring produced is 1:2:1.

Explanation:If two heterozygous parents with a genotype of Yy are crossed, the possible combination of genotypes in their offspring would be YY, Yy, Yy, and yy. Therefore, the genotypic ratio of the offspring produced is 1:2:1.

The law of partial pressures was developed by ___________.

Answers

Answer:

John Dalton

Explanation:

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