Answer:
m = 664.821 kg
General Formulas and Concepts:
Physics
p = mv
p = momentumm = mass (kg)v = velocity (m/s)Explanation:
Step 1: Define variables
m = unknown
p = 3723 kg * m/s
v = 5.6 m/s
Step 2: Find mass
3723 kg * m/s = m(5.6 m/s)
m = 664.821 kg
When dividing, m/s and m/s cancel out to leave kg as our final answerplz answer this...its urgent!!
its about gravitation..only 3 questions
Answer: For #1, 7.3 m/s2.
Explanation: See this wikipedia screenshot for explanation, it's complicated.
1. A kettle contains 1.5kg of water at a
temperature of 18°C. How much energy is
needed to bring the water to the boil?
Answer:
water boiling point is usually 100°C so I think we subtract 18 degrees Celsius from 100 degrees Celsius to get 82 degrees Celsius to be the energy needed
If a small asteroid named ‘B612’ has a radius of only 20 m and mass of
1 × 104 kg, what is the acceleration due to gravity on its surface?
Acceleration produced in the motion of a body under the effect of gravity is called acceleration due to gravity.
It is a vector quantity and it's SI unit is m/s².
It is usually denoted by the symbol g.
Formula of Acceleration due to Gravity:
[tex] \boxed{ \bf{g = \dfrac{GM}{r^2}}}[/tex]
G → Universal Gravitational Constant [tex] \sf (6.67 \times 10^{-11} \ Nm^2/kg^2) [/tex]
M → Mass of the Asteroid (1 × 10⁴ kg)
R → Radius of the Asteroid (20 m)
By substituting values in the equation, we get:
[tex] \rm \longrightarrow g = \dfrac{6.67 \times {10}^{ - 11} \times 1 \times {10}^{4} }{20^2} \\ \\ \rm \longrightarrow g = \dfrac{6.67 \times {10}^{ - 11 + 4} }{400} \\ \\ \rm \longrightarrow g = 0.016675 \times {10}^{ - 7} \\ \\ \rm \longrightarrow g = 1.6675 \times {10}^{ -9} \: m {s}^{ - 1} [/tex]
[tex] \therefore [/tex] Acceleration due to gravity on the surface of small asteroid named ‘B612’ = [tex] \sf 1.6675 \times 10^{-9} \ m/s [/tex]
Acceleration produced in the motion of a body under the effect of gravity is called acceleration due to gravity. Acceleration due to gravity on the surface of small asteroid named ‘B612’ = 1.776 * 10 9 m/s2.
What is acceleration due to gravity?A free-falling item is one that is falling solely as a result of gravity, as was discovered in the previous section of this course. A free-falling object experiences a downward acceleration of 9.8 m/s. (on Earth).
The acceleration of any object moving only as a result of gravity is referred to as the acceleration of gravity.
In fact, this quantity, known as the acceleration of gravity, is so significant to physics that it has its own distinctive symbol, the letter g. The most precise measurement of the gravitational acceleration is 9.8 m/s.
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What does is the glenohumeral joint and what does it do? (ANATOMY)
Your task now is to look up the effects of the temperature on an equilibrium and how the reaction will shift when adding or removing heat. Explain in no less than 4 complete sentences the effect of the temperature and list at least on example.
Answer:
If you increase the temperature, the position of equilibrium will move in such a way as to reduce the temperature again. It will do that by favouring the reaction which absorbs heat. In the equilibrium we've just looked at, that will be the back reaction because the forward reaction is exothermic.
Explanation:
You pull horizontally on a 50 kg crate with a force of 400N and the friction force on the crate in 150N. What is the acceleration of the crate?
If you pull horizontally on a 50 kg crate with a force of 400 N and the friction force on the crate of 150 N, then the acceleration of the crate would be 5 m / s² .
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
As given in the problem if you pull horizontally on a 50 kg crate with a force of 400 N and the friction force on the crate in 150 N.
The net force acting on the crate = 400 N - 150 N
= 250 N
The acceleration of the crate = 250 / 50
= 5 m / s²
Thus, the acceleration of the crate would be 5 m / s² .
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There is a spot of paint on the front wheel of the bicycle. Take the position of the spot at time t=0 to be at angle θ=0 radians with respect to an axis parallel to the ground (and perpendicular to the axis of rotation of the tire) and measure positive angles in the direction of the wheel's rotation. What angular displacement θ has the spot of paint undergone between time 0 and 2 seconds?
Here is the missing information.
An exhausted bicyclist pedal somewhat erraticaly when exercising on a static bicycle. The angular velocity of the wheels takes the equation ω(t)=at − bsin(ct) for t≥ 0, where t represents time (measured in seconds), a = 0.500 rad/s2 , b = 0.250 rad/s and c = 2.00 rad/s .
Answer:
0.793 rad
Explanation:
From the given question:
The angular velocity of the wheel is expressed by the equation:
[tex]\omega (t) =\dfrac{d\theta}{dt}[/tex]
The angular velocity of the wheels takes the description of the equation ω(t)=at−bsin(ct)
SO;
[tex]\dfrac{d \theta}{dt} = at - b \ sin \ ct[/tex]
dθ = at dt - (b sin ct) dt
Taking the integral of the above equation; we have:
[tex]\int \limits^{\theta}_{0} \ d \theta = \int \limits ^{t=2}_{0} at \ dt - (b \ sin \ ct) \dt[/tex]
[tex][\theta] ^{\theta}_{0} = a \bigg [\dfrac{t^2}{2} \bigg]^2_0 - \bigg[ -\dfrac{b}{c} \ cos \ ct \bigg] ^2_0[/tex]
where;
a = 0.500 rad/s2 ,
b = 0.250 rad/s and
c = 2.00 rad/s
[tex]\theta = (0.500 \ rad/s^2 ) \bigg [\dfrac{(2s)^2}{2} \bigg] - \bigg[ -\dfrac{0.250 \ rad/s}{2.00 \ rad/s} \ cos \ (2.00 \ rad/s )( 2.00 \ s) \bigg] - \bigg [ \dfrac{0.250 \ rad/s}{2.00 \ rad/s}\bigg ] cos 0^0[/tex]
[tex]\mathbf{\theta = 0.793 \ rad}[/tex]
Hence, the angular displacement after two seconds = 0.793 rad
What is the average translational KE of 5 moles of gas molecules at 300 K?
a.
2.1 x 103 J
b.
1.87 x 104 J
c.
1.78 x 105 J
d.
1.68 x 106 J
Answer:
What is the average translational kinetic energy of molecules in an ideal gas at 37°C? The average translational energy of a molecule is given by the equipartition theorem as, E = 3kT 2 where k is the Boltzmann constant and T is the absolute temperature.
Explanation:
The average translational energy of a molecule is given by the equipartition theorem as, E = 3kT 2 where k is the Boltzmann constant and T is the absolute temperature.
At its closest approach, a moon comes within 200,000 km of the planet it orbits. At that point, the moon is 300,000 km from the other focus of its orbit, f2. The planet is focus f1 of the moon's elliptical orbit. How far is the moon from the planet when it is 260,000 km from f2?
Answer:
s₁ = 240,000 km
Explanation:
The distance between both the focuses f₁ and f₂ will be the sum of distances of the moon from each focus at a given point. Therefore,
s = s₁ + s₂
where,
s = total distance between the focuses = ?
s₁ = distance between f1 and moon = 200,000 km
s₂ = distance between f₂ and moon = 300,000 km
Therefore,
s = 200,000 km + 300,000 km
s = 500,000 km
Now, when the distance from f₂ becomes 260,000 km, then the distance from f₁(planet) will become:
s = s₁ + s₂
500,000 km = s₁ + 260,000 km
s₁ = 500,000 km - 260,000 km
s₁ = 240,000 km
an average net force of 31.6 N is used to accelerate a 15.0 kg object uniformly from rest to 10.0 m/s leftward. What is the change in momentum?
Answer:
-150 kg m/s
Explanation:
The change of momentum is calculated as ;
Δp= m*Δv where
where
Δp= change in momentum
Δv = vf-vi
m= mass of the object
Change in momentum is also calculated when using the formula;
Δp = F * Δt when F is the net force applied and Δt is the time of action.
In this case;
m= 15 kg
vf= -10 m/s
vi= 0 m/s
Taking rightward direction to be positive, then leftward will be negative.
Applying the formula as;
Δp = m*Δv
Δp = 15 * { -10 -0} = 15*-10 = -150 kg m/s
which type of energy is released when a nucleus is split apart?
a. kinetic energy
b. elastic energy
c. chemical energy
d. nuclear energy
Answer:
D. Nuclear energy
Explanation:
A nucleus is the result of nuclear energy if it is split into an other the same result shall happen it being nuclear energy.
Write an equation of a line that passes through the point (-9,2) and is perpendicular to the line y = 3x - 12
Answer:
y = (-1/3)x + 5
Explanation:
the gradient of required equation (m2)
the gradient of given equation (m1) = 3
m1*m2 = -1 ( they are perpendicular)
3*m2 = -1
m2 = -1/3
required equation
y = m2 + c
( 9,2) satisfy the above equation
2 = (-1/3)*9 + c
c = 5
y = (-1/3)x + 5
Which list places the layers of the sun in the correct order from innermost to outermost?
Corona, photosphere, chromosphere
Photosphere, convective zone, radiative zone
Convective zone, chromosphere, corona
Radiative zone, corona, convective zone
Answer: The answer is A, Corona, Photosphere, Chromoshpere
Explanation:
Just took the test
The Photosphere, Chromosphere, Transition Region, and Corona are the outer layers. Option A is correct.
What are the layer of sun?Corona, photosphere, chromosphere are the layers of the sun in the correct order from innermost to outermost.
The distance is measured from the sun's core for the inner layers and from the sun's surface for the outer layers. The Core and Convection Zone, are the inner layers.
The Photosphere, Chromosphere, Transition Region, and Corona are the outer layers.
Hence, option A is correct.
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HELLO PLEASE HELPPP!! WILL GIVE BRAINIEST
Answer: Wavelength
Explanation:
Answer:
C) wavelength
Explanation:
I hope this is right, have a nice day!
A block weighing 35 N is resting on a steel table (us = 0.40).
The minimum force to start this block moving is ___ N.
Answer: 14
Explanation:
Force(normal)*coefficient
The static friction force is a force that prevents motion of an object kept on a surface, due to the interaction of the surface of the object and the surface on which it is kept
The minimum force required to start the block moving is 14 NReason:
The known parameter are;
The weight of the block, W = 35 N
The static friction of the surface of the table surface, [tex]\mu_s[/tex] = 0.40
Required:
To find the minimum force to start the block moving
Solution:
The force required to start the block moving is given by the frictional force that needs to be surpassed
Force required, F = Force of friction
Force of friction = Normal reaction × Coefficient of static friction
On a flat surface, the normal reaction = The weight of the object
∴ Force of friction, [tex]F_f[/tex] = Weight of the object × Coefficient of static friction
Which gives;
[tex]F_f = W \times \mu_s[/tex]
[tex]F_f = 35 \, N \times 0.40 = 14 \, N[/tex]
Force required, F = Force of friction, [tex]F_f[/tex] = 14 N
The minimum force required to start the block moving, F = 14 N
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An example of a chemical change is water boiling
Answer:
False, Boiling water is an example of a physical change and not a chemical change
Answer:
yes
Explanation:
cos from the boiling water, you can still get another change
In regard to exercise, which of the following statements about safety consideration is correct?
A.
In hot weather, exercising between 10 a.m. and 4 p.m. is best.
B.
Exercising at 100% of your maximum heart rate is best.
C.
Exercising one hour before eating is best.
D.
Remaining well-hydrated while exercising is best
Answer:
the correct answer is
D.Remaining well-hydrated while exercising is best
How does a second class lever make our work easier?
Define malleability?
Answer:
Explanation:
the quality or state of being malleable: such as. a : capability of being shaped or extended by hammering, forging, etc. the malleability of tin.
can anyone help me with this
Answer:
earth is 4.54 billion years old
for an organism to survive they would have to change ( mutate )
A mutation is any permenant change in dna of a gene or chromosome
some mutations are bad and some can be good
Explanation:
As Derrick is driving around town, he stops at a red-light. When the light turns green, he takes off and travels
212m in 6.7 seconds. What is his average acceleration?
Answer:
31.6
Explanation:
velocity÷ time
212 ÷ 6.7 = 31.6m/s
Q: How can variations in the rate of interaction between the hydrosphere and the atmosphere result in global climate change?
A. by causing droughts and floods
B. by producing more greenhouse gases
C. by changing the amount of water on Earth
D. by decreasing the atmospheric temperature
The energy is different within each wave type across the spectrum true or false
Answer:
T kinda waky tho -_-----_-----_-////_----_---///
Explanation:
Answer:
true
Explanation:
PLSS THIS LOOKS SIMPLE Tina throws a softball up with an initial speed of 25 meters per second. Calculate the maximum height that the ball will reach.
Answer:
31.86m
Explanation:
recall that one of the equations of motion can be written
v² = u² + 2as
where
u = initial velocity = 25m/s
v = final velocity = 0m/s because at maximum height, the ball will momentary stop moving (i.e have zero velocity)
a = acceleration = -9.81m/s² (i.e a deceleration as it moves upwards equal to the magnitude of the gravitational acceleration)
s = distance (we are asked to find this)
substituting these into the equation:
v² = u² + 2as
0² = 25² + 2(-9.81)s
0 = 625 - 19.62s
19.62s = 625
s = 625 / 19.62
s = 31.86m
What is the formula for freefall?
Answer: vf = g * t
Explanation:
G represents the acceleration of gravity.
T represents time so multiply the acceleration of gravity times time.
Define kinetic energy in your own words, and write a statement about how kinetic energy is affected as velocity increases.
newtons second law of physics, solve the chart
Answer:
(from top to bottom)
350 N, 80 kg, 10 m/s^2, 80 kg, -15 m/s^2, -3000 N
Explanation:
Force = Mass*Acceleration (aka F = ma)
Using algebra, you can find the variables/unknown values.
Which of the following is strenuous?
Atraining for an athletic competition
Bsharing a candy bar with a friend
Creading an exciting mystery
Dforgetting to complete your homework
Answer:
I think it c
Explanation:
Answer:
Atraining for an athletic competition
La superficie de unas botas suman 400 cm2 y la persona que las usa tiene 45 kg de masa, calcula la presión que ejerce sobre el piso. NOTA: Se debe encontrar la fuerza, para lo cual, se debe obtener el peso utilizando la fórmula de masa por gravedad que es 9.8 m / s2
Answer:
11025 N / m²
Explanation:
Los siguientes datos se obtuvieron de la pregunta:
Área (A) = 400 cm²
Masa (m) = 45 Kg
Aceleración por gravedad (g) = 9,8 m / s²
Presión (P) =?
A continuación, determinaremos la fuerza aplicada. Esto se puede obtener de la siguiente manera:
Masa (m) = 45 Kg
Aceleración por gravedad (g) = 9,8 m / s²
Fuerza (F) =.?
F = m × g
F = 45 × 9,8
F = 441 N
A continuación, convertiremos 400 cm² a m². Esto se puede obtener de la siguiente manera:
1 cm² = 0,0001 m²
Por lo tanto,
400 cm² = 400 cm² × 0,0001 m² / 1 cm²
400 cm² = 0,04 m²
Por tanto, 400 cm² equivalen a 0,04 m².
Finalmente, determinaremos la presión ejercida de la siguiente manera:
Área (A) = 0.04 m².
Fuerza (F) = 441 N
Presión (P) =?
P = F / A
P = 441 / 0,04
P = 11025 N / m²
Por tanto, la presión ejercida es 11025 M / m²
LITERALLY PLZ HELP I WILL GIVE BRAINLIEST If you had the opportunity to interview an experienced scientist at NASA who has been involved in numerous space explorations, what would you want to know? Identify at least three specific questions that you would ask this scientist and briefly explain why you would ask these particular questions.
Answer:
What was your sleep situation like during your time in space? Did you get more or fewer hours of sleep than when you were on earth? I would be very interested in learning about their answer because they still have to perform tasks that require energy and obviously they would need to sleep but do they have to strap themselves down on a bed so they don't float away? Is it easy to fall asleep in space or would your body be confused because time is so much different that it doesn't even follow the same time zones as on earth? That is why I find this to be interesting for them to answer.
Did you have any activities to do aside from researching and your tasks that were mandatory? What would they have done in their free time? I can’t imagine simply doing work the whole time, did they get to bring along certain games or time wasters to do while in space? I would just be really curious to find out how they occupied their free time or if they even had free time.
What was the most difficult part about being in space? Was it terrifying or was the work overwhelming? Was it scary thinking about returning to earth or staying in space for too long? There are so many ways to answer this question so I would be very interested in understanding their fears and their reason for being afraid.
Explanation: