Which line on the graph represents the information in the table?
A. Line a
B. Line b
C. Line c
D. Line c
First one near with CORRECT answer gets brainless.

Answer:

A) 21

Step-by-step explanation:

Mean:

(23 + 18 + 24 + 15 + 25)/5

105/5

21

Answer:

21

The mean is 21. Remember to calculate the mean we add up the numbers then divide them by the number of numbers.

Mark my answer brilliant if it helps you.

the varsity tutors ap statisyics app (app)

a) 640.32 cm^3

b) 98.4 cm^3

(3.14) × 2^2 × 12 = 150.72 cm^3

We need to find the height of the base so we use the Pythagorean theorem.

5^2 + x^2 = 14.1^2

25 + x^2 = 198.81

x^2 = 173.81

x = 13.184

After finding height, we can use the equation for a normal triangular prism:

[tex]\frac{1}{2}[/tex] × Base × Height × Length

[tex]\frac{1}{2}[/tex] × 13.184 × 10 × 12= 791.04cm^3

Total Volume: 791.04 - 150.72 = 640.32 cm^3

[tex]\frac{4}3[/tex] × 3.14 × 1^3 = [tex]\frac{314}{75}[/tex]cm^3

0.5([tex]\frac{4}3[/tex]× 3.14 × 3^3) = 56.52cm^3

5^2 = 3^2 + h^2

25 = 9 + h^2

16 = h^2

h = 4

(3.14) × 3^2 × [tex]\frac{4}{3}[/tex] = 37.68 cm^3

Total Volume = 98.4 after rounding

Answer:

11/12

Step-by-step explanation:

Answer:

[tex]P(50 < x < 150) =0.3834[/tex]

[tex]P(x = 100) =0.0074[/tex]

Step-by-step explanation:

Given

[tex]f(x) = \left \{ {{\frac{1}{100}e^{-x/100}\ x\ge 0} \atop {0\ x<0}} \right.[/tex]

Solving (a): Probability that it will function between 50 and 150 hr before it breaks down

This is represented as:

[tex]P(50 < x < 150) = \int\limits^{150}_{50} {f(x)} \, dx[/tex]

So, we have:

[tex]P(50 < x < 150) = \int\limits^{150}_{50} {\frac{1}{100}e^{-x/100}} \, dx[/tex]

Integrate:

[tex]P(50 < x < 150) =- e^{-x/100}|\limits^{150}_{50}[/tex]

This gives:

[tex]P(50 < x < 150) =- e^{-150/100} - - e^{-50/100}[/tex]

[tex]P(50 < x < 150) =- e^{-150/100} + e^{-50/100}[/tex]

[tex]P(50 < x < 150) =- e^{-1.5} + e^{-0.5}[/tex]

[tex]P(50 < x < 150) =- 0.2231 + 0.6065[/tex]

[tex]P(50 < x < 150) =0.3834[/tex]

Solving (a): Probability that it will function exactly 100 hr before it breaks down

This is represented as:

[tex]P(x= 100)[/tex]

This can be rewritten as:

[tex]P(x= 100) = P(99<x<101)[/tex]

So, we have:

[tex]P(99 < x < 101) = \int\limits^{101}_{99} {f(x)} \, dx[/tex]

So, we have:

[tex]P(99 < x < 101) = \int\limits^{101}_{99} {\frac{1}{100}e^{-x/100}} \, dx[/tex]

Integrate:

[tex]P(99 < x < 101) =- e^{-x/100}|\limits^{101}_{99}[/tex]

This gives:

[tex]P(99 < x < 101) =- e^{-101/100} - - e^{-99/100}[/tex]

[tex]P(99 < x < 101) =- e^{-101/100} + e^{-99/100}[/tex]

[tex]P(99 < x < 101) =- e^{-1.01} + e^{-0.99}[/tex]

[tex]P(99 < x < 101) =- 0.3642 + 0.3716[/tex]

[tex]P(99 < x < 101) =0.0074[/tex]

Hence:

[tex]P(x = 100) =P(99 < x < 101) =0.0074[/tex]

Answer:

Step-by-step explanation:

hello : solve     (x+1)(x+4)=40

x²+5x+4 =40

x²+5x-36 =0      continu  us  delta

Given:

The point is U'(-8,1).

It is translated along <2,0> and reflected across the x-axis.

To find:

The image of U'.

Solution:

The given point is U'(-8,1).

It is translated along <2,0> . So, the rule of translation is:

[tex](x,y)\to (x+2,y+0)[/tex]

[tex]U'(-8,1)\to U_1(-8+2,1+0)[/tex]

[tex]U'(-8,1)\to U_1(-6,1)[/tex]

Then, it is reflected across the x-axis. So, the rule of reflection is:

[tex](x,y)\to (x,-y)[/tex]

[tex]U_1(-6,1)\to U''(-6,-1)[/tex]

The image of U'( -8 , 1) is U''(-6,-1).

Therefore, the correct option is A.

69.82 i think

Step-by-step explanation:

First the area of a rectangle is bh, so 5 times 12 is 60. Then you have a semicircle which is half a circle, so it would be pi(radius)squared divided by 2. The diameter is 5 because it's five on the other side and rectangles have opposite sides congruent. Radius is 2.5 after dividing diameter by 2. 2.5 pi r squared is like 19.634 blah blah blah. Divide that by two and add 60 to get 69.82.

Answer:

27n³+125n³ = 152n³

5.337n)(5.337n)(5.337n)

Answer:

Step-by-step explanation: use math-way a chegg service

Answer:

15:35??

Step-by-step explanation:

1. 20 + 15 = 35

2. 35 + 10= 45

3. 45 + 25 = 70 =  1 hour and 10 minutes

4. 95 mins = 1 hour and 45 minutes

5. 1 hour and 10 mins + 1 hour and 45 minutes = 2 hours and 55 minutes

6. 17:20

- 02:55

   15:35

15:35

i don't  know if this is right but it it does, your welcome.

Step-by-step explanation:

[tex] \frac{2}{4} + \frac{3}{8} = \\ = \frac{4 + 3}{8} = \\ = \frac{7}{8} [/tex]

Answer:

The answer is 0.875 in decimal form but is 7/8 in fraction form

Step-by-step explanation:

Answer:

1/6

Step-by-step explanation:

convert ti decimal then compare the two

Answer:

Hello There!!

Step-by-step explanation:

1/6 is less.You can check this by 2÷5=0.4 and 1÷6=0.1666666667 so 1/6 is less.

hope this helps,have a great day!!

~Pinky~

Area of square = (2x-3)^2

Area = 2x-3 x 2x-3

Area = 4x^2 -6x -6x +9

Area = 4x^2 -12x + 9

Area of ovals = x-5 + x-5 = 2x-10

Area of square - area of ovals:

4x^2  - 12x +9 - 2x -10

4x^2 -14x +19 square units

Answer:

negative linear relationship

Step-by-step explanation:

Answer:

320

Step-by-step explanation:

Step 1: Estimate the answer by rounding .

Step 2: If the divisor is not a whole number, then move the decimal place in places to the right to make it a whole number.

Step 3: Divide as usual.

Step 4: Put the decimal point in the quotient directly above where the decimal point now is in the dividend.

Answer:  320 is the correct answer

Step-by-step explanation:

To answer this questions is simple, you can see it as a long division question or regular division

Regular division:

16 ÷ 0.05 = 1600  

(You can transform this into a simple non-decimal question and solve easliy)

1600 ÷ 5 = 320

This is the way to solve these type of questions without straining your brain in the process.

Answer:

Area of ΔQRS = 2.3 square inches

Step-by-step explanation:

From the given information,

<S + <Q + <R = [tex]180^{o}[/tex]

51 + 44 + <R = [tex]180^{o}[/tex]

95 + <R = [tex]180^{o}[/tex]

<R = [tex]180^{o}[/tex] - 95

    = [tex]85^{o}[/tex]

<R = [tex]85^{o}[/tex]

Applying the Sine rule, we have;

[tex]\frac{q}{SinQ}[/tex] = [tex]\frac{r}{SinR}[/tex] = [tex]\frac{s}{SinS}[/tex]

Using [tex]\frac{r}{SinR}[/tex] = [tex]\frac{s}{SinS}[/tex]

[tex]\frac{r}{Sin 85}[/tex] = [tex]\frac{2.3}{Sin51}[/tex]

r = [tex]\frac{2.3*Sin85}{sin51}[/tex]

  = 2.9483

r = 2.9 inches

Also, [tex]\frac{q}{SinQ}[/tex] = [tex]\frac{s}{SinS}[/tex]

[tex]\frac{q}{Sin44}[/tex] = [tex]\frac{2.3}{Sin51}[/tex]

q = [tex]\frac{2.3*Sin44}{Sin51}[/tex]

  = 2.0559

q = 2.0 inches

From Herons formula,

Area of a triangle = [tex]\sqrt{s(s-q)(s-r)(s-s)}[/tex]

s = [tex]\frac{2.3 + 2.0 + 2.9}{2}[/tex]

  = 3.6

Area of ΔQRS = [tex]\sqrt{3.6(3.6-2.0(3.6-2.9)(3.6-2.3)}[/tex]

                        = 2.2895

Area of ΔQRS = 2.3 square inches

Answer:

2.4

Step-by-step explanation:

Answer:

The answer is false. 2 is not congruent to 5.

Honestly, someone has a different answer but they have a whole paragraph so I think you should listen to what they say.

Answer:

True

Step-by-step explanation:

Same-side exterior angle converse theorem states that if two lines are intersected by a transversal and the same-side exterior angle are congruent, then the two lines are parallel. One can apply this theorem to the given case, and thus lines A and B are parallel.

Answer:

I would believe 90* clockwise.

Step-by-step explanation:

It rotated 90* to be located on its side.

As per the given details, the value of ff.ds over the region V bounded by the planes x = 0, y = 0, z = 0, z = 4, and the surface of the cylinder x² + y² = 9 in the first octant, where F = xî + xyj + 2k, is 81π.

The divergence theorem relates a flux fundamental across a closed floor S to a triple crucial over strong E enclosed by way of the surface.

It states that for a vector field F and a closed floor S that encloses a solid area E, the outward flux of F across S is equal to the triple necessary of the divergence of F over E.

Mathematically, the divergence theorem can be written as:

∫∫ F · dS = ∭ div(F) dV

To examine ff.Ds over the vicinity V bounded by using the planes x = zero, y = zero, z = zero, z = 4, and the floor of the cylinder x² + y² = 9 within the first octant, in which F = xî + xyj + 2k, we can use the divergence theorem. The first step is to locate the divergence of F:

div(F) = ∂Fx/∂x + ∂Fy/∂y + ∂Fz/∂z

= 1 + x

Next, we want to discover the volume enclosed via the surface. The cylinder x² + y² = 9 inside the first octant is a round cylinder with radius 3 and top 4. Therefore, the volume enclosed with the aid of the floor is:

V = ∫∫R (4 - z) dA

= ∫0^3 ∫0^(2π) (4 - z) r dr dθ

= 18π

So,

∫∫S F · dS = ∭V div(F) dV

= ∭V (1 + x) dV

= ∫0^4 ∫0^3 ∫0^(2π) (1 + x) r dθ dz dr

= 81π

Therefore, the value of ff.Ds over the place V bounded through the planes x = 0, y = 0, z = zero, z = four, and the surface of the cylinder x² + y² = 9 inside the first octant, where F = xî + xyj + 2k, is 81π.

For more details regarding divergence theorem, visit:

https://brainly.com/question/31272239

#SPJ1

Answer:

e

Step-by-step explanation:

beishdhsjsvsudjdnbdhdjrjdxbxbudsndnbhhxhxbdhddbdbd

Answer: x > 4

x > 4 would look like that on the graph. If it was x is greater than or equal to 4, then the circle would be completely filled in. Hope this helped!

Step-by-step explanation:

[tex]40 - (40 \div 100 \times 65) = \\ = 40 - (0.4 \times 65) = \\ = 40 - 26 = \\ = 14[/tex]

Answer:

t = 9 s

Step-by-step explanation:

A stone is thrown downward with an intitial velocity of 29.5 m/sec will travel a distance of a meters, where

[tex]s(t) = -4.9t^2 + 29.4+132.3[/tex]

We need to find when the stone will hit the ground. It means when s(t) = 0. So,

[tex]-4.9t^2 + 29.4t+132.3=0\\\\t=-3\ and\ t=9[/tex]

So, the stone will take 9 seconds to hit the ground. Hence, this is the required solution.

Answer:

Let x be the weight of the candy in pounds, then 0.9x is the weight of the milk chocolate in pounds

The weight of the caramels in the candy is 3 pounds, so

An equation that can be used find the total number of pounds of milk chocolate and caramels in the candy is

0.9x + 3 = x ⇒ x = 30

So there are 0.9(30) = 27 pounds of milk chocolate in the candy.

hope this helps