The assumption made about forecasting residuals is that they have a mean zero because the forecasted values are unbiased.
When forecasting residuals, it is typically assumed that they have a mean value of zero. This assumption implies that, on average, the forecasted values are unbiased and do not consistently overestimate or underestimate the true values. A mean-zero assumption is often necessary for accurate forecasting, as it helps ensure that the forecasted residuals are centered around the actual observed values.
On the other hand, the assumption that residuals are normally distributed, have constant variance, or are uncorrelated is not universally made in all forecasting models. While these assumptions are commonly used in certain forecasting techniques like linear regression or time series analysis, they may not always hold true in all situations. The specific nature of the data and the forecasting method being employed determine whether these assumptions are applicable.
Therefore, among the options provided, the assumption made about forecasting residuals is that they have mean zero.
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A game has a 10-sided die. What is the probability of rolling a number less than 3 or an odd number? All answers should be in FRACTION form ONLY.
The probability of rolling a number less than 3 or an odd number is 3/5 in fraction form.
To compute the probability of rolling a number less than 3 or an odd number, we need to calculate the probability of each event separately and then subtract the probability of their intersection.
The probability of rolling a number less than 3 is 2/10, as there are two numbers (1 and 2) that satisfy this condition out of the ten possible outcomes.
The probability of rolling an odd number is 5/10, as there are five odd numbers (1, 3, 5, 7, and 9) out of the ten possible outcomes.
To compute the probability of their intersection (rolling a number less than 3 and an odd number), we observe that there is only one number (1) that satisfies both conditions.
Therefore, the probability of their intersection is 1/10.
To compute the probability of rolling a number less than 3 or an odd number, we sum the probabilities of each event and subtract the probability of their intersection:
Probability of rolling a number less than 3 or an odd number = (2/10) + (5/10) - (1/10) = 6/10 = 3/5.
Therefore, the probability of rolling a number less than 3 or an odd number is 3/5.
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Find the mean of the following probability distribution? Round your answer to one decimal. P(2) 0 0.0017 1 0.3421 2 0.065 3 0.4106 4 0.1806 mean = ___
The mean of the given probability distribution is 3.4.
To find the mean of a probability distribution, we multiply each value of x by its corresponding probability and then sum them up. Using the provided data:
P(2) 0
P(1) 0.0017
P(2) 0.3421
P(3) 0.065
P(4) 0.4106
P(5) 0.1806
mean = 2(0) + 1(0.0017) + 2(0.3421) + 3(0.065) + 4(0.4106) + 5(0.1806)
= 0 + 0.0017 + 0.6842 + 0.195 + 1.6424 + 0.903
= 3.4263
Therefore, the mean of the given probability distribution is approximately 3.4 (rounded to one decimal place).
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question in screenshot
Answer:
10
Step-by-step explanation:
use pythagorean theorm
√(8^2+6^2) = 10
A bicycle has a listed price of $615.98 before tax. If the sales tax rate is 9.75%, find the total cost of the bicycle with sales tax included. Round your answer to the nearest cent, as necessary.
What is the mean? 2, 4, 7, 5, 8, 10
Remember- add all the
numbers, and then divide by the total
amount of numbers
6
9
5
36
Answer:
6
Step-by-step explanation:
2+4+7+5+8+10
=36÷6
=6
Select all the properties of a right triangle.
A. Has a Right Angle
B. Has 1 Obtuse Angle
C. Has Parallel Lines
D. Has Perpendicular Lines
E. Has 3 Acute Angles
If u are an Expert PLzzz Answer Thisss!
Answer:
Sorry sis don't know the meaning
Organisms are present in ballast water discharged from a ship according to a Poisson process with a concentration of 10 organisms/m3 (the article "Counting at Low Concentrations: The Statistical Challenges of Verifying Ballast Water Discharge Standards"† considers using the Poisson process for this purpose).
For what amount of discharge would the probability of containing at least 1 organism be 0.993? (Round your answer to two decimal places.)
The amount of discharge for which the probability of containing at least 1 organism is 0.993 is approximately 0.14 m³.
To find the amount of discharge for which the probability of containing at least 1 organism is 0.993, we can use the Poisson distribution formula. The Poisson distribution describes the probability of a certain number of events occurring in a fixed interval of time or space, given the average rate of occurrence.
In this case, the concentration of organisms in the ballast water is given as 10 organisms/m³. Let's denote λ as the average rate of occurrence, which is equal to the concentration in this case, λ = 10 organisms/m³.
The Poisson distribution formula is:
P(X ≥ k) = 1 - P(X < k) = 1 - e^(-λ) * (λ^0/0! + λ^1/1! + λ^2/2! + ... + λ^(k-1)/(k-1)!)
We want to find the amount of discharge (let's call it x) for which P(X ≥ 1) = 0.993. Plugging in the values into the formula, we have:
0.993 = 1 - e^(-10) * (10^0/0! + 10^1/1!)
Simplifying the equation, we have:
0.993 = 1 - e^(-10) * (1 + 10)
Now we can solve for e^(-10) using logarithms:
e^(-10) = 1 - 0.993 / (1 + 10)
e^(-10) ≈ 0.0045
Substituting this back into the equation, we have:
0.993 = 1 - 0.0045 * (1 + 10)
Simplifying further, we get:
0.993 = 1 - 0.0045 * 11
Now, let's solve for the discharge amount x:
0.993 = 1 - 0.0495x
0.0495x = 1 - 0.993
0.0495x ≈ 0.007
x ≈ 0.007 / 0.0495
x ≈ 0.14 m³
Therefore, the amount of discharge for which the probability of containing at least 1 organism is 0.993 is approximately 0.14 m³.
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The important difference to note for the scales of measurement and how they are analyzed is whether they involve Oratios, intervals categories, ration O numbers, categories O numbers, intervals as responses on the scale.
The important difference to note for the scales of measurement and how they are analyzed is whether they involve ratios, intervals, categories or numbers. The scales of measurement can be divided into four types: nominal, ordinal, interval, and ratio.
Nominal scales use categories or numbers to group data, but these categories or numbers have no inherent order or value. Examples of nominal scales include gender, race, or eye color. Ordinal scales use categories or numbers to group data, but these categories or numbers have a specific order or rank. Examples of ordinal scales include educational attainment, income, or level of agreement on a survey question.
Interval scales use numbers as responses on the scale, but the distance between the numbers is not meaningful. Examples of interval scales include temperature measured in Celsius or Fahrenheit, or IQ scores. Ratio scales use numbers as responses on the scale, but the distance between the numbers is meaningful and there is a true zero point. Examples of ratio scales include height, weight, or income.
In summary, the important difference to note for the scales of measurement and how they are analyzed is whether they involve categories or numbers, and whether the numbers have a specific order or rank, a meaningful distance between them, or a true zero point.
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OMG HELP PLS IM PANICKING OMG OMG I GOT A F IN MATH AND I ONLY HAVE 1 DAY TO CHANGE MY GRADE BECAUSE TOMORROW IS THE FINAL REPORT CARD RESULTS AND I DONT WANNA FAIL PLS HELP-
AND CAN ANYONE PLS DRAW ME THE ANSWERS I CANT UNDERSTAND ANYTHING PLS I BEG U ILL GIVE U BRAINLEST
Answer:
The 2/5th’s bucket is the answer to question one.
for the second one, draw a square or rectangle and divide one of them by 5 (draw 4 lines in it) and fill in two of those lines.
the second fraction, draw another rectangle and draw 3 lines on the inside of it, filling in 3. (you’re creating a visual representation of the fractions. you can also look up ‘3/4 picture’ and ‘2/5 picture’ and copy off the internet.
Step-by-step explanation:
find the volume v of the solid obtained by rotating the region bounded by the given curves about the specified line. y = 3e−x, y = 3, x = 2; about y = 6 v =
The volume (v) of the solid obtained by rotating the region about y = 6 is approximately 339.02 cubic units.
To find the volume of the solid obtained by rotating the region bounded by the curves y = 3e^(-x), y = 3, and x = 2 about the line y = 6, we can use the method of cylindrical shells.
First, let's plot the curves and the line of rotation to visualize the region:
|
| y = 3e^(-x)
| _______
|__________| y = 3
| |
| |___ x = 2
|
y=6|_____________________
We can see that the line y = 6 is above the region bounded by the curves. To find the volume, we will integrate the circumference of each cylindrical shell multiplied by its height.
The height of each cylindrical shell is given by the difference between the line y = 6 and the curve y = 3e^(-x), which is 6 - 3e^(-x).
The radius of each cylindrical shell is given by the distance from the line y = 6 to the x-axis, which is 6 - 0 = 6.
The differential volume element is given by dV = 2πrh dx, where r is the radius and h is the height.
Therefore, the volume of the solid can be obtained by integrating this expression over the range of x from 0 to 2:
V = ∫[0,2] 2π(6 - 3e^(-x))(6) dx
Simplifying the expression:
V = 12π ∫[0,2] (6 - 3e^(-x)) dx
V = 12π ∫[0,2] (6 - 3e^(-x)) dx
V = 12π [6x + 3e^(-x)] evaluated from 0 to 2
V = 12π [(12 + 3e^(-2)) - (0 + 3e^(-0))]
V = 12π (12 + 3e^(-2) - 3)
V = 12π (9 + 3e^(-2))
V ≈ 339.02 cubic units
Therefore, the volume (v) of the solid obtained by rotating the region about y = 6 is approximately 339.02 cubic units.
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An auto maker estimates that the mean gas mileage of its sports utility vehicle is at least 20 miles per gallon. A random sample of 36 such vehicles had a mean of 18 miles per gallon and a standard deviation of 5 miles per gallon. At α = .01 can you reject the auto maker's claim?
Answer:
Yes, we reject the auto maker's claim.
Step-by-step explanation:
H0 : μ ≥ 20
H1 : μ < 20
Sample mean, xbar = 18 ;
Sample size, n = 36
Standard deviation, s = 5
At α = 0.01
The test statistic :
(xbar - μ) ÷ s /sqrt(n)
(18 - 20) ÷ 5/sqrt(36)
-2 /0.8333333
= - 2.4
Pvalue from test statistic : Pvalue = 0.00819
Pvalue < α
0.00819 < 0.01
Hence, we reject the Null
12/5 divided by 21/10
A stem and leaf plot titled High Temperatures in degrees Fahrenheit. The stems are 4, 5, 6, 7. The first column of leaves are 9, 2, 0, 2. The second column of leaves are blank, 4, 1, 3. The third column of leaves are blank, 4, blank, blank. The fourth column of leaves are blank, 6, blank, blank. The fifth column of leaves are blank, 8, blank, blank. The stem and leaf plot shows high temperatures recorded each day at the beginning of the month. Which temperature occurs the most frequently
Answer:
The temperature with the highest frequency is 54
Step-by-step explanation:
Given
The above data
Required
The temperature with the highest frequency
The first step, is to plot the stem and leaf plot.
[tex]\begin{array}{cc}{4} & {9\ \ } & {5} & {2\ 4\ 4\ 6\ 8} & {6} & {0\ 1\ } & {7} & {2\ 3\ } \ \end{array}[/tex]
Next, is to identify the leaf with the highest frequency.
The leaf is 4 (with frequency 2)
Next, is to identify the accompanying stem of the leaf
The stem is 5
Hence, the temperature with the highest frequency is 54
Answer:
B
Step-by-step explanation:
edg 2021
$297.89 with a 9.5% tax
2.75603957 rounded to 2 decimal places
He points (2, -3) and (2,5) represent the locaons of two towns on a coordinate grid, where 1 unit is equal to 1 mile. What is the distance, in miles, between the two towns?
Answer:
Distance between the points is 8 miles.
Step-by-step explanation:
Distance between tow points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is defined by,
Distance = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Distance between the given points (2, -3) and (2, 5) will be,
Distance = [tex]\sqrt{(2-2)^2+(-3-5)^2}[/tex]
= 8 units
Since, 1 unit = 1 mile
Therefore, distance between these points will be 8 miles.
Consider a sample with data values of 6, 17, 14, 7, and 16. Compute the variance. (to 1 decimal) Compute the standard deviation.
The standard deviation of the sample data is 4.6 and the variance is 21.2.
To compute the variance, follow these steps:
1. Calculate the mean (average) of the data values. In this case, (6 + 17 + 14 + 7 + 16) / 5 = 12.
2. Subtract the mean from each data value and square the result. For each value: (6 - 12)² = 36, (17 - 12)² = 25, (14 - 12)² = 4, (7 - 12)² = 25, and (16 - 12)² = 16.
3. Calculate the sum of all the squared differences: 36 + 25 + 4 + 25 + 16 = 106.
4. Divide the sum by the number of data values (5) to get the variance: 106 / 5 = 21.2 (rounded to 1 decimal place).
To compute the standard deviation, take the square root of the variance.
Standard deviation = √(21.2) = 4.6
Variance measures how much the data values differ from the mean, while the standard deviation represents the average amount of deviation from the mean. In this sample, the variance is 21.2 and the standard deviation is 4.6. These metrics help quantify the spread and variability of the data set.
Therefore the standard deviation of the sample data is 4.6.
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PLEASE HELP!
Write down the Equation of the following lines:
1)parallel to y=2x-1 and passing through (1, 8)
Answer:
y=2x+6
Step-by-step explanation:
We use this following formula to find the equation:
[tex]y-y_{1} =m(x-x_{1} )[/tex]
Now, we substitute the values in [tex]y_{1}[/tex] and [tex]x_{1}[/tex] :
[tex]y-8=2(x-1)[/tex]
Distribute the 2 inside the parentheses:
[tex]y-8=2x-2[/tex]
Now add 8 to both sides:
[tex]y=2x+6[/tex] is your answer.
Step-by-step explanation:
y=mx+b
m=slope
b=y-intercept
y=2x-1
2=slope
-1=y intercept
NOTE: parallel lines have the same slope
and we put the point (1,8) into y=mx+b with (x,y)
8=1m+b
now we put in 2 for the slope
8=1(2)+b
6=b
2=m
now insert that back into y=mx+b
y=2x+6
and that is the line that is parallel to y=2x-1 and passes through (1,8)
Hope that helps :)
What is the line of symmetry for the parabola whose equation is y = x2 + 10x + 25?
A-x = -5
B-x = 5
C-x = -10
Answer:
x = -5
Step-by-step explanation:
Please write this as y = x^2 + 10x + 25. Here the coefficients are {1, 10, 25}.
The equation of the axis of symmetry is x = -b/[2a], which here is
x = -10 / [2*1] = -5
PLEASE HELP ASAP
Find the surface area and volume of the cylinder below:
Answer:
Surface Area: 848.23
Volume: 1727.88
Step-by-step explanation:
I know dis im in 8th grade iz ez!
Please Help — Neil is going to a bookstore 45 miles away. The bridge was closed on the way back, so
he had to take an alternate route and had to drive 15 mph slower, which make the trip
back take 7 minutes longer. How fast was he going on the way to the bookstore??
Student Council is selling T-shirts to raise money for new volleyball equipment. There is a fixed cost of
$200 for producing the T-shirts, plus a variable cost of $5 per T-shirt made. Council has decided to sell
the T-shirts for $8 each.
A. Write an equation to represent the total cost, C, as a function of the number, n, of T-shirts
produced.
B. Write an equation to represent the revenue, R, as a function of the number, n, of T-shirts
produced
C. Profit, P, is the difference between revenue (R(n)) and expenses (C(n)). Develop an algebraic
function to model the profit.
D. How many T-shirts does the Student Council have to sell to "break even," make a $0 profit?
Answer:
It is A
Write an equation to represent the total cost, C, as a function of the number, n, of T-shirts
produced.
Step-by-step explanation:
:)
OK a quarter steam covers a 100' square feet how many courts should you buy to stay in the wheelchair ramp
Answer:
He should buy about 2 quart of stain
Step-by-step explanation:
Find the diagram attached
First we need to find the area of the given ramp
The ramp consists of two identical triangles, a larger and small rectangles
Since area of triangle = 1/2 * base * height
Area of the identical triangles = 1/2 * 25ft * 25/12 ft (Note that 1ft = 12in)
Area of the 2 identical triangles = 2* 625/24ft² = 625/12 ft²
Area of the large rectangle = Length * Width
Area of the large rectangle = 25 1/12 * 5
Area of the large rectangle = 301/12 * 5
Area of the large rectangle = 1505/12 ft²
Area of the small rectangle = 25/12 * 5
Area of the small rectangle = 125/12 ft²
Area of the figure = 625/12 + 1505/12 + 125/12
Area of the figure = (625+1505+125)/12
Area of the figure = 2255/12
Area of the figure = 187.917
Area of the figure = 187.917ft²
Since a quarter steam covers a 100' square fee, then;
1 quarter = 100ft²
x = 187.917ft²
Cross multiply
100 * x = 187.917
100x =187.917
x = 187.917/100
x = 1.87917
x ≈ 2
Hence he should buy about 2 quart of stain
I ask for your help fellow strugglers
Answer: C is false
Step-by-step explanation: If B is correct and C is saying otherwise that must mean it's the only false choice :) brainliest would be appreciated :)
I need help with this please help me.
Answer:
a) $93, $117.80, $86.80, $68.20
b) $365.80
Step-by-step explanation:
a)
Add 12 hours to each p.m. time to make the subtraction of hours easier.
Also, use decimal numbers to do the subtraction. Remember that 0:30 means 30 minutes which is 0.5 hour, so 7:30 is the same as 7.5 as a decimal.
Monday: 8:00 to 15:30
15:30 - 8:00 = 1.5 - 8 = 7.5 hours
7.5 hours * $12.40/h = $93
Wednesday: 7:30 to 17:00
17:00 - 7:30 = 17 - 7.5 = 9.5 hours
9.5 hours * $12.40/h = $117.80
Friday: 9:00 to 16:00
16:00 - 9:00 = 16 - 9 = 7 hours
7 hours * $12.40/h = $86.80
Saturday: 10:30 to 16:00
16:00 - 10:30 = 16 - 10.5 = 5.5 hours
5.5 hours * $12.40/h = $68.20
b) Add all the daily amounts above.
$93 + $117.80 + $86.80 + $68.20 = $365.80
X and Y are two continuous random variables whose joint pdf f(x, y) = kr² over the region 0≤x≤1 and 0 ≤ y ≤ 1, and zero elsewhere. Calculate the covariance Cov(X,Y).
The covariance Cov(X, Y) can be calculated for the given joint probability density function (pdf) f(x, y) = kr² over the region 0 ≤ x ≤ 1 and 0 ≤ y ≤ 1.
To calculate the covariance Cov(X, Y), we need to determine the joint probability density function (pdf) of X and Y and apply the formula for covariance.
First, we need to find the constant k by integrating the joint pdf over its entire range to ensure it integrates to 1 (since it represents a probability density function).
The integral of f(x, y) over the region 0 ≤ x ≤ 1 and 0 ≤ y ≤ 1 is given by:
∫∫ f(x, y) dy dx = ∫∫ kr² dy dx.
Integrating with respect to y first, we get:
∫[0,1] ∫[0,1] kr² dy dx = k∫[0,1] r² [y=0 to y=1] dx
= k∫[0,1] r² dx
= k[r²x] [x=0 to x=1]
= k(r² - 0)
= kr².
Since the integral of the joint pdf over its entire range equals 1, we have kr² = 1, which implies k = 1/r².
Now, we can calculate the covariance Cov(X, Y) using the formula:
Cov(X, Y) = E[XY] - E[X]E[Y],
where E denotes the expected value.
Since X and Y are continuous random variables with a uniform distribution over the range [0,1], we have E[X] = E[Y] = 1/2.
To calculate E[XY], we integrate the product XY over the range [0,1] for both x and y:
E[XY] = ∫∫ xy f(x, y) dy dx
= ∫∫ xy kr² dy dx
= k∫∫ xyr² dy dx
= k∫[0,1] ∫[0,1] xyr² dy dx.
Integrating with respect to y first, we get:
E[XY] = k∫[0,1] ∫[0,1] xyr² dy dx
= k∫[0,1] [(1/2)xr² [y=0 to y=1]] dx
= k∫[0,1] (1/2)xr² dx
= (k/2)∫[0,1] xr² dx
= (k/2)[(1/3)x³r² [x=0 to x=1]]
= (k/2)(1/3)r²
= (1/2)(1/3)r²
= 1/6r².
Finally, we can calculate the covariance:
Cov(X,Y) = E[XY] - E[X]E[Y]
= 1/6r² - (1/2)(1/2)
= 1/6r² - 1/4.
Therefore, the covariance Cov(X, Y) for the given joint pdf f(x, y) = kr² over the region 0 ≤ x ≤ 1 and 0 ≤ y ≤ 1 is 1/6r² - 1/4.
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8^15÷8^−3 it needs to like this 43^5 I can't find out the answer
Answer:
Hello!
The answer is 8^18.
Step-by-step explanation:
Answer:
8^12
Step-by-step explanation:
Exponents are confusing at first. You subtract them when dividing, and add them when multiplying, if the base number is the same.
Picture 8 to the 15th as a numerator of:
8x8x8x8x8x8x8x8x8x8x8x8x8x8x8 over a denominator of
8x8x8
To solve that, you'd cancel out 3 of the top 8s and the three bottom 8s, marked in bold to be easier to see. This leaves you with
8^12
Does that help?
Happy to answer questions.
F(x_1,x_2,x_3) = (y_1,y_2,y_3) Set
(1) x_1/ (x_1 + x_2 + x_3) = y_1
(2) x_2/ (x_1 + x_2 + x_3) = y_2
(3) x_3/ (x_1 + x_2 + x_3) = y_3
1. Prove that F is injective.
2. Without appealing to the Inverse Function Theorem, find the investment directly.
3. Find the domain of F
4. Find the range of F, which is the domain of F^-1.
5. Explain why J_f(x) 6=0 when x € Dom (F)
1. Proof that F is injective. Suppose that two different elements in the domain of F have the same image; that is, if x and y are elements of the domain of F and F(x)= F(y). We need to show that x=y. Let F(x) = F(y). This means that y1= x1/ (x1 + x2 + x3) = y1, y2= x2/ (x1 + x2 + x3) = y2 and y3= x3/ (x1 + x2 + x3) = y3.Now adding (1), (2), and (3), we have:y1+y2+y3= x1/ (x1 + x2 + x3) + x2/ (x1 + x2 + x3) + x3/ (x1 + x2 + x3)But this is equal to 1, therefore,x1 + x2 + x3= y1 + y2 + y3 = 1, or, equivalently, y1= 1- y2 - y3x1= (1- y2 - y3)(x1 + x2 + x3) = (1-y2 - y3), x2= y2(x1 + x2 + x3) = y2, and x3= y3(x1 + x2 + x3) = y3Thus, we have constructed an element of the domain of F, with different elements of the domain, that have the same image. Therefore, F is injective.
2. Find the investment directly without appealing to the Inverse Function Theorem. F(x1,x2,x3) = (y1,y2,y3)So, x1= (1- y2 - y3), x2= y2, and x3= y3Thus, the inverse of F is F-1(y1,y2,y3)= ((1-y2-y3),y2,y3)3. The domain of F. The domain of F is the set of all three-tuples, F(x1,x2,x3) where 0 ≤ xi ≤ ∞, and where at least one xi is positive. That is, Dom (F)={(x1,x2,x3)|x1≥0, x2≥0, x3≥0 and (x1,x2,x3)≠(0,0,0)}4. The range of F, which is the domain of F-1. The range of F is the set of all three-tuples, F(y1,y2,y3) where 0 ≤ yi ≤ 1, and where at least one yi is positive.
That is, Rng(F)={(y1,y2,y3)|y1≥0, y2≥0, y3≥0 and y1+y2+y3=1}5. We have J_f(x) = ∣∣ ∂(y1,y2,y3) /∂(x1,x2,x3) ∣∣= ∣∣ ∂y1/∂x1 ∂y1/∂x2 ∂y1/∂x3 ∂y2/∂x1 ∂y2/∂x2 ∂y2/∂x3 ∂y3/∂x1 ∂y3/∂x2 ∂y3/∂x3 ∣∣= ∣∣ (1 / (x1 + x2 + x3) ) - (x1/ (x1 + x2 + x3)2) - (x1/ (x1 + x2 + x3)2) 0 1 / (x1 + x2 + x3) - (x2/ (x1 + x2 + x3)2) 0 0 1 / (x1 + x2 + x3) - (x3/ (x1 + x2 + x3)2) ∣∣= (1 / (x1 + x2 + x3) )((1 - y2 - y3) (1 - y2 - y3 - y3) - y2 (1 - y2 - y3) - y3(1 - y2 - y3)) = (1 / (x1 + x2 + x3) )((1 - y2 - y3 - y2 + 2y2y3 + y2 - y3 - 2y2y3 + y3 - y2y3 - y3 + y2y3)) = 1 / (x1 + x2 + x3) which is non-zero in the domain of F. Therefore, J_f(x) ≠ 0 when x ∈ Dom (F).
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PLEASE HELP ME OUT! QUICK POINTS FOR YOU!
All information needed can be found in the image below
Thank you in advance.
Answer:
5π
Step-by-step explanation:
just need to find half of the circumference
If Tony wants to add a 22% tip to his $35 charge from the barbershop, how much should he add?
Answer:
Tony should add $7.70
Step-by-step explanation:
22% = 0.22
0.22 x $35 = $7.70