Answer:
Sir Isaac Newton was an English mathematician, physicist, astronomer, theologian, and author
Explanation:
but he is most importantly known for having formulated the theory of universal gravity
and for having invented the calculus in the mid to late 1660s
one side of a copper sheet is highly polished and the other side is painted matt black. the copper sheet is very hot and placed in a verticle position. a student places her hands at equal distances from the sheet. explain why her hands are not heated by convection
Answer:
Because radiation does not require material medium for its propagation.
Explanation:
Radiation is one of the types of modes of heat transfer that takes place majorly in gases. Heat energy can be transferred through gases by radiation without heating up the intervening medium. Even, if the available molecules of gases are evacuated, the heat energy would propagate.
Thus, student's hands were not heated by convection since convection is a mode where material medium is required for propagation of heat energy.
Her hands are not heated by convection because radiation does not require material medium for its propagation.
Radiation
It is one of the types of modes of heat transfer that takes place majorly in gases. Heat energy can be transferred through gases by radiation without heating up the intervening medium. Even, if the available molecules of gases are evacuated, the heat energy would propagate.The sun's light and heat cannot reach us by conduction or convection because space is almost completely empty. There is nothing to transfer the energy from the sun to the earth.Thus, student's hands were not heated by convection since convection is a mode where material medium is required for propagation of heat energy.
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PLEASE HELP ME ! ! ! !
Answer:
A. fault
Explanation:
When mechanical and chemical weathering breaks up materials on the Earth's surface, erosion can move them to new locations. For example, wind, water or ice can create a valley by removing material.
hope this helps :)
Mr. Turner is driving through downtown Houston at 35 MPH (15.56 m/s). This is above the posted speed limit and there are cars parked alongside the curb in the lane next to Mr. Turner. Of course, a large delivery truck ahead looks like it is parked and driverless, but the driver's door swings open into the lane ahead of Mr. Turner. Mr. Turner's reaction time is 3/4th's of a second and the stopping distance at his speed is 1.7 meters. The driver exiting the delivery truck is 13.3 meters ahead. Can Mr. Turner stop in time? What is the vehicle's acceleration when the brakes are applied?
How far will the vehicle travel before Mr. Turner engages the brake?
(I need someone to explain this to me)
Answer:
Mr. Turner will not be able to stop in time.
a = - 71.2 m/s²
s₁ = 11.67 m
Explanation:
Since, Mr. Turner is driving at 45.56 m/s and his reaction time for applying brakes is 3/4th of a second. So, the distance covered by car in this time will be:
s₁ = vt
where,
s₁ = distance covered by car before applying brakes = ?
v = speed of car = 15.56 m/s
t = reaction time = 3/4th of second = 0.75 s
Therefore,
s₁ = (15.56 m/s)(0.75 s)
s₁ = 11.67 m
and the distance required for the car to stop after applying brakes is:
s₂ = 1.7 m
So, the total distance traveled by car before stopping will be:
s = s₁ + s₂
s = 11.67 m 1.7 m
s = 13.37 m
since, the driver was 13.3 m ahead.
Therefore, Mr. Turner will not be able to stop in time.
To find the deceleration of Mr. Turner after applying brakes we use 3rd equation of motion:
2as₂ = Vf² - Vi²
where,
a = deceleration = ?
Vf = Final Velocity = 0 m/s
Vi = Initial velocity = 15.56 m/s
Therefore,
2a(1.7 m) = (0 m/s)² - (15.56 m/s)²
a = - (242.1136 m²/s²)/3.4 m
a = - 71.2 m/s²
Which three arrows indicate a phase change that occurs at 0 degrees.
Explanation:
(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1÷1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1 )
A bird is flying at an initial velocity of 5m/s. It flaps its wings harder, causing it to
accelerate forward at 2m/s/s. At this rate, how long would it take for the bird to fly a total
of 25m?
Answer:So first of all you should probably go ask your teacher because he’s the one that feels or she and I think I can help you with this just wait I need her
Explanation:
Oh wait never mind I can’t because you’re nice calling them now but that’s OK my teachers close to me I’m gonna go tell him to come and help me help you
Answer:
7.32 s
Explanation:
2ad = Vf^2 - Vi^2
2(2)(25) = Vf^- (5)^2
Solve for Vf = 8.66 m/s
t=a(Vf-Vi)
t= 2(8.66-5) =7.32 s
A wire having resistance 1 ohm is stretched to double its length. what is its new resistance?
Answer:
1 ohm
Explanation:
resistance doesn't depend upon the length of the material as the material is same
A block slides down a rough ramp with a 30-degree incline as shown.
A diagram of a block on a 30 degree incline.
Which diagram represents the forces acting on the block?
A free body diagram with three forces: a force vector northeast labeled F Subscript N Baseline, a force vector southeast labeled F Subscript f Baseline, and a force vector south labeled F Subscript g Baseline.
A free body diagram with three forces: a force vector northeast labeled F Subscript N Baseline, a force vector southeast labeled F Subscript f Baseline, and a force vector southwest labeled F Subscript g Baseline that is equal in magnitude but opposite in direction to the vector pointing northeast.
A free body diagram with three forces: a force vector north labeled F Subscript N Baseline, a force vector southeast labeled F Subscript f Baseline, and a force vector south labeled F Subscript g Baseline, which is equal in magnitude but opposite in direction the north vector.
A free body diagram with three forces: a force vector northeast labeled F Subscript N Baseline, a force vector northwest labeled F Subscript f Baseline, and a force vector south labeled F Subscript g Baseline.
Answer: The first one
Explanation: My best guess is in the pic attached. Hope this helps.
Answer:
b
e
Explanation:
PLEASE HELP!!! WILL GIVE 30 POINTS!!
Recalling the FITT Principles, decide which principle is used when you increase the number of days per week that you exercise.
Intensity
Frequency
Time
Type
Answer:
I think its frequency
Explanation:
Answer:
its B or A thank me please
Which skateboarder has greater momentum?
a) Skateboarder A: mass = 60 kg; velocity = 1.5 m/s
b) Skateboarder B: mass = 50 kg; velocity = 2.0 m/s
Answer:
skateboard b
Explanation:
p=mv
skateboard a
p=(60kg)(1.5m/s)=90kg*m/s
skateboard b
p=(50kg)(2m/s)=100kg*m/s
Skateboarder B has the greater momentum because the momentum of A is 90 kg m/s and the momentum of B is 100 kg m/s so B has the greater momentum.
What is momentum?Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force applied on a particle is equal to the time rate of change of momentum. Check out Newton's laws of motion.
According to Newton's second law, if a particle is subjected to a constant force for a specific amount of time, the result of the force and time (referred to as the impulse) is equal to the change in momentum. On the other hand, a particle's momentum represents the length of time needed for a consistent force to bring it to rest.
According to the question,
For Skateboarder A :
momentum = 60 × 1.5
momentum = 90 kg m/s
For Skateboarder B :
momentum = 50 × 2
momentum = 100 kg m/s.
Hence, B has greater momentum than A.
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A spring is 17 cm long when it is lying on a table. One end is then attached to a hook and the other end is pulled by a force that increases to 25 N, causing the spring to stretch to a length of 19.2 cm. How much work was required to stretch the spring?
A. 3.13 J
B. 0.552 J
C. 1.67 J
D. 0.276 J
Answer:
D. 0.276 J
Explanation:
When I solved this, I got 0.275, so I chose the one closest.
To solve:
convert 17 cm and 19.2 cm to 0.17 m and 0.192 m
W(on spring) = 1/2 (0.192 m - 0.17 m)(25N)
= 1/2 (.022 m)(25 N)
= 0.275
D. 0.276 J
What is the work?Work is force applied over distance.
Examples of work include lifting an object against the Earth's gravitation, driving a car up a hill, and pulling down a captive helium balloon.
Work is a mechanical form of energy.
The standard unit of work is the joule (J), equivalent to a newton - meter (N · m).
According to the question,
W = Fs
Convert 17 cm and 19.2 cm to 0.17 m and 0.192 m
W = [tex]\frac{1}{2}[/tex](0.192 m - 0.17 m)(25N)
=[tex]\frac{1}{2}[/tex] (.022 m)(25 N)
= 0.276 J
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Which statement does not describe the relationship between genes and
inherited traits?
A. Individual genes carry the instructions for inherited traits.
B. Some inherited traits are affected by more than one gene.
C. Inherited traits carry the instructions for individual genes.
D. Some genes influence more than one inherited trait.
Answer: C. Inherited traits carry the instructions for individual genes.
Explanation: bejewels I know stuff. ☆ - ~ hope this helps
Which of the following are located outside the nucleus of an atom? Select all that
apply.
Electrons
Protons
Neutrons
Nonsense! None of these are located outside the nucleus of the atom.
PLEASE HELP 100 POINTS!!!!!
Study this image of the process of photosynthesis. What’s wrong with the image?
A. Sun rays are shown on the right side of the image.
B. Carbon dioxide is shown as an input.
C. Oxygen is shown as an input.
D. Water is shown as an input.
Answer:
C
Explanation:
Carbon dioxide should be the input, and oxygen should be the output.
Answer:
c
Explanation:
i got it right :D
HELP ME FAST!!!!
a small fish eats plant material. Later that day, a heron dives into the water and eats the small fish.
Which type of organism does the small fish represent in this scenario?
A: parasite
B:predator
C: prey
D: producer
Explain a situation in which a lighter object would take more work to move than a heavier object
Answer: The lighter object could be pushed up a much steeper incline and for a much longer distance.
Explanation: Using the formula for work, W= F d cosФ, you can see that it takes into account distance and the angle of the incline. With a much larger incline and with much more distance to cover, eventually the lighter object would require more work than a heavier object with no incline and very little distance to cover.
look at the illustration , what concepts of heat are being shown in this pictures
Answer:
♥ Convection.
♥ Conduction.
♥ Radiation.
♥ ( お力になれて、嬉しいです！) ♥
Help meeeeeeeeeeeee ill mark brainlist to people
Answer: question 1 , would be one question 2 , would be 1 joule and number three would be number one and number four would be , power and last one would be, number two
Explanation: sorry if its wrong
Which of the following statements are TRUE, you can select more than one. * IT
(4 Points)
Chemical reactions always involve changes in energy.
Energy must be taken away to break bonds
Forming bonds releases energy
Energy is released in chemical reactions
Answer:
Chemical reactions always involve changes in energy.
Energy is released in chemical reactions
Explanation:
Chemical reactions involves the formation and breaking of bonds by the combination of atoms in a system.
Chemical reactions always involve changes in energy which can be exothermic or endothermic in nature. When bonds are broken energy is always released, bond dissociation is an exothermic process. When bonds are formed, energy is used up and this process is an endothermic one.Do astronauts have the same WEIGHT in
space?
No
Yes
Answer:
Explanation: Astronauts on the orbiting space station are weightless because... a. there is no gravity in space and they do not weigh anything. ... space is a vacuum and there is no gravity in a vacuum.
Answer:
No I believe
Explanation:
4. A trolley of mass 2kg rests next to a trolley of mass 3 kg on a flat
bench as shown in the diagram. When the spring is released
between the trolley's, they pushed apart. The 2kg travels to left at a
velocity of 6m/s.
a. What is the total momentum of the trolleys before
separation?
b. What is the total momentum of the trolleys after
separation?
c. What is the momentum of of 2kg trolley after
separation
d. What is the momentum of 3kg trolley after separation?
e. What is the velocity of the 3kg trolley?
Answer:
a. The total momentum of the trolleys which are at rest before the separation is zero
b. The total momentum of the trolleys after separation is zero
c. The momentum of the 2 kg trolley after separation is 12 kg·m/s
d. The momentum of the 3 kg trolley is -12 kg·m/s
e. The velocity of the 3 kg trolley = -4 m/s
Explanation:
a. The total momentum of the trolleys which are at rest before the separation is zero
b. By the principle of the conservation of linear momentum, the total momentum of the trolleys after separation = The total momentum of the trolleys before separation = 0
c. The momentum of the 2 kg trolley after separation = Mass × Velocity = 2 kg × 6 m/s = 12 kg·m/s
d. Given that the total momentum of the trolleys after separation is zero, the momentum of the 3 kg trolley is equal and opposite to the momentum of the 2 kg trolley = -12 kg·m/s
e. The momentum of the 3 kg trolley = Mass of the 3 kg Trolley × Velocity of the 3 kg trolley
∴ The momentum of the 3 kg trolley = 3 kg × Velocity of the 3 kg trolley = -12 kg·m/s
The velocity of the 3 kg trolley = -12 kg·m/s/(3 kg) = -4 m/s
a-The total momentum of the trolleys before separation=0
b.The total momentum of the trolleys after separation=0
c. The momentum of 2kg trolley after separation=12kg-m/sec
d. The momentum of 3kg trolley after separation=-12kg-m/sec
e. The velocity of the 3kg trolley=4kg-m/sec
Given-
Trolley A with mass= 2kg
Trolly B with mass= 3kg
Velocity of trolly A =6m/sec
A- Total momentum of the trolleys before separation-
Here, in this problem both the trolleys are in the rest position hence the momentum of both trolleys = 0
B- Total momentum of the trolleys after separation-
We know that motion never changes in an isolated collection of objects,
hence the momentum of the trolleys before and after the separation=0
C- Momentum of the Trolley A (2kg)-
It is known that momentum= Mass x Velocity
[tex]P=m\times v[/tex]
[tex]P=2\times 6[/tex]
[tex]P=12[/tex]
Hence, the momentum of the 2kg trolley is 12 kg-m/sec
D- Momentum of the Trolley B (3kg)-
As we know that motion never changes in an isolated collection of an object hence the total moment of after saparation = 0
hance the momentum of the trolley B will be equal and opposite to the momentum of trolley A=
[tex]P= -12[/tex]
Momentum of trolley B (3kg) is -12kg-m/sec
E- The velocity of the 3kg trolley-
The momentum of trolley A= Momentum of trolley B
[tex]m_{b} v_{a} =m_{b} v_{a}[/tex]
[tex]-2\times 6=3\times v_{a}[/tex]
[tex]v_{a}=-4[/tex]
The value of the velocity of the 3kg trolley is -4m/sec
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The block in the drawing has dimensions L0×2L0×3L0,where L0 =0.5 m. The block has a thermal conductivity of 300 J/(s·m·C˚). In drawings A, B, and C, heat is conducted through the block in three different directions; in each case the temperature of the warmer surface is 37 ˚C and that of the cooler surface is 8 ˚C Determine the heat that flows in 3 s for each case.
The drawing showing the block is missing, so i have attached it.
Answer:
Q_p = 19575 J
Q_o = 8700 J
Q_g = 78300 J
Explanation:
We are given L0 = 0.5 m
From the image, we can see that;
Length; L = 3L0 = 3 × 0.5 = 1.5 m
Width; W = L0 = 0.5 m
Height; H = 2L0 = 2 × 0.5 = 1 m
Temperature of warmer surface; T_h = 37 ˚C
Temperature of cooler surface; T_l = 8 ˚C
thermal conductivity; k = 300 J/(s·m·C˚)
Time for which the heat flows; t = 3 s
Now, from Fourier's law of conduction, the rate of heat flow is given by;
Q/t = kA(dT/dx)
Where;
A is area
dt is change in temperature = 37 - 8 = 29°C
dx is perpendicular distance
Now, for the amount heat flow perpendicular to the pink surface, from the image dx will be the height 1 m.
Thus;
Q_p/3 = 300 × (1.5 × 0.5) × (29/1)
Q_p/3 = 6525
Q_p = 3 × 6525
Q_p = 19575 J
for the amount heat flow perpendicular to the orange surface, from the image dx will be the length 1.5 m.
Thus;
Q_o/3 = 300 × (1 × 0.5) × (29/1.5)
Q_o/3 = 2900
Q_o = 2900 × 3
Q_o = 8700 J
for the amount heat flow perpendicular to the green surface, from the image dx will be the width 0.5 m.
Thus;
Q_g/3 = 300 × (1 × 1.5) × (29/0.5)
Q_g/3 = 26100
Q_g = 26100 × 3
Q_g = 78300 J
Newton's first law of motion is also called the law of
pls help
Answer:
looks like law of inertia
Explanation:
Answer:
The focus of Lesson 1 is Newton's first law of motion - sometimes referred to as the law of inertia. Newton's first law of motion is often stated as. An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.
How does energy release from the sun reach Earth? How does the sun's energy interact with Earth's atmosphere and hydrosphere?
help plz soon :((
Answer:
When the Sun's energy moves through space, it reaches Earth's atmosphere and finally the surface. This radiant solar energy warms the atmosphere and becomes heat energy. This heat energy is transferred throughout the planet's systems in three ways: by radiation, conduction, and convection.
NEED HELP ASAP, WILL GIVE BRAINLIEST
Which is an example of convection currents?
marshmallows toasting over a campfire
a pot being heated by an electric burner
feet getting hot when stepping across sand
a radiator emitting warm air and drawing in cool air
Answer: A radiator emitting warm air and drawing in cool air.
This is due to the warm air expanding and begins to rise as it is less dense. The cool air begins to "fall" as it is denser, drawing nearer to the radiator. The radiator will then heat the cool air and it will rise. The process then continues
Answer:
It's D
Explanation:
Can't explain I'm taking a timed test(not including this question it wass related to what I looked up)
Byeee!
I hope this helped!
1. An object with a mass of 2.0 kg accelerates 2.0 m/s when an unknown force
is applied to it. What is the amount of the force?
2. An object with a mass of 5.0 kg accelerates 8.0 m/s? when an unknown force
As applied to it. What is the amount of the force?
3. An object with a mass of 1500 g (grams) accelerates 10.0 m/s when an
unknown force is applied to it. What is the amount of the force?
Answer:
Given: 6 questions with certain values of mass and acceleration.
To find: The amount of force?
Solution:
An object with a mass of 2.0 kg accelerates 2.0 m/s2 when an unknown force is applied to it. What is the amount of the force?
F = m x a = 2 x 2 = 4 N
An object with a mass of 5.0 kg accelerates 8.0 m/s2 when an unknown force is applied to it. What is the amount of the force?
F = m x a = 5 x 8 = 40 N
An object with a mass of 1500 g (grams) accelerates 10.0 m/s2 when an unknown force is applied to it. What is the amount of the force?
Now in this mass is in grams, so converting it kg, we get:
1500/1000 kg = 1.5 kg
F = m x a = 1.5 x 10 = 15 N
Explanation:
A 2.80 kg mass is dropped from a height of 4.50 m . Find its potential energy (PE) at the moment it is dropped .
Answer:0
Explanation:
because it ran out when it hit the ground
ANSWER ASAP!!!!!!!!
Southwest Airlines has two mission statements: one for customers and one for _____ .
Answer:
Employees
Explanation:
1) The corporate mission statement of Southwest Airlines states that the airline is focused on the provision of the high quality customer service that will also be given with kindness, a good nature, pride that reflect the essence of the Company
2) The mission statement for the employees is the provision of an equal opportunity and stable work environment that promotes personal development and learning.
A certain AM radio wave has a frequency of
1.12 x 10^6
Hz. Given that radio waves travel at
2.99 x 10^8
m/s, what is the wavelength of this radio wave? (Round your answer to three significant figures.)
Answer:
267 m
Explanation:
v=λf
v= [tex]2.99*10^8[/tex]m/s
λ=?
f=[tex]1.12*10^6[/tex]Hz
[tex]2.99*10^8=(1.12*10^6)[/tex]λ
λ=267 m
A 49 kg person is being dragged in their sleeping bag to the lake by a 593 N
force at an angle of 30°. If the person accelerates at a rate of 0.57 m/s2, how
much resistive forte (force of friction) is acting on them?
Answer:
485.62 N
Explanation:
To obtain the magnitude of unbalanced forces acting on the body;
Unbalanced Force = Horizontal Component of Applied Force - Frictional Force
Frictional Force = Horizontal Component of Applied Force - Unbalanced Force
f = frictional force = ?
F = Applied force = 593 N
m = mass of person = 49 kg
a = acceleration = 0.57 m/s²
θ = Angle with horizontal = 30°
Hence;
Horizontal Component of Applied Force = (593 N)(Cos 30°)
Unbalanced Force = (49 kg)(0.57 m/s²)
f = (593 N)(Cos 30°) - (49 kg)(0.57 m/s²)
f = 513.55 N - 27.93 N
f = 485.62 N
NEED HELP ASAP, WILL GIVE BRAINLIEST
What effect would El Niño most likely have on organisms?
El Niño would cause the extinction of an entire species.
El Niño would cause changes in the genetic makeup of organisms.
El Niño would cause continents to move to different parts of the planet.
El Niño would cause organisms to move in search of food and better conditions.
Answer:
i think the best one is c
Explanation: