Write the following ratio using two other notations. 7:6 Use only the numbers above (not any others).​

Write The Following Ratio Using Two Other Notations. 7:6 Use Only The Numbers Above (not Any Others).

Answers

Answer 1

[tex]\textbf{Notation one:}~~ \dfrac 76\\\\\textbf{Notation two:} ~ \text{7 to 6}[/tex]


Related Questions

Jeff is going snowboarding this weekend and wants to determine the exact slope of this hill.

Answers

Answer:

-2/5

Step-by-step explanation:

the distance between -1 and -3 on the y-axis is 2. 2 is the rise of your slope. two find the run, find the distance between -5 and 0. The distance is negative 2. Rise over run equals the slope so -2/5 is the answer


9. The figure below is made up of a rectangle and a semicircle.
What is the area, in square feet, of the figure? (Use = 3.14)
54
68.13
72.84
92.76

Answers

Area of rectangle + area of semicircle
Base x height + 1/2 pi x radius^2
9 x 6 + 1/2 x 3.14 x 3^2
54 + 14.13
65.13 ft^2

2x+2y
3x+3y


=5
=7


How many solutions does the system of equations above have?

Answers

The system of equations have one solution

How to determine the number of solutions?

The equations are given as:

2x + 2y = 5

3x + 3y = 7

The above equations are distinct linear equations.

This means that they would have one point of intersection, if plotted on a graph

Hence, the system of equations have one solution

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TRUE OR FALSE
1. Standard units gives a consistent and accurate of the volume of a container.
TRUE OR FALSE ?

Answers

Answer:

True

Step-by-step explanation:

Cant really provide step by step per se.

a pie shop offers 20% off the price of a large pie every Monday night. If the regular price is $22, what is the discounted price?
brainliest to answrer

Answers

4.4 is the discounted price leading to 17.6

Answer:

$17.60

Step-by-step explanation:

20% of $22 is $4.4 - Subtract $4.40 from $22 to calculate the discounted price: $17.60

Hope this helped! :)

Kapil's robot starts 70cm from its charging base. It faces the base, then turns 60 degrees clockwise, as shown. Finally, the robot moves 50cm. After moving, how far is the robot from the charging base? Do not round during your calculations. Round your final answer to the nearest centimeter.

Answers

The distance of the robot from the charging base is gotten as; 62 cm

How to use Cosine Rule?

From the image attached showing the movement of Kapil's robot, we can use cosine rule to find the value of h which is the distance of the robot from the charging base.

The distance of the robot from the charging base is gotten by;

h = x² + b² - 2xb cos 60

h = 50² + 70² - 2*50*70 * 0.5

h = 62 cm

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what is the volume of a cone with a radius of 4x and a height of 21xy^2?

Answers

The volume of a cone with radius of 4x and a height of 21xy² is 352 x³y²

How to calculate the volume of a cone

Using the formula:

V=πr²h/3

Where r= radius = 4x

h= height = 21xy∧2

Substitute the values into the equation

V = 22/7 × 4x × 4x × (21 × x × y × y) ÷ 3

V = 22/7 × 16x² × 7xy²

V= 22 × 16x² × xy²

Multiply all through

Volume, V = 352 x³y²

Therefore, the volume of the cone is 352 x³y²

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Use Cramer’s rule to solve for x: x + 4y − z = −14 5x + 6y + 3z = 4 −2x + 7y + 2z = −17

Answers

Looks like the system is

x + 4y - z = -14

5x + 6y + 3z = 4

-2x + 7y + 2z = -17

or in matrix form,

[tex]\mathbf{Ax} = \mathbf b \iff \begin{bmatrix} 1 & 4 & -1 \\ 5 & 6 & 3 \\ -2 & 7 & 2 \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} -14 \\ 4 \\ -17 \end{bmatrix}[/tex]

Cramer's rule says that

[tex]x_i = \dfrac{\det \mathbf A_i}{\det \mathbf A}[/tex]

where [tex]x_i[/tex] is the solution for i-th variable, and [tex]\mathbf A_i[/tex] is a modified version of [tex]\mathbf A[/tex] with its i-th column replaced by [tex]\mathbf b[/tex].

We have 4 determinants to compute. I'll show the work for det(A) using a cofactor expansion along the first row.

[tex]\det \mathbf A = \begin{vmatrix} 1 & 4 & -1 \\ 5 & 6 & 3 \\ -2 & 7 & 2 \end{vmatrix}[/tex]

[tex]\det \mathbf A = \begin{vmatrix} 6 & 3 \\ 7 & 2 \end{vmatrix} - 4 \begin{vmatrix} 5 & 3 \\ -2 & 2 \end{vmatrix} - \begin{vmatrix} 5 & 6 \\ -2 & 7 \end{vmatrix}[/tex]

[tex]\det \mathbf A = ((6\times2)-(3\times7)) - 4((5\times2)-(3\times(-2)) - ((5\times7)-(6\times(-2)))[/tex]

[tex]\det\mathbf A = 12 - 21 - 40 - 24 - 35 - 12 = -120[/tex]

The modified matrices and their determinants are

[tex]\mathbf A_1 = \begin{bmatrix} -14 & 4 & -1 \\ 4 & 6 & 3 \\ -17 & 7 & 2\end{bmatrix} \implies \det\mathbf A_1 = -240[/tex]

[tex]\mathbf A_2 = \begin{bmatrix} 1 & -14 & -1 \\ 5 & 4 & 3 \\ -2 & -17 & 2 \end{bmatrix} \implies \det\mathbf A_2 = 360[/tex]

[tex]\mathbf A_3 = \begin{bmatrix} 1 & 4 & -14 \\ 5 & 6 & 4 \\ -2 & 7 & -17 \end{bmatrix} \implies \det\mathbf A_3 = -480[/tex]

Then by Cramer's rule, the solution to the system is

[tex]x = \dfrac{-240}{-120} \implies \boxed{x = 2}[/tex]

[tex]y = \dfrac{360}{-120} \implies \boxed{y = -3}[/tex]

[tex]z = \dfrac{-480}{-120} \implies \boxed{z = 4}[/tex]

Answer:

in photo attached.

Step-by-step explanation:

For all values of x
f(x) = 3x + 2
Find f-¹(-12)

Answers

Answer:

-4.67

Step-by-step explanation:

first find f^-1(x)

let f(x)=y

y=3x+2

3x=y-2

x=y-2/3

Therefore f^-1(x)=x-2/3

Now f^-1(-12)=-12-2/3

=-14/3

=-4.67

please someone help me​

Answers

Answer:

uh I'm not so sure but

Step-by-step explanation:

it might be 1664

Need help with this math question

Answers

Hey there!

Answer :

[tex] \displaystyle{\orange{\boxed{\bold{\green{d = -5}}}}}[/tex]

[tex] \\ [/tex]

Explanation:

[tex] \displaystyle{ \frac{4}{5}d + 3 = -2 - \frac{1}{5}d} \\ [/tex]

[tex] \hookrightarrow [/tex] Subtract 3 from both sides :

[tex] \\ \displaystyle{ \frac{4}{5}d + 3 \bold{ \red{ - 3} }} = \displaystyle{ - 2 - \frac{1}{5}d \bold{ \red{ - 3}} } \\ \\ \implies \displaystyle{\frac{4}{5}d = - \frac{1}{5}d - 5 } \: \: \: \: [/tex]

[tex] \\ \hookrightarrow [/tex] Add [tex] \frac{1}{5}d [/tex] to both sides :

[tex]\\ \displaystyle{\frac{4}{5}d \: \bold{ \blue{ + \frac{1}{5}d }} = \displaystyle{ - \frac{1}{5}d - 5 \: \bold{ \blue{ + \ \frac{1}{5}d }}}} \\ \\ \implies \displaystyle{\frac{5}{5}d = - 5} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \implies \displaystyle{\green{ \boxed{ \orange{{d = - 5}}}}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

Therefore, our answer is d = -5

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add [tex]\bf{\frac{1}{5}d }[/tex] on both sides.

[tex]\boldsymbol{\dfrac{4}{5}d+3+\dfrac{1}{5}d=-2 }[/tex]

combine [tex]\bf{\frac{4}{5}d }[/tex] and [tex]\bf{\frac{1}{5}d }[/tex] to get d.

[tex]\boldsymbol{d+3=-2}[/tex]

Subtract 3 from both sides.

[tex]\boldsymbol{d=-2-3}[/tex]

Subtract 3 from −2 to get −5.

[tex]\boxed{\boldsymbol{d=-5}} \ \ \to \ \ \bf{Answer}[/tex]

Verification

Let d=-5.

[tex]\sf{\dfrac{4}{5}\times-5+3=-2-\dfrac{1}{5}\times-5 }[/tex]

[tex]\rm{Apply \ this \ rule:\dfrac{a}{b}\times c=\dfrac{ac}{b} }[/tex]

[tex]\sf{\dfrac{4\times-5}{5}+3=-2-\dfrac{1}{5}\times-5 \ \ \to \ \ Multiply \ 4 \ by \ -5 }[/tex]

[tex]\sf{\dfrac{-20}{5}+3=-2-\dfrac{1}{5}\times-5 }[/tex]

[tex]\rm{Move \ the \ negative \ symbol \ to \ the \ left. }[/tex]

[tex]\sf{-\dfrac{20}{5}+3=-2-\dfrac{1}{5}\times-5 \ \ \to \ \ Simplify \ \frac{20}{5} \ to \ 4. }[/tex]

[tex]\sf{-4+3=-2- \dfrac{1}{5}\times-1 }[/tex]

[tex]\rm{Move \ the \ negative \ symbol \ to \ the \ left.}[/tex]

[tex]\sf{-4+3=-2-(-1) \ \ \to \ \ Simplify \ -4+3 \ to \ -1. }[/tex]

[tex]\sf{-1=-2-(-1) \ \ \to \ \ \to \ \ Remove \ parentheses. }[/tex]

[tex]\sf{-1=-2+1 \ \ \to \ \ Simplify \ -2+1 \ to \ -1.}[/tex]

[tex]\sf{-1=-1 \ \to \ Equality \ is \ met.}[/tex]

Checked ✅

[tex]\huge \red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}[/tex]

The first step for deriving the quadratic formula from the quadratic equation, 0 = ax2 + bx + c, is shown.

Step 1: –c = ax2 + bx

Answers

Answer:

The first step for deriving the quadratic formula from the quadratic equation, 0 = ax2 + bx + c, is shown.

[tex] \: first the formula of quadratic equation \: = - b ≠ \: \sqrt{ \frac{ \: {b }^{2} - 4ac}{ \: 2a} } [/tex]

let's begin to solve this equation,,,

[tex]ax² + bx + c = 0 \\

ax² + bx + c =0 \\ {x}^{2} + \frac{b}{a} \: + \frac{ {b}^{2} }{2a} = \frac{b2}{a} - \frac{c}{a}

\\ x + \frac{ {b}^{2} }{2a} = - \frac{ {b}^{2} }{2a} - \frac{c}{a} [/tex]

MORE BASIC INFORMATION

an equation having the maximum power of the variable equal to is called the quadratic equation the general form of quadratic equation is ax² + bx +c =0 where a,b,c are real numbers a ≠0 x is variable •

a quadratic equation can be solved by two method by factorization and by formula

by factorization a quadratic equation can be solved by factorization only when the product AC can be divided into two such part that it had the sum of the difference of the two part is equal to b

[tex]by the formula of quadratic equation can be solved by \ - } [/tex]

[tex]x = \frac{ - b \sqrt{ {b}^{2} - 4ac } }{2a } \\ root \: of \: equation \: {ax}^{2} + bx + c = 0 \\ - b - \sqrt{ \frac{ {b}^{2} - 4ac}{2a} } [/tex]

Interest earned or paid on the principal is ___ interest

Answers

Answer:

simple interest

Step-by-step explanation:

SI = principal x rate x time

Find the area of the shade regions. Give your answer as a completely simplify exact value in terms of pie(no approximation). a=

Answers

Answer:

125.6 in²

Step-by-step explanation:

Area shaded :

2 × Sector (72°)2 x πr² x θ/3602 x 3.14 x 100 x 72/3606.28 x 100 x 1/520 x 6.28125.6 in²

What similarity statement can you write relating the three triangles in the diagram?

Answers

Answer:

They are both right-angled triangles.

Step-by-step explanation:

If LogN= 3.8609, find the value of N, to the nearest integer

Answers

[tex]~~~~~~~\log_{10} N = 3.8609\\\\\\\implies N = 10^{3.8609} ~~~~~~~~~;[\log_b c =d \implies b^d = c]\\\\\\\implies N \approx 7259[/tex]

According to the graph, what is the value of the constant in the equation
below?

Answers

Answer:

A

Step-by-step explanation:

height (y-axis) = constant × width (x-axis)

let's look at the point coordinates.

remember, an ordered pair of point coordinates consists of an x value and an associated (typically calculated by a function) y value.

we see that all y values are half of the x values (3 and 1.5, 2 and 1, 7 and 3.5, 8 and 4).

so, the constant in our equation is responsible for returning half of the x value back as the y value.

what constant factor turns a number in half ?

x × c = x/2

c = 1/2

and so, A is the right answer.

Help please 50 PTS! I need this asap

Design your own statistical question that you can ask at least twenty different people. Keep in mind that the question should result in a variety of different numerical answers. What is your statistical question?

Answers

Answer:

How tall are you

ez clappp

Trying to solve this problem but I can’t

Answers

Answer:

option c I think as the correct answer.

Step-by-step explanation:

hope this helps you.

The answer is c
I hope you find this helpful

In this triangle, a = 6 cm, b = 8 cm, and c = 10 cm.

What is the area of this triangle?


24 cm²

30 cm²

40 cm²

48 cm²

Answers

Answer:

A) 24 cm²

Step-by-step explanation:

Area of a triangle formula:

A = 0.5bh

Given:

b = 6

h = 8

Work:

A = 0.5bh

A = 0.5(6)(8)

A = 3(8)

A = 24

[tex]\large{\underline{\underline{\pmb{\sf{\color{yellow}{Answer:}}}}}}[/tex]

Right answer is option A

24 cm²

Step-by-step explanation:

To find :-

The area of triangle

Given :-

a = 6 cm, b = 8 cm, c = 10 cm

Solution :-

He know

[tex] \mathfrak {Area \: of \: triangle = \frac{1}{2} \times base \times height}[/tex]

Here (a) acts like base

while (b) acts like height

Now substituting the values

[tex] \sf \longmapsto Area = \frac{1}{2} \times a \times b \\ \\ \\ \sf \longmapsto Area = \frac{1}{2} \times 6 \times 8 \\ \\ \\ \sf \longmapsto Area = 3 \times 8 \\ \\ \\ \sf \purple{\boxed {\longmapsto Area = 24 \: {cm}^{2} }}[/tex]

If a male student is selected at random, what is the probability the student is a freshman?

Answers

The probability that the student selected at random is a freshman is; 29%

How to find the Probability?

From the given table;

Total number of male students = 4 + 6 + 2 + 2 = 14

Number of freshmen students = 4 students

Thus;

Probability that the student selected at random is a freshman is;

P(Freshman | Male) = 4/14 * 100% = 28.57% ≈ 29%

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For an experiment comparing two treatment conditions, an independent-measures design would obtain ____ score(s) for each subject and a repeated-measures design would obtain ____ score(s) for each subject.

Answers

The score(s) that will be obtained respectively in an independent-measures design and repeated-measures design are; 1 and 2

How to interpret Experiments?

There are different ways to carry out an experiment in mathematics. This is because there are various means of research and also ways to interpret the results.

Now, when comparing two treatment conditions, an independent-measures design would always obtain 1 score for each subject. However, when a repeated-measures design is carried out on the same sample, it will obtain 2 scores.

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Fill in the blank to complete the formula that represents 2, 4, 8, 16,...

Answers

Answer:

I'm not 100% sure about this question but the formula to get that is

(x-1) x 2 =y

if you help me I will make you branliest

Answers

This exercise is about creating two-dimensional shapes. The resulting shape is a quadrilateral - Square. See the attached for the lines drawn.

What was noticed about the two lines drawn?

The two lines are drawn each had parallel pairs; andThey were perpendicular to one another.

What is the meaning of perpendicularity?

When two lines intersect with one another such that they create a right angle, perpendicularity has occurred and both lines are said to be perpendicular to one another.

Hence:

AB ⊥ BCBC ⊥ CDCD ⊥ DA; and DA ⊥ AB.

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que numero elevado al cubo me da 19648

Answers

Answer:

[tex]4\sqrt[3]{307}[/tex] o 26.98398684 en forma decimal

Step-by-step explanation:

evaluate and simplify the following complex fraction.:6/7 ÷ 3/11​

Answers

Answer:

3  7/50

Step-by-step explanation:

so you need them to become common denominators

a common multiple they both have would be is 77

6/7 becomes 66/77 and 3/11 becomes 21/77

now we divide

keep the 66/77 as is and flip 21/77 (keep, change, flip)

so now our equation looks like this: 66/77 x 77/21

and your answer is 3.14

but as a fraction it is 157/50 and to simplified it would be 3 7/50 (mixed fraction)

Just look at this and answer it right someone please how.

Answers

Answer:

they are 10km 32 degrees far from each other

Step-by-step explanation:

scott - 100km - 30 degrees

spork - 110km - 62 degrees

how far = difference between them

as spork's distance and degrees are greater than scott we substract Scott's from spork's

110 - 100 = 10 km

62 - 30 = 32 degrees

they are 10km 32 degrees far from each other

Find the ratio of the perimeter for the pair of similar two regular pentagons with areas 144 in² and 36 in²

Answers

The ratio between the perimeter of the largest and smallest pentagon is 2.

How to find the ratio between the perimeters?

We know that the pentagons are similar, meaning that the dimensions of one of the pentagons is k times the dimensions of the other.

Because of this, the ratio between the areas is k squared. And because the perimeter depends linearly on the dimensions, the ratio between the perimeters will be equal to k.

So we need to find k, we will have:

[tex]\frac{144 in^2}{36 in^2} = k^2 = 4\\\\k = \sqrt{4} = 2[/tex]

Then we conclude that the ratio between the perimeters is k  =2.

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Sun cover manufactures umbrellas for a monthly fixed cost of $675,921.00 and a
variable cost per umbrella of $42.15. determine the break-even sales price per umbrella if sun cover manufactures 8,573 umbrellas per month
$109.95
$114.50
$120.99
$131.25

Answers

The break-even sales price per umbrella if sun cover manufactures the units is $120.99.

How to calculate the sales price?

This can be done by using the formula:

Break even units = Total fixed cost / (Price - Variable cost)

8573 = 675921/(Price - 42.15)

8573(P - 42.15) = 675921

8573P - 361351.95 = 675921

8573P = 675921 + 361351.95

8573P = 1037273.4

P = 1037273.4/8574

P = $120.99

Therefore, the price is $120.99.

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In a group there are 3 boys and 4 girls. A child is selected from the group at random. Find the probability that the selected child is a boy. ​

Answers

Answer:

3/7

Step-by-step explanation:

Probability=Number of possible items÷Number of total items.

We will make the possible item 3 because we are looking for the probability whether a boy will be picked.

The number of total items will therefore be: the number of boys + the number of girls; that will be 3+4 =7.

So the probability of picking a boy will be 3/7

THANK YOU.

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