y=A + Cexp(-0.5x^2) is the general solution of the DEQ: y' + xy = 72x. Determine A. Is the DEQ separable, exact, 1st-order linear, Bernouli?

Answer:

The Degree of the polynomial is 3

The scenario that can be solved using a two-way data table out of the options provided is to display how the profit of a lemonade stand will change when the price per cup and the count per cup change.

A two-way data table is a useful tool for conducting sensitivity analysis and exploring how changing two input variables affects the output or result of a formula or calculation. In this case, the profit of a lemonade stand is the output variable, while the price per cup and the count per cup are the two input variables. By creating a two-way data table with different values for the price per cup and the count per cup, we can systematically analyze how these two factors impact the profit of the lemonade stand. Each combination of the price per cup and the count per cup will be evaluated, and the corresponding profit will be calculated. This analysis allows us to observe the relationship between the input variables (price per cup and count per cup) and the output variable (profit). We can identify the optimal price per cup and count per cup that maximize the profit or explore different scenarios to understand how changes in these variables affect the overall profitability of the lemonade stand. Therefore, the option "b. to display how the profit of a lemonade stand will change when the price per cup and the count per cup change" can be solved using a two-way data table.

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Using telescoping or iteration, the closed form for the recurrence relation c₂ = 2cn-1 - 1 with co = 2 is `cₙ = 2ⁿ+1 - 1` for `n ≥ 0`.

As the recurrence relation is `c₂ = 2cn-1 - 1` with `c₀ = 2`. In the closed form, first, we write out the first few terms of the sequence: `c₀ = 2, c₁ = 3, c₂ = 5, c₃ = 9, c₄ = 17, c₅ = 33, c₆ = 65, ...`

Let's try a pattern in the sequence. Observe that `c₁ = 2c₀ + 1 = 2(2) + 1 = 5`. Similarly, `c₂ = 2c₁ + 1 = 2(5) + 1 = 11`. Continuing this process, we can see that `cₙ = 2cₙ₋₁ + 1` for `n ≥ 1`.

Let's apply telescoping to this formula:```
c₁ = 2c₀ + 1c₂ = 2c₁ + 1= 2(2c₀ + 1) + 1

= 2²c₀ + 2 + 1c₃ = 2c₂ + 1

= 2(2²c₀ + 2 + 1) + 1

= 2³c₀ + 2² + 2 + 1c₄

= 2c₃ + 1= 2(2³c₀ + 2² + 2 + 1) + 1

= 2⁴c₀ + 2³ + 2² + 2 + 1

```Note that each term in this sum telescopes. In general, we can write `cₙ = 2ⁿc₀ + 2ⁿ-1 + ... + 2² + 2 + 1`. Simplifying this expression gives:```
cₙ = 2ⁿc₀ + (2ⁿ - 1)
= 2ⁿ(2) + (2ⁿ - 1)
= 2ⁿ+1 - 1 ```

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Answer:

First row of blanks: -3 -3

Second row of blanks: 2 2 3

Third row blank: 6

Step-by-step explanation:

x/2 + 3 = 6

The objective is to isolate the variable:

Subtract both sides by 3

x/2 = 3

Multiply both sides by 2

x = 6

Answer:

1. y=2x^2-8X-1

2. y=-6x^2+36x-63

3. y=-3x^2+18x-34

4. y=9x^2+54x+76

5. y=-x^2+8x-22

6. y=6x^2-48x+90

7. y=8x^2+16x+5

8. y=2x^2-8x+1

Have a great day :)

Answer:

The probability that Scott will wash is 2.5

Step-by-step explanation:

Given

Let the events be: P = Purple and G = Green

[tex]P = 2[/tex]

[tex]G = 3[/tex]

Required

The probability of Scott washing the dishes

If Scott washes the dishes, then it means he picks two spoons of the same color handle.

So, we have to calculate the probability of picking the same handle. i.e.

[tex]P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)[/tex]

This gives:

[tex]P(G_1\ and\ G_2) = P(G_1) * P(G_2)[/tex]

[tex]P(G_1\ and\ G_2) = \frac{n(G)}{Total} * \frac{n(G)-1}{Total - 1}[/tex]

[tex]P(G_1\ and\ G_2) = \frac{3}{5} * \frac{3-1}{5- 1}[/tex]

[tex]P(G_1\ and\ G_2) = \frac{3}{5} * \frac{2}{4}[/tex]

[tex]P(G_1\ and\ G_2) = \frac{3}{10}[/tex]

[tex]P(P_1\ and\ P_2) = P(P_1) * P(P_2)[/tex]

[tex]P(P_1\ and\ P_2) = \frac{n(P)}{Total} * \frac{n(P)-1}{Total - 1}[/tex]

[tex]P(P_1\ and\ P_2) = \frac{2}{5} * \frac{2-1}{5- 1}[/tex]

[tex]P(P_1\ and\ P_2) = \frac{2}{5} * \frac{1}{4}[/tex]

[tex]P(P_1\ and\ P_2) = \frac{1}{10}[/tex]

Note that: 1 is subtracted because it is a probability without replacement

So, we have:

[tex]P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)[/tex]

[tex]P(Same) = \frac{3}{10} + \frac{1}{10}[/tex]

[tex]P(Same) = \frac{3+1}{10}[/tex]

[tex]P(Same) = \frac{4}{10}[/tex]

[tex]P(Same) = \frac{2}{5}[/tex]

Answer:

Step-by-step explanation:

The two inside angles will sum to 180°.

The top to angles are equal.  

Think about this as what if both of the parallel lines were intersected by a perpendicuar line.  Every angle would be a right triangle 90°.  The inside angles will sum to 180° and the opposite angles are again equal.

 (2x + 18) + (8x + 12) = 180

          10x +   30   =   180

                   10x    =   150

                      x  =  15

-------------------------

             (3y - 18)  =  (8x + 12)       x = 15

            (3y - 18)  =  (8(15) + 12)

            (3y - 18)  =  (120 + 12)

            (3y - 18)  =  132

                   3y   =   132 + 18

                   3y   =  150

                     y   =  50

Answer:5.7

Step-by-step explanation:

The tangent or tanθ in a right angle triangle is the ratio of its perpendicular to its base. The distance between the point Q and the ground is h-[L cos(80°)].

The tangent or tanθ in a right angle triangle is the ratio of its perpendicular to its base. it is given as,

[tex]\rm Tangent(\theta) = \dfrac{Perpendicular}{Base}[/tex]

where,

θ is the angle,

Perpendicular is the side of the triangle opposite to the angle θ,

The Base is the adjacent smaller side of the angle θ.

Let the height of the support be h and the height between the point q and the ground is x. Also, the distance between point Q and the support of the seesaw is L.

Now if we look at the ΔQAR, the measure of the ∠QRA is 80°, therefore, the sine of ∠QRA can be written as,

[tex]\rm Cos(\theta)=\dfrac{Base}{Perpendicular}\\\\Cos(\angle QRA) = \dfrac{AR}{QR}\\\\Cos(\angle QRA) = \dfrac{h-x}{L}\\\\L \times Cos(80^o)=h-x\\\\x=h-[L\ Cos(80^o)][/tex]

Hence, the distance between the point Q and the ground is h-[L cos(80°)].

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The best-fit quadratic model is given by the equation y = -0.19378x² - 0.15265x + 31.0148, where x represents the year after 1900.

According to the best-fit quadratic model obtained from the data, approximately 14,000 families will live in Sunnyvale in 2015.

To estimate the number of families in 2015, we substitute x = 115 (2015 - 1900) into the quadratic model:

y = -0.19378(115)² - 0.15265(115) + 31.0148

≈ 14,000

Therefore, based on the best-fit quadratic model, it is estimated that approximately 14,000 families will live in Sunnyvale in 2015. The model is obtained by performing a quadratic regression using the given data points, and it provides a reasonable estimate for the number of families in 2015 based on the trend observed in the data.

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The solution to the inequality y < 43.5 can be graphed on a number line. The graph will show all the values of y that are less than 43.5.

To graph the solution to the inequality y < 43.5 on a number line, we start by marking the point 43.5 on the number line. Since the inequality is y < 43.5, we represent it with an open circle at 43.5 to indicate that 43.5 itself is not included in the solution.

Next, we shade the region to the left of the open circle. This shaded region represents all the values of y that are less than 43.5, including any negative values and values approaching negative infinity.

The resulting graph on the number line will show a shaded region to the left of the open circle at 43.5, indicating that all values of y in that region satisfy the inequality y < 43.5.

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Answer:

D<28

Step-by-step explanation:

The required inequality for the given situation can be, d > 28 or d < 28

A relationship between two expressions or values that are not equal to each other is called inequality.

Given that, write an inequality for the situation.

Situation :-

A number of days, d, of sunshine is not 28.

Here, the number of days is said to be not equal to 28, we are not given if is less or more,

It can be less or more than 28 but not 28

So, here we get two situations,

Either, the number of days, d, of sunshine is less than 28, or the number of days, d, of sunshine is more than 28.

If we write these situations, mathematically, the inequalities we will have, are :-

1) The number of days, d, of sunshine is less than 28 :-

d < 28

2) The number of days, d, of sunshine is more than 28 :-

d > 28

Therefore, the two inequalities, are :- d < 28 or d > 28

Hence, the required inequality for the given situation can be, d > 28 or d < 28

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The complete question is :-

Write an inequality for the situation.

A number of days, d, of sunshine is not 28 .

Answer:

mhmm feels so good

Step-by-step explanation:

Answer: + 1000

Step-by-step explanation:

Answer: 4

Step-by-step explanation: 13.6 divided by 3.4 = 136 then divide by 34 you get 34 from 3.4 but divide by 34. Once you divide 136 and 34 you get your answer 4.

Answer:

5 :12 ; what is the ratio of the number of gumamela to the total number of flowers

5 : 7 ; what is the ratio of the number of gumamela to the number of orchids

7:5 ; what is the ratio of the number of orchids to the number of gumamela

12 : 5 ; what is the ratio of the total number of flowers to the number of gumamela

12 : 7 ; what is the ratio of the total number of flowers to the number of orchid

Step-by-step explanation:

Ratios of a to b ;is written as a : b

Ratio of b to a is written as b : a

The ratio of a to the sum of a and b equals ;

a : (a + b)

Number of orchids = 7

Number of gumamela = 5

Total number of flowers = 7 + 5 = 12

Ratio two quantities are compared. A number of times a number contains another. It makes value comparisons. When two components of the same unit are compared, it is possible to determine how much of one number is represented in the other. The quotient of two mathematical equations is shown.

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Answer:

Step-by-step explanation:

x = 9

Answer:

61

Step-by-step explanation:

all angles that are in a triangle add up to 180

x+80+39=180

x+119=180

x=61

Hope that helps :)

If the probabilities of their outcomes are 20%, 60%, and 20% respectively, the expected value of these outcomes is $346.

To calculate the expected value of the outcomes, we multiply each outcome by its corresponding probability and then sum up the results.

In this case, the projected outcomes are $240, $310, and $560, with probabilities of 20%, 60%, and 20% respectively.

To calculate the expected value, we use the formula:

Expected value = (Outcome 1 * Probability 1) + (Outcome 2 * Probability 2) + (Outcome 3 * Probability 3) + ...

Expected value = ($240 * 0.20) + ($310 * 0.60) + ($560 * 0.20)

Expected value = $48 + $186 + $112

Expected value = $346

The expected value represents the average value or the long-term average outcome we can expect from the given probabilities and outcomes. It provides a summary measure that helps in understanding the central tendency of the distribution of outcomes.

In this case, the expected value indicates that, on average, we can expect the project's outcome to be around $346.

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Answer:

D

i thank

Step-by-step explanation:

The present value needed to accumulate $150,000 after 6 years with a 2% interest rate compounded quarterly is $131,488

To calculate the present value needed to accumulate $150,000 after 6 years with a 2% interest rate compounded quarterly, we can use the formula for compound interest:

Present Value = Future Value / (1 + r/n)^(n*t)

Where:

Future Value = $150,000

Interest Rate (r) = 2% = 0.02 (converted to decimal)

Number of Compounding Periods per Year (n) = 4 (quarterly compounding)

Number of Years (t) = 6

Substituting these values into the formula, we have:

Present Value = $150,000 / (1 + 0.02/4)^(4*6)

Calculating inside the parentheses first:

Present Value = $150,000 / (1 + 0.005)^(24)

Next, calculate the exponent:

Present Value = $150,000 / (1.005)^(24)

Using a calculator or spreadsheet, we can evaluate the expression inside the parentheses and then divide $150,000 by that result to find the present value. Rounding to the nearest dollar, the present value needed is $131,488.

Therefore, the amount to be invested now or the present value needed is $131,488.

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Bill should eat 4 cups of rice, 4 cups of tofu, and 4 cups of peanuts to meet his specific nutritional goals.

To determine how many cups of rice, tofu, and peanuts Bill should eat, we need to set up a system of equations based on the given nutritional information. Let's denote the number of cups of rice, tofu, and peanuts as x, y, and z respectively.

Based on the given information, we can establish the following equations

Carbohydrate equation: 46x + 6y + 26z = 312

Fat equation: 0x + 12y + 70z = 328

Protein equation: 2x + 15y + 28z = 180

We now have a system of three equations that we can solve to find the values of x, y, and z.

Using any appropriate method to solve the system of equations, we find

12y + 70z = 328

y = 328 - 70z/12

y = 27.33 - 5.833z

putting the value of y in both equation

2x + 15(27.33 - 5.833z ) + 28z = 180

2x + 28z + 409.95 - 87.45z = 180

(2x - 59.45z = -391.95)23

46x  - 1367.35z = - 9014.85

46x + 6(27.33 - 5.833z) + 26z = 312

46x + 163.98 - 34.998z + 26z = 312

46x - 8.998z = 148.02

equation both equation

- 8.998z + 1367.35z = 9014.85 + 148.02

z = 9162.87/1358.352

z ≈ 4

Solving equation we get

x = 4 cups of rice

y = 4 cups of tofu

z = 4 cups of peanuts

Therefore, Bill should eat 4 cups of rice, 4 cups of tofu, and 4 cups of peanuts to meet his nutritional goals.

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Answer:

Step-by-step explanation: 675 ssa SAS 342w

Answer:

283 1/3 pizzas

Step-by-step explanation:

I did 3,400 div 12 = 1,420

The given function is f(x) = x/(x^2 + 25).

Intercepts:

To find the intercepts, we set f(x) = 0 and solve for x. However, in this case, the function does not have any x-intercepts because the numerator x cannot be zero.

The y-intercept occurs when x = 0. Substituting x = 0 into the function, we have f(0) = 0/(0^2 + 25) = 0.

Relative Extrema:

To find the relative extrema, we take the derivative of the function and find the critical points where the derivative is zero or undefined. However, in this case, the function does not have any relative extrema because its derivative is always nonzero and defined for all x.

Points of Inflection:

To find the points of inflection, we need to analyze the second derivative of the function. However, in this case, the second derivative is always zero, indicating that there are no points of inflection.

Asymptotes:

The function has two asymptotes: a vertical asymptote and a horizontal asymptote.

The vertical asymptote occurs when the denominator of the function is equal to zero. Solving x^2 + 25 = 0, we find that there are no real solutions. Therefore, there is no vertical asymptote.

The horizontal asymptote can be found by examining the behavior of the function as x approaches positive or negative infinity. As x approaches positive or negative infinity, the function approaches zero. Hence, the horizontal asymptote is y = 0.

To verify these results, a graphing utility can be used to plot the function and visualize its behavior.

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Yes, it is possible to fill all twenty mugs.

a) To solve the recurrence relation an = an-1 + 3(n-1), a0 = 1, we can expand the recurrence relation iteratively.

a1 = a0 + 3(1-1) = 1 + 0 = 1

a2 = a1 + 3(2-1) = 1 + 3 = 4

a3 = a2 + 3(3-1) = 4 + 6 = 10

a4 = a3 + 3(4-1) = 10 + 9 = 19

...

We can observe a pattern from the values:

a0 = 1

a1 = 1

a2 = 4

a3 = 10

a4 = 19

We can notice that an = [tex]n^2 + 1.[/tex] We can prove this by induction, but in this case, we can also recognize that the given recurrence relation generates the triangular numbers (1, 3, 6, 10, 15, ...), which are defined by the formula Tn = n(n+1)/2.

Thus, the solution to the recurrence relation is an = [tex]n^2 + 1.[/tex]

b) For the recurrence relation an = an-1 + n(n-1), a0 = 3, we can again expand it iteratively:

a1 = a0 + 1(1-1) = 3 + 0 = 3

a2 = a1 + 2(2-1) = 3 + 2 = 5

a3 = a2 + 3(3-1) = 5 + 6 = 11

a4 = a3 + 4(4-1) = 11 + 12 = 23

...

Observing the values, we can notice that an =[tex]n(n^2 + 1).[/tex]

Thus, the solution to the recurrence relation is an = [tex]n(n^2 + 1).[/tex]

c) For the recurrence relation an = an-1 +[tex]3n^2[/tex], a0 = 10, we expand it iteratively:

a1 = a0 + [tex]3(1^2)[/tex] = 10 + 3 = 13

a2 = a1 + [tex]3(2^2) =[/tex] 13 + 12 = 25

a3 = a2 + [tex]3(3^2)[/tex]= 25 + 27 = 52

a4 = a3 + [tex]3(4^2)[/tex]= 52 + 48 = 100

...

We can notice that an = [tex]n^3 + 10.[/tex]

Thus, the solution to the recurrence relation is an = [tex]n^3 + 10.[/tex]

These are the solutions to the given recurrence relations.

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Answer:

D

Step-by-step explanation:

Answer: The 3rd one is the correct answer

Step-by-step explanation: