help i need this to be answerd

Answer:

6, 8 and 10  and  -2, 0, 2

There are two roots x = -2 and 6,    

but the since I don't believe 0 is an even number the answer is 6, 8 and 10

I was incorrect according to G0ggle zero is an even number so another answer is  -2, 0, 2

Step-by-step explanation:

read the question and convert the English to mathematics

x, y and z    even consecutive number

y = x+2

z = y+2 = x+4

and

xyz = x³ + y² + 2z²                                   substitiute x terms  in for y and z

x(x+2)(x+4)  = x³ + (x+2)² + 2(x+4)²           solve for x by graphing on DEMOS

                                                                 x = -2, 6  solved algebraically below

x = -2   y=0   z=2

x = 6    y=8   z=10

Checked both answers

xyz = x³ + y² + 2z²

-2(0)2 = -8 + 0 + 8                  when x = -2

   0   =  0

and

6(8)(10)  =  6³ + 8² +2(10)²      when x = 6

   480   =  216+64+200

             =  480

x(x+2)(x+4)  = x³ + (x+2)² + 2(x+4)²                           solved algebraically

(x²+2x)(x+4)   = x³ + x² +4x +4 + 2x² + 16x + 32

x³ + 6x² + 8x = x³ + x² +4x +4 + 2x² + 16x + 32

x³ + 6x² + 8x = x³ + 3x² + 20x + 36

      3x² - 12x - 36 = 0         factor out the 3

      3[x² - 4x - 12] = 0

       3(x+2)(x-6) = 0     x = -2 and -12

There is insufficient evidence to support the claim that the training technique is effective in raising the gymnasts scores.

In hypothesis testing, we often use significance levels such as 0.01 to determine whether or not there is enough evidence to support the hypothesis.

Here is the solution to the given problem.

The null hypothesis is that the training technique is not effective in raising the gymnasts' scores.

It is expressed as

H0: µd = 0.

The alternative hypothesis is that the technique is effective in raising the gymnasts' scores.

It is expressed as

Ha: µd > 0.

The significance level α = 0.01 is given.

Therefore, the given problem can be tested using a one-tailed t-test.

This is because the alternative hypothesis states that the mean difference between the two populations is greater than zero.

A t-test is appropriate because the sample sizes are less than 30.

The difference between the before and after competition scores of each gymnast should be calculated.

This gives us the difference scores, which are as follows:

0.1, 0.2, -0.02, -0.1, 0.1, 0.3, -0.2.

Next, we compute the mean and standard deviation of the differences. We have:

n = 7d

= 0.0714Sd

= 0.1466

Then we compute the t-statistic:

t = (d - µd) / (Sd / √n)

t = (0.0714 - 0) / (0.1466 / √7)

t = 1.5184

The degrees of freedom for this test are (n - 1) = 6.

Using a t-distribution table with 6 degrees of freedom and a significance level of 0.01 for a one-tailed test, we find that the critical t-value is 2.998.

For the given problem, the test statistic t = 1.5184 is less than the critical value of 2.998.

Therefore, we do not reject the null hypothesis.

There is insufficient evidence to support the claim that the training technique is effective in raising the gymnast scores.

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Answer:

53.8 gallons

Step-by-step explanation:

5.4*3=16.2

5.4 (gallons used per shower) * 3 (number of showers) = 16.2 (gallons used in 3 showers)

70-16.2=53.8

70 (Water in tank) - 16.2 (gallons used in 3 showers) = 53.8 (gallons of water left)

Hope this helps! Please brainliest!!!

Answer:

A(3) = 53.8 gallons left after 3 showers

Step-by-step explanation:

A(x) = volume of water left in tank = 70 gallons - (5.4 gallons)x, where x is the number of showers already taken.  

After  3 showers, the volume of water left is A(3) = 70 gal - (5.4 gallons)(3), or

A(3) = 53.8 gallons left after 3 showers

To approximate the sum of the series [infinity] (−1)n−1n^2/(8n), we can use a numerical method such as the partial sum method.

Let's calculate the partial sums of the series and add up terms until the sum converges to a desired level of accuracy. We will stop adding terms once the absolute difference between two consecutive partial sums is less than the desired accuracy.

Let's start by calculating the partial sums:

S_1 = (-1)^1-1(1^2)/(81) = 1/8

S_2 = (-1)^2-1(1^2)/(82) + (-1)^1-1(2^2)/(82) = 1/8 - 1/16 = 1/16

S_3 = (-1)^3-1(1^2)/(83) + (-1)^2-1(2^2)/(83) + (-1)^1-1(3^2)/(83) = 1/8 - 1/16 - 1/24 = -1/24

We can observe that the partial sums alternate between positive and negative values. This indicates that the series does not converge to a specific value but oscillates between two values.

To approximate the sum, we will calculate partial sums until the difference between two consecutive partial sums is less than the desired accuracy. Let's say we want the accuracy to be 0.0001.

Let's continue calculating partial sums:

S_4 = (-1)^4-1(1^2)/(84) + (-1)^3-1(2^2)/(84) + (-1)^2-1(3^2)/(84) + (-1)^1-1(4^2)/(84) = 1/8 - 1/16 - 1/24 + 1/32 = -1/48

S_5 = (-1)^5-1(1^2)/(85) + (-1)^4-1(2^2)/(85) + (-1)^3-1(3^2)/(85) + (-1)^2-1(4^2)/(85) + (-1)^1-1(5^2)/(8*5) = 1/8 - 1/16 - 1/24 + 1/32 + 1/40 = 1/120

The difference between S_4 and S_5 is 1/120 - (-1/48) = 1/120 + 1/48 = 1/80, which is greater than 0.0001.

Therefore, we can approximate the sum of the series as -1/48, correct to four decimal places.

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Answer:

Q2. angle 5 +angle 6=90°

angle 5+ 6°=90°

angle 5=90°-6°

angle 5=84°

Q.3 angle 8+angle 9=90°

angle 8 + 11°=90°

angle 8=90°-11°

angle 8=79°

Answer:

(1.5, -4)

Step-by-step explanation:

( -1, -5) and (4, -3)

[tex](\frac{-1+4}{2} ,\frac{-5-3}{2} )\\\\(\frac{3}{2} ,\frac{-8}{2} )\\\\(1.5,-4)[/tex]

Answer:

I don't think so .... :(((

Answer:

area of triangle =1/2 p×b=1/2×4×3=6unit²

Answer:

35

Step-by-step explanation:

subtract highest and lowest numbers

Answer:

c

Step-by-step explanation:

it passes vertical line test and is linear

Answer:

C

Step-by-step explanation:

The answer is C. Hoped it helped.

Answer:

The question needs more information but you can see that all the numbers in the 1st column are multiplied by 6 to equal the number in column 2

Step-by-step explanation:

3 x6 =18

6 x 6= 36

9 x6= 54

12 x6 =72

The third-degree Maclaurin polynomial for f(x) = sin(x) is P3(x) = x - (x^3) / 6.

To find the nth Maclaurin polynomial for the function f(x) = sin(x) when n = 3, we need to compute the polynomial up to the third-degree term.

The Maclaurin polynomial for a function f(x) centered at x = 0 is given by the formula:

Pn(x) = f(0) + f'(0)x + (f''(0)x^2) / 2! + (f'''(0)x^3) / 3! + ...

Let's calculate the nth Maclaurin polynomial for f(x) = sin(x) when n = 3:

First, we find the values of the function and its derivatives at x = 0:

f(0) = sin(0) = 0

f'(x) = cos(x), so f'(0) = cos(0) = 1

f''(x) = -sin(x), so f''(0) = -sin(0) = 0

f'''(x) = -cos(x), so f'''(0) = -cos(0) = -1

Using these values, we can write the Maclaurin polynomial:

P3(x) = 0 + 1x + (0x^2) / 2! + (-1x^3) / 3!

Simplifying further, we have:

P3(x) = x - (x^3) / 6.

Therefore, the third-degree Maclaurin polynomial for f(x) = sin(x) is:

P3(x) = x - (x^3) / 6.

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The given parabola is a downward-opening parabola, its directrix is y = -1/2, and its focus is located at (0, -1/2).

The parabola represented by the equation [tex]-2y^2 = 4x[/tex] is a downward-opening parabola.

To understand the direction of the parabola, we can look at the coefficient of the [tex]y^2[/tex] term in the equation. Since it is negative (-2), the parabola opens downwards. If the coefficient were positive, the parabola would open upwards.

The equation of the directrix of a parabola can be determined by rearranging the given equation to the standard form, which is [tex](y - k)^2 = 4p(x - h)[/tex], where (h, k) represents the vertex of the parabola and p represents the distance between the vertex and the focus.

In the given equation, [tex]-2y^2 = 4x[/tex], we can divide both sides by -2 to obtain [tex]y^2 = -2x[/tex]. Comparing this to the standard form, we can see that the vertex is at (0, 0) since h = 0 and k = 0.

The coefficient of x in the standard form equation is 4p. Therefore, in our equation, 4p = -2, which implies p = -1/2.

Since p is negative, the directrix will be a horizontal line parallel to the x-axis and situated below the vertex. The equation of the directrix can be written as y = -1/2.

The focus of the parabola can be found by adding p to the y-coordinate of the vertex. In this case, since the vertex is at (0, 0) and p = -1/2, the focus will be at (0, -1/2).

In summary, the parabola represented by [tex]-2y^2 = 4x[/tex] is a downward-opening parabola. The equation of the directrix is y = -1/2, and the focus is located at (0, -1/2).

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Answer:

586.76

Step-by-step explanation:

Take the area of the rectangular prism = 348

Find the area of the cylinder = 477.52

Divide the cylinder by 2 = 238.76

Add both together = 586.76

A Möbius transformation is a transformation of the form f(z) = (az+b)/(cz+d), where a, b, c, and d are complex numbers and ad-bc ≠ 0. The complex number z maps to f(z).

To find the Möbius transformation f such that f(0) = 0, f(1) = 1, f([infinity]) = 2, we follow these steps:

Step 1: Map 0 to 0 We need to map 0 to 0, so we set f(0) = 0. So, we get 0 = (a(0) + b) / (c(0) + d). This gives us b = 0. Step 2: Map infinity to 2We need to map [infinity] to 2, so we set f([infinity]) = 2. So, we get 2 = (a[infinity] + b) / (c[infinity] + d). This gives us a/c = 2/d. Cross-multiplying the terms, we get ad = 2c.

Let us assume that d = 1, then we have a = 2c.

We can substitute this value of a in the Möbius transformation, and we get f(z) = (2cz) / (cz + 1).Step 3: Map 1 to 1To map 1 to 1, we evaluate the Möbius transformation at z = 1. We get f(1) = (2c) / (c + 1) = 1.

Solving this, we get c = -1/2. Therefore, the Möbius transformation is f(z) = (2z) / (z - 2).

Hence, we have found the required Möbius transformation f(z) = (2z) / (z - 2) such that f(0) = 0, f(1) = 1, and f([infinity]) = 2.

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The eigenvalues of the given matrix A are 1, 2, and -2.

To find the eigenvalues of the matrix A:

A = [1 0 0]

[0 -4]

[0 4]

To find the eigenvalues, we need to solve the characteristic equation |A - λI| = 0, where λ is the eigenvalue and I is the identity matrix.

The matrix A - λI is:

A - λI = [1 - λ 0]

[0 -4]

[0 4 - λ]

Taking the determinant of A - λI:

|A - λI| = (1 - λ)(-4 - λ(4 - λ))

Expanding the determinant and setting it equal to zero:

(1 - λ)(-4 - λ(4 - λ)) = 0

Simplifying the equation:

(1 - λ)(-4 - 4λ + λ²) = 0

Now, we can solve for λ by setting each factor equal to zero:

1 - λ = 0 or -4 - 4λ + λ² = 0

Solving the first equation, we get:

λ = 1

Solving the second equation, we can factorize it:

(λ - 2)(λ + 2) = 0

From this equation, we get two additional eigenvalues:

λ = 2 or λ = -2

Therefore, the eigenvalues are 1, 2, and -2.

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Answer:

995.26

Step-by-step explanation:

I'm not sure but this is what I got

Complete Question

Find the circumference of the pizza to the nearest hundredth.

When Diameter = 18 in.

Answer:

56.55 inches

Step-by-step explanation:

A pizza is circular in shape.

The formula for the circumference of a circle is given as:

πD

Where D = Diameter

From the above question,

Diameter = 18 inches

Hence,

Circumference of the circular pizza = π × 18 inches

= 56.548667765 inches

Approximately = 56.55 inches

Answer:

8 cups of potatoes are needed

Step-by-step explanation:

One way of doing this work is to write out

1/4 cup                                             1 cup

------------- , which is equivalent to  ------------ (a unit rate)

 1 bowl                                              4 bowl

and then multiply this unit rate by 32 bowls:

(1/4)(32 bowls) = 8 cups of potatoes are needed

Answer:

2 + 1 = 3

Step-by-step explanation:

According to the scenario, computation of the given data are as follows,

Berverly already has = 2 pens

Berverly bought = 1 pen

Then to show this situation in numerical expression, we have to add both values, then

= 2 + 1 = 3

Hence, this shows that the total number of pens Berverly has after buying is 3.

Answer:

I would expect Emmy to get 8 hits in her next 16 tosses.

Emmy is to get 8 hits in her next 16 tosses.

Probability is defined as the ratio of the number of favourable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

Probability = Number of favourable outcomes / Number of samples

Given that Emmy is tossing bean bags at a target. She hit the target on 9 out of her last 18 tries. Considering this data.

The probability is,

P = 9 / 18

P = 0.5

The expected number of the hits on the target in 16 tosses will be;-

Number = 16 x 0.5

Number = 8

Therefore, Emmy is to get 8 hits in her next 16 tosses.

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Answer:

(2x+7)(x+7)

Step-by-step explanation:

Answer:

96730322328

Step-by-step explanation:

I hope this helps

Answer:

B. Sam should buy the jacket at Coats 'R Us because it is cheaper after the discount

Answer:

I suggest that sum should buy the jacket at coats 'R us because it is still cheaper after the discount even when you've not counted the discount in it is still cheaper than the other one and the other one even when it has such a high discount it is still not cheap so I suggest that the answer is choice B

Answer:

I can't able to understand this question plz check this question if it is right or not

Answer:

y=3x^2-6x+3

Step-by-step explanation:

Answer:

51

Step-by-step explanation:

mode is the value which appears the most than other values. In this case 51 will appear 3 times.

Answer:

5.1

Step-by-step explanation:

dont forget the decimal

Given that (xn) and (yn) are Cauchy sequences, then for any ε > 0, there exist N1 and N2 such that |xn - xm| < ε/2, for all n, m ≥ N1 and |yn - ym| < ε/2, for all n, m ≥ N2. Then, for all n, m ≥ max{N1, N2},

we have: |xnyn - xmym| = |xnym - xmym + xmym - xnym| ≤ |xn - xm||ym| + |ym - yn||xm| ≤ |xn - xm|ε/2 + |ym - yn|ε/2 < εThis shows that (xnyn) is a Cauchy sequence.

Moreover, for any ε > 0, there exists N such that |xn - xm| < ε/2 and |yn - ym| < ε/(2max{|x1|, |x2|, . . . , |y1|, |y2|, . . . , |yn|}) for all n, m ≥ N. Then, for all n, m ≥ N,

we have: |xnyn - xmym| = |xnym - xmym + xmym - xnym| ≤ |xn - xm||ym| + |ym - yn||xm| + |ym - yn||yn| ≤ |xn - xm|ε/(2max{|x1|, |x2|, . . . , |yn|}) + |ym - yn|ε/(2max{|x1|, |x2|, . . . , |yn|}) + |yn|ε/(2max{|x1|, |x2|, . . . , |yn|}) < ε.

This shows that (xn)(yn) is also a Cauchy sequence.

Therefore, from the given definition, it has been shown that if (xn) and (yn) are Cauchy sequences, then (xn) (yn) and (xnyn) are Cauchy sequences.

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