HELP PLEASE I DONT GET THIS

so the idea being, we have a system of equations of two variables and 4 equations, each one rendering a line, for this case these aren't equations per se, they're INEquations, so pretty much the function will be the same for an equation but we'll use > or < instead of =, but fairly the function is basically the same, the behaviour differs a bit.

we have a line passing through (-6,0) and (0,8), side one

we have a line passing through the x-axis and -6, namely (-6,0) and the y-axis and -4, namely (0,-4), side two

we have a line passing through (0,-4) and (6,4), side three

now, side four is simply the line connecting one and three.

the intersection of all four lines looks like the one in the picture below, so what are those lines with their shading producing that quadrilateral?

well, we have two points for all four, and that's all we need to get the equation of a line, once we get the equation, with its shading like that in the picture, we'll make it an inequality.

[tex](\stackrel{x_1}{-6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{8}-\stackrel{y1}{0}}}{\underset{\textit{\large run}} {\underset{x_2}{0}-\underset{x_1}{(-6)}}} \implies \cfrac{8 -0}{0 +6} \implies \cfrac{ 8 }{ 6 } \implies \cfrac{4}{3}[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{ \cfrac{4}{3}}(x-\stackrel{x_1}{(-6)}) \implies y -0 = \cfrac{4}{3} ( x +6) \\\\\\ y=\cfrac{4}{3}x+8\hspace{5em}\stackrel{\textit{side one} }{\boxed{y < \cfrac{4}{3}x+8}}[/tex]

[tex]\rule{34em}{0.25pt}\\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{-4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-4}-\stackrel{y1}{0}}}{\underset{\textit{\large run}} {\underset{x_2}{0}-\underset{x_1}{(-6)}}} \implies \cfrac{-4 -0}{0 +6} \implies \cfrac{ -4 }{ 6 } \implies - \cfrac{2}{3}[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{- \cfrac{2}{3}}(x-\stackrel{x_1}{(-6)}) \implies y -0 = - \cfrac{2}{3} ( x +6) \\\\\\ y=-\cfrac{2}{3}x-4\hspace{5em}\stackrel{\textit{side two} }{\boxed{y > -\cfrac{2}{3}x-4}} \\\\[-0.35em] \rule{34em}{0.25pt}[/tex]

[tex]\stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{4}-\stackrel{y1}{(-4)}}}{\underset{\textit{\large run}} {\underset{x_2}{6}-\underset{x_1}{0}}} \implies \cfrac{4 +4}{6 -0} \implies \cfrac{ 8 }{ 6 } \implies \cfrac{4}{3}[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-4)}=\stackrel{m}{ \cfrac{4}{3}}(x-\stackrel{x_1}{0}) \implies y +4 = \cfrac{4}{3} ( x -0) \\\\\\ y=\cfrac{4}{3}x-4\hspace{5em}\stackrel{ \textit{side three} }{\boxed{y > \cfrac{4}{3}x-4}} \\\\[-0.35em] \rule{34em}{0.25pt}[/tex]

[tex](\stackrel{x_1}{6}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{8}) ~\hfill~ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{8}-\stackrel{y1}{4}}}{\underset{\textit{\large run}} {\underset{x_2}{0}-\underset{x_1}{6}}} \implies \cfrac{ 4 }{ -6 } \implies - \cfrac{2}{3}[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{- \cfrac{2}{3}}(x-\stackrel{x_1}{6}) \\\\\\ y=-\cfrac{2}{3}x+8\hspace{5em}\stackrel{ \textit{side four} }{\boxed{y < -\cfrac{2}{3}x+8}}[/tex]

now, we can make that quadrilateral a trapezoid by simply moving one point for "side four", say we change the point (0 , 8) and in essence slide it down over the line to  (-3 , 4).  Notice, all we did was slide it down the line of side one, that means the equation for side one never changed and thus its inequality is the same function.

now, with the new points for side for of (-3,4) and (6,4), let's rewrite its inequality

[tex](\stackrel{x_1}{-3}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{4}-\stackrel{y1}{4}}}{\underset{\textit{\large run}} {\underset{x_2}{6}-\underset{x_1}{(-3)}}} \implies \cfrac{4 -4}{6 +3} \implies \cfrac{ 0 }{ 9 } \implies 0[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{ 0}(x-\stackrel{x_1}{(-3)}) \implies y -4 = 0 ( x +3) \\\\\\ y=4\hspace{5em}\stackrel{ \textit{side four changed} }{\boxed{y < 4}}[/tex]

what is the gcf of the term -15y^4+12y^2-9y​

please solve and include an explanation!!!

the three cubes shown weigh 12 ounces how many pounds would 24 cubes weigh A. 4.5 lb B. 6lb C. 18lb D. 72lb

4.01 ESSENTIAL QUESTIONS
How do you use the distance formula and slope formula to classify a
quadrilateral?
How do you use the distance formula and slope formula to classify a triangle?
How do you use the distance formula and slope formula to prove properties of
polygons?

4.02 ESSENTIAL QUESTIONS
How do you use the slope to prove lines are parallel or perpendicular?
How do you write an equation of a line so that it is parallel or perpendicular to a
given point?
How do you use parallel and perpendicular lines to solve real-world problems?
4.03 ESSENTIAL QUESTIONS
How do you divide a segment into given ratios?

How do you use coordinates to find the perimeter and area of polygons?

Find the missing measures using trig

Help 15 pts good luck

It is reported that 56% of a state is experiencing drought conditions. An agricultural researcher randomly selects ten farmers in the state and asks if their farms are experiencing drought. What is the expected number of farmers who have experienced drought? Find the standard deviation.

please answer it's easy ​

Complete the equation so that it represents the proportional relationship
shown in the table.

What is the name of the object pictured below?

Can someone please help no links and if you can explain thank you so much ​

A popular game requires the player to select the same five numbers out of a set of allowed numbers that will be drawn at random by the lottery commission. For the next game, if you select the five numbers that won in the most recent prior drawing, your chances of winning will:

which equation has a slope of -1/4?

A) y=4
B) y=-4x
C) y=-1/4x+1
D) y=4x+9
E) x=-1/4
F) y=-1/4

How do you write an equation in slope-intercept form for the line through the given points (8, 10) and (14, 13)

Please help I’m struggling please

Prove that triangle Bad is congruent to triangle ABC​

Will give brainliest

Find the area of this triangle.
Round to the nearest tenth.
7 in
133
13 in
[ ? ) in2

3. The rectangle below has an area of 297 in. Find the length of the diagonal.
14
27 in.
odhad.

Help with this question pls

2x+8>4 translate the inequality into written language

Are these two angles complementary, supplementary, or neither?
530
1270
Complementary Angles
Supplementary Angles
Neither

6 Melvin and Roberto played football on two different teams last season.
• Melvin's team won w games.
• Roberto's team won 3 fewer games than Melvin's team.
Which expression can be used to represent the number of games Roberto's
team won last season?
Select one answer.
A W + 3
BW-3
CW.3
Dw3

Write the following as an inequality. x is greater than 4 and less than or equal to 8 Use x only once in your inequality. pls hurry i will give brainlist​

A number than can be written as a ratio
of two integers a and b, where b is not
zero

Please help ASP!!!! A= positive, B=Negative, C=Zero​

help pls ! need it asap

Employee Earnings per
month($)
1

1,200

2

2,600

3

1,800

4

1,450

5

3,500

6

2,800

7

12,500

8

3,200

Compare and 1.6. Use <, >, or =.
A. 5/3 = 1.6
B. 5/3 < 1.6
c. 5/3 > 1.5

Omlll, I'm actually stuck rn xD If anyone can help,i'd appreciate it so much!! Tyssmm!!!!!

Help- this is also due tomorrow-