1. The two vectors parallel to the plane: Vector AB = (8, -5, 4) and Vector AC = (0, 7, 6)
2. The vector perpendicular to the plane is (-58, -48, 56).
How do we calculate for vectors parallel and perpendicular to the plane?
To find the vectors parallel to the plane, we begin by finding the vectors AB and AC.
Vector AB = B - A = (11 - 3, -5 - 0, 2 - (-2)) = (8, -5, 4)
Vector AC = C - A = (3 - 3, 7 - 0, 4 - (-2)) = (0, 7, 6)
To find a vector perpendicular to the plane, we can take the cross product of the two vectors we found in part (a), AB and AC.
AB × AC = (AB_y * AC_z - AB_z * AC_y, AB_z * AC_x - AB_x * AC_z, AB_x * AC_y - AB_y * AC_x)
If we insert the figures, it will be
= ((-5) x 6 - 4 x 7, 4 x 0 - 8 x 6, 8 x 7 - (-5) x 0)
= (-30 - 28, -48, 56)
= (-58, -48, 56)
Consider the plane determined by the points A(3, 0, -2), B(11, -5, 2) and C(3, 7, 4).
a. Find two vectors parallel to the plane and name each vector appropriately.
b. Find a vector perpendicular to the plane.
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Please see the attached
Elsa has a 5:7 an odd of getting an extra-large stuffed animal against her.
Elsa has a 7:5 chance in her favor of getting an extra-large stuffed animal.
How to calculate odds?(a) The total number of balloons is 1 + 2 + 2 + 7 = 12. The number of balloons that are not extra-large is 1 + 2 + 2 = 5. So the odds against Elsa winning an extra-large stuffed animal are 5:7.
(b) The odds in favor of Elsa winning an extra-large stuffed animal are the opposite of the odds against winning an extra-large stuffed animal. So the odds in favor of Elsa winning an extra-large stuffed animal are 7:5.
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What is the perimeter of the polygon?
Given: ABCD is a trapezoid, AD = 10, BC = 8, CK - altitude ,Area of ∆ACD = 30.Find: Area of ABCD
BTW:the answer is somehow not 54
The area of ACD based on the information given will be 54 units².
How to calculate the areaThe area of a trapezoid is calculated as follows:
(base1 + base2) height / 2 = Area
where base1 and base2 are the lengths of the trapezoid's two parallel sides, and height is the perpendicular distance between them.
So, assuming you have the measurements for base1, base2, and height, you can use the formula above to compute the area of the trapezoid.
Area = 1/2 × (10 + 8) × 6
Area = 1/2 × 18 × 6
Area = 54 units ²
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Simplify the product using the distributive property
(3h - 5)(5h + 4)
Step-by-step explanation:
(3h - 5)(5h + 4) = 3h * 5h + 3h * 4 - 5*5h - 5 *4
= 15h^2 - 13h -20
[tex](3h-5)(5h+4)[/tex]
[tex]=(3h+-5)(5h+4)[/tex]
[tex]=(3h)(5h)+(3h)(4)+(-5)(5h)+(-5)(4)[/tex]
[tex]=15h^2+12h-25h-20[/tex]
Answer:
[tex]\bold{=15h^2-13h-20}[/tex]What is the distance between the points located at (−7, −18) and (−7, 25)?
7 units
43 units
−43 units
−7 units
Answer:
43
Step-by-step explanation:
The distance formula is
[tex] \sqrt{{(x2 - x1)}^{2} + (y2 - y1)^{2} } [/tex]
So
[tex] \sqrt{(25 + 18) ^{2} + ( - 7 + 7)^{2} } \\ = \sqrt{ {43}^{2} + 0 {}^{2} } = 43[/tex]
Answer:
43 unitsStep-by-step explanation:
The distance between the two given points can be found using the formula for the distance between two points in a coordinate plane,
which is d = √((x₂ - x₁)² + (y₂ - y₁)²). In this case, the x-coordinates of both points are the same (-7), so we only need to calculate the difference between their y-coordinates: d = √((0)² + (25 - (-18))²) = √(43²) = 43 units. Therefore, the distance between the two points located at (-7, -18) and (-7, 25) is 43 units
For a standard normal distribution, find (as a decimal NOT a percent):
P(Z > 1.5)
The approximate z-score that corresponds to a right tail area of 1.50 is 0.066807
Calculating the probability of values from the the z-scoresFrom the question, we have the following parameters that can be used in our computation:
P(Z > 1.5)
This means that we calculate the z-score right tail area of 1.50
This is represented as
Probability = (z > 1.50)
Using a graphing calculator, we have
Probability = 0.066807
Hence, the probability value is 0.066807
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Choose the best multiple choice option below! Thanks in advance!
Answer:
Q5. D, Q6. D, Q9. B.--------------------
Question 5The range of the given function has one restriction, its denominator can't be zero, hence:
3x + 4 ≠ 0 ⇒ 3x ≠ - 4 ⇒ x ≠ - 4/3Therefore the function can get any value but zero:
y ≠ 0The matching answer choice is D.
Question 6Linear function is f(x) = mx + b.
Reciprocal of a function f(x) is 1/f(x).
So the reciprocal of linear function has a form of f(x) = 1 / (mx + b).
The only answer choice in same form is D.
Question 9Substitute x = - 5/3 into function to get:
[tex]f(x)=\cfrac{1}{3*(-5/3)+5} =\cfrac{1}{-5+5} =\cfrac{1}{0}[/tex]This is undefined value, therefore it represents the vertical asymptote.
The function gets close to - ∞ when x → - 5/3 from left and gets close to +∞ when x → - 5/3 from right (see attached graph).
Therefore the correct choice is B.
The television show Pretty Betty has been successful for many years. That show recently had a share of 15, which means, that among the TV sets in use, 15% were tuned to Pretty Betty. An advertiser wants to verify that 15% share value by conducting its own survey, and a pilot survey begins with 11 households have TV sets in use at the time of a Pretty Betty broadcast. Find the probability that none of the households are tuned to Pretty Betty. P(none) = Find the probability that at least one household is tuned to Pretty Betty. P(at least one) = Find the probability that at most one household is tuned to Pretty Betty. P(at most one) =
The probabilities will be :
P(none) = 0.018
P(at least one) = 0.982
P(at most one) = 0.187
What are the probabilities?Pretty Betty share is 15%, the probability that any one household is tuned to the show will be: 0.15.
To find the probability that none of the households are tuned to Pretty Betty will be:
P(none) = 0.85¹¹
≈ 0.018
So, to find the probability that at least one household is tuned to Pretty Betty, i use the complement rule as well as subtract the probability of none of the households being tuned to the show from 1:
P(at least one)
= 1 - P(none)
≈ 1 - 0.018
≈ 0.982
So, to find the probability that at most one household is tuned to Pretty Betty:
P(at most one) = P(none) + P(one)
= 0.85^11 + 11(0.15)(0.85^10)
≈ 0.187
Hence, the probabilities will be :
P(none) = 0.018
P(at least one) = 0.982
P(at most one) = 0.187
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The diagram shows a calculator screen on which the parabolas y=1/4(x-3)(x-8) and y=1/2(x+1)(x-3) have been graphed. The window setting consists of two inequalities, A is less than or equal to X is less than or equal to B and C is less than or equal to Y is less than or equal to D. What are the values of a, b, c, and d?
Answer:
If I am not mistaken a=3;b=10;c=23;d=39
Step-by-step explanation:
HELP PLSZZZZSZZZZZZZZZZ need asap
Answer:
the answer is E
Step-by-step explanation:
1. A train travels 16.8 km in 25 minutes. Find the speed of the train in (i) km/h, (ii) m/s. f 55 km/h. Find the distance travelled bynumber, opinion, size, shape, condition, age, color, pattern, origin, materials, and purpose.04-Jan-2022
the speed of the train in km/h is 40.32 whereas the speed of the train in m/s is 11.2.
(i) To find the speed of the train in km/h, we can use the formula:
speed = distance/time
Here, the distance travelled by the train is 16.8 km, and the time taken is 25 minutes, which is equivalent to 0.4167 hours (since 1 hour = 60 minutes). Substituting these values in the formula, we get:
speed = 16.8 km/0.4167 hours
speed = 40.32 km/h (rounded to two decimal places)
Therefore, the speed of the train in km/h is 40.32.
(ii) To find the speed of the train in m/s, we can convert the speed in km/h to m/s by multiplying by 1000/3600 (since 1 km/h = 1000 m/3600 s). Using the speed of 40.32 km/h from part (i), we get:
speed = 40.32 km/h * 1000 m/km / 3600 s/h
speed = 11.2 m/s (rounded to one decimal place)
Therefore, the speed of the train in m/s is 11.2.
If the speed limit is 55 km/h, we cannot directly determine the distance travelled by the train without additional information. The distance travelled by the train would depend on the time it took to travel at the given speed limit.
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At the park there is a pool shaped like a circle with diameter 22 yd. A ring-shaped path goes around the pool. Its
width is 5 yd. If one gallon of coating can cover 5yd many gallons of coating do we need? Note that coating comes only by the gallon so the number of gallons must be a whole number. (Use the value 3.14 for pi.)
Answer: To find the area of the ring-shaped path, we need to subtract the area of the inner circle (the pool) from the area of the outer circle. The radius of the pool is half the diameter, so it is 11 yards. The radius of the outer circle is the sum of the radius of the pool and the width of the path, so it is 11 + 5 = 16 yards.
The area of the pool is:
A_pool = pi * r^2 = pi * 11^2 ≈ 380.13 square yards
The area of the outer circle is:
A_outer = pi * R^2 = pi * 16^2 ≈ 804.25 square yards
The area of the ring-shaped path is:
A_path = A_outer - A_pool ≈ 804.25 - 380.13 ≈ 424.12 square yards
Since one gallon of coating can cover 5 square yards, we need:
Gallons = A_path / 5 ≈ 424.12 / 5 ≈ 84.82
Therefore, we need approximately 85 gallons of coating to cover the ring-shaped path.
Step-by-step explanation:
What is the factored form of 8x24-27y6?
o (8x-27y2) (2x¹+xy+3y*)
ọ (2x³− 3y²)(4x¹6−6x³y² +9y4)
0 (2x³-3y²) (4x¹6 +6x³y² +9yª)
(8x-27y²) (2x¹6-Bxy+3y4)
The factored form of [tex]8x^{2} 4 - 27y^{6}[/tex] 8x²4 - 27y⁶
To factor this expression, that it is in the form of a difference of two squares.
Specifically, 8x²4 is equal to (2x²)³ and 27y⁶ is equal to (3y²)³.
the formula for the difference between two cubes, states that:
[tex]a^3 - b^3 = (a - b)(a^2 + ab + b^2)[/tex] (a³ - b³ = (a - b)(a² + ab + b²)
Substituting [tex]a = 2x^2[/tex] a = 2x² and [tex]b = 3y^2[/tex] b = 3y², gives
[tex]8x^24 - 27y^6 = (2x^2)^3 - (3y^2)^3= (2x^2 - 3y^2)(4x^2 + 6x^2y^2 + 9y^4)[/tex]
8x²4 - 27y⁶ = (2x²)³ - (3y²)³ = (2x² - 3y²)(4x⁴ + 6x²y² + 9y⁴)
Therefore, the factored form of [tex]8x^{2} 4 - 27y^{6}[/tex] 8x²4 - 27y⁶ is [tex](2x^2 - 3y^2)(4x^4 + 6x^2y^2 + 9y^4).[/tex](2x² - 3y²)(4x⁴ + 6x²y² + 9y⁴).
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6.
2. How many more goldfish were given away before noon than in the afternoon? Circle
the letter of the correct answer.
a. 38
b. 30
c. 100
d. 28
3. How many goldfish were given away all day?
4.
Did the owner have enough goldfish for the entire day?
complete sentence.
Statistics
Show your work.
Explain with a
5. How many goldfish were left over, if any? Circle the letter of the correct answer.
a. 8
b. 10
c. 16
d. 0
At 11 a.m., why did the owner get nervous that she might not have enough
goldfish to give away? Use complete sentences to explain your thinking.
7. What might be a reason that no one came into the store at noon? Explain in
complete sentences.
Give the number of the sentence that provides the best evidence for the answer
2. 28 goldfish was what was given away before noon than in the afternoon
3. 108 goldfish were given away all day
4. Yes the owner have enough goldfish for the entire day
5. 16 goldfish were left over
How to solve for the goldfish2. Before noon, gold fish = 30 + 36 + 40 = 106
after noon gold fish = 28 + 30 + 10 + 2 + 8 = 78
diference = 106 - 78
= 28
3. Gold fish given away all day = 106 + 78
= 184
4. The owner had enough fish because the total fist he had was 200 and the amount that was given away is 184
5. The left over fish = 200 - 184
= 16
6. The owner was nervous because the customers were increasing between 9 to 11 and she had given away more than half in the first three hours
7. A reason no one came at noon could be because a resstaurant was having a lunch special
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Find the values of x
and y that make these triangles congruent by the HL theorem quiz: congruence in right triangles
Where the above information about right triangles are given, the asnswer is
A. x = 3, y = 2 (Option A)
How did we arrive at the above?The hypotenuse and the length of one leg of one right triangle must be equal to the hypotenuse and corresponding length of the one leg of the other ∆ for both triangles to be equal by the HL Congruence Theorem.
Thus, let's find x and y by setting the corresponding lengths of the two right ∆s equal to each other.
Therefore:
x = y + 1 ----› eqn. 1
2x + 3 = 3y + 3 ----› eqn. 2
Substitute x = (y + 1) into eqn. 2, and solve for y.
2x + 3 = 3y + 3 ----› eqn. 2
2(y + 1) + 3 = 3y + 3
2y + 2 + 3 = 3y + 3
2y + 5 = 3y + 3
Collect like terms
2y - 3y = -5 + 3
-y = -2
Divide both sides by -1
y = 2
Substitute y = 2 into eqn. 1.
x = y + 1 ----› eqn. 1
x = 2 + 1
x = 3
Thus,
x = 3, and y = 2 (Option A)
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Full Question:
See attached image
[ASAP Please!] Which are the better statistics to use to compare the distributions? Assume you know the mean, median, standard deviation, and IQR for each.
A.
Median and standard deviation
B.
Median and IQR
C.
Mean and standard deviation
D.
Mean and IQR
The better statistics to use to compare the distributions includes mean and standard deviation. The Option C is correct.
How are mean and standard deviation used to compare distributions?Mean represents the central tendency of the distribution, while standard deviation reflects the spread of the data around the mean. Comparing mean & standard deviation of 2 or more distributions can provide insights into similarities and differences.
If the means of two distributions are similar, it suggests the data points in each distribution are centered around similar value. But if standard deviations are also similar, it indicates that the spread of the data points around the mean is also similar.
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For a certain company, the cost function for producing x
items is C(x)=50x+250
and the revenue function for selling x
items is R(x)=−0.5(x−120)2+7,200
. The maximum capacity of the company is 170
items.
1. Required profit function is P(x)= -0.5x² + 60x + 6850
2. The domain of P(x) is 20 - 4√205 ≤ x ≤ 170.
3. P(70) = 2650 and P(80) = 2600.
The company should choose to produce 70 items as it results in a higher profit.
4. The leads to a decrease in profit, which is why the company makes less profit when producing 10 more units.
What is profit function?
A profit function is a mathematical formula that describes the relationship between the level of production or sales and the resulting profit of a business. The profit function takes into account the costs of production, including fixed costs and variable costs, and the revenue generated by the sale of goods or services.
1. The profit function P(x) is given by subtracting the cost function C(x) from the revenue function R(x):
P(x) = R(x) - C(x)
= [−0.5(x−120)²+7,200] - [50x+250]
= -0.5x² + 60x + 6850
2. The domain of P(x) is the set of all possible values of x for which the profit function P(x) makes sense. Since P(x) involves subtracting the cost function from the revenue function, it only makes sense to calculate P(x) when the revenue generated from selling x items is greater than or equal to the cost of producing x items. Therefore, the domain of P(x) is the set of all x such that R(x) ≥ C(x),
R(x) ≥ C(x)
-0.5(x−120)²+7,200 ≥ 50x+250
-0.5x²+60x+6850 ≥ 50x+250
-0.5x²+10x+6600 ≥ 0
Solving for x, we get:
x ≤ 20 - 4√205 or x ≥ 20 + 4√205
Since the maximum capacity of the company is 170 items, the domain of P(x) is the intersection of the above solution and the maximum capacity, i.e. x ≤ 170. Therefore, the domain of P(x) is 20 - 4√205 ≤ x ≤ 170.
3. To find the profit when producing 70 items, substitute x = 70 into the profit function P(70) = -0.5(70)² + 60(70) + 6850
= 2650
To find the profit when producing 80 items, substitute x = 80 into the profit function P(80) = -0.5(80)² + 60(80) + 6850
= 2600
Therefore, the company should choose to produce 70 items as it results in a higher profit.
4. The profit function P(x) is a quadratic function with a negative leading coefficient (-0.5), which means that it opens downwards. This implies that the profit function reaches its maximum value at the vertex of the parabola, which occurs at x = -b/2a, where a = -0.5 and b = 60. Therefore, the vertex occurs at x = -60/-1 = 60. This means that the maximum profit occurs at x = 60.
When the company produces 10 more units (i.e. x increases by 10), it moves away from the optimal production level of 60 and closer to the maximum capacity of 170. As a result, the cost of production increases while the revenue generated from selling those extra units decreases due to diminishing returns. This leads to a decrease in profit, which is why the company makes less profit when producing 10 more units.
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The winning long jump at a track meet was 27 ft 10 in. Convert this distance to meters. Round to the nearest hundredth.
The distance, 27 ft 10 in, is equivalent to 8.48 meters.
The Conversion Factor:1. Convert 27 ft first to inches by multiplying it by a conversion factor.
2. Add the converted value to 10 inches.
3. Convert the inch measure by multiplying it by a conversion factor.
4. Round to the nearest hundredth.
Convert the factor 12 inch/ 1 ft.
since 1 foot is equivalent to 12 inches.
= 27 ft × [tex]\frac{12inch}{1ft}[/tex] + 10 inch = 324 inch + 10 inch = 334 inch
This means that 27 ft 10 in is equivalent to 47/2 inches.
Again, The conversion factor 0.0254 m/ 1 inch
since there are 0.0254 meters in an inch.
[tex]334 inches[/tex] × [tex]\frac{0.00254 meters}{1 inch}[/tex]
= 334 × 0.00254 meters
= 8.4836 meters
Thus, distance, 25 ft and 20 inches, is equivalent to approximately 8.48 meters.
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URGENT!! ILL GIVE
BRAINLIEST! AND 100 POINTS
Answer:
Plot the points on the graphing calculator, and then determine the linear regression function: y = -1.16786x + 8.82857
You may obtain a slightly different linear regression equation.
1) -1 (g)
2) 8 (not one of the choices)
3) graph (i)
4) approximately -1/strong negative trend (not one of the choices)
5) y = -x + 8 (h)
Given this equation what is the value of y at the indicated point?
Answer:
y = [tex]\sqrt{11}[/tex]
Step-by-step explanation:
Substitute -4 for x and solve for y
[tex]y^{2}[/tex] = -2x + 3
[tex]y^{2}[/tex] = -2(-4) + 3
[tex]y^{2}[/tex] = 8 + 3
[tex]y^{2}[/tex] = 11
[tex]\sqrt{y^{2} }[/tex] = [tex]\sqrt{11}[/tex]
y = [tex]\sqrt{11}[/tex]
Helping in the name of Jesus.
Consider the function defined by f(x) for x > 0 and its graph y = f(x).
The graph of f has a horizontal tangent at point P. Find the coordinates of P.
This means that the coordinates of P are (a, b), where a is the value for which f'(a) = 0, and b = f(a).
What is coordinate?The term "coordinate" generally refers to a value or set of values that describe the position or location of a point or object in a particular system or space. In mathematics, coordinates are typically used to describe the position of a point on a graph or in a geometric plane, and they usually consist of a set of numerical values that indicate the distance or direction of the point from a specified origin or reference point. In geographic or cartographic contexts, coordinates might refer to latitude and longitude values that indicate a specific location on the Earth's surface. Other systems may use different types of coordinates, but the underlying idea is usually the same: a set of values that describe the position of an object or point in a given space or system.
if the graph of f has a horizontal tangent at point P, this means that the slope of the tangent line at P is zero.
Let (a, b) be the coordinates of P. Then the equation of the tangent line at P is:
[tex]y - b = f'(a)(x - a)[/tex]
Since the slope of the tangent line at P is zero, we have:
f'(a) = 0
This means that the derivative of f at x = a is zero. So, we need to find the value of a for which f'(a) = 0.
Once we find the value of a, we can substitute it into the equation of the tangent line to find the value of b.
So, let's find f'(x) first:
f(x) = ... (the function is not given, so we cannot find f'(x) explicitly)
We know that f'(a) = 0, so we have:
[tex]f'(a) = lim h- > 0 [f(a+h) - f(a)]/h = 0[/tex]
This means that:
[tex]lim h- > 0 [f(a+h) - f(a)]/h = 0[/tex]
Multiplying both sides by h, we get:
[tex]lim h- > 0 [f(a+h) - f(a)] = 0[/tex]
Taking the limit as h approaches 0, we get:
[tex]f(a) - f(a) = 0[/tex]
So, we have:
[tex]f(a) = b[/tex]
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The distance between Eilat and Jerusalem is 292 kilometers. Give this distance in miles. Round the answer to the nearest tenth.
The distance between Eilat and Jerusalem is 181.4 miles.
To convert kilometers to miles, we need to multiply the number of kilometers by 0.621371, which is the conversion factor from kilometers to miles. Therefore, to convert the distance between Eilat and Jerusalem from kilometers to miles, we can use the following formula:
distance in miles = distance in kilometers × 0.621371
Substituting the given distance of 292 kilometers into the formula, we get:
distance in miles = 292 km × 0.621371 = 181.417852 miles
Rounding this answer to the nearest tenth, we get:
distance in miles ≈ 181.4 miles
Therefore, the distance between Eilat and Jerusalem is approximately 181.4 miles.
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The amount of snowfall in December was 5 7/8 feet. The amount of snowball in October was 1/4 feet. How much more snowfall was there in December? Write your answer as a mixed number in simplest form.
Answer: 5 5/8 more feet of snow in December.
Step-by-step explanation: 5 7/8 also equals 47/8, and we need convert 1/4 to something over 8 so we can subtract the two. 1/4, but multiply both sides by 2 is 2/8. 47/8-2/8=45/8. 45/8 as a mixed fraction is 5 5/8.
Find [tex]A(3,4)[/tex].
HINT: [tex]A(1,n)=2^n[/tex] whenever [tex]n \geq 1[/tex]
Along with proof of (a.) and (d.), (b.) Power tower: one level is a, (k + 1) levels is a raised to the power of a power tower with k levels, (c.) A(2, n) <= 2 ↑↑ n for all positive integers n, where ↑↑ denotes power tower notation.
What is an Ackermann function?The idea of a fully computable function that is not primitive recursive is illustrated by the recursively constructed mathematical function known as the Ackermann function. Since m and n are non-negative integers, it is commonly written as A(m, n).
a.) Prove using regular induction that [tex]A(1, n) \leq 2^n[/tex] for all positive integers n:
Base Case: For n = 1, A(1, 1) = 2, which is equal to [tex]2^1[/tex].
Inductive Hypothesis: Assume that [tex]A(1, k) \leq 2^k[/tex] for some positive integer k.
Inductive Step: We need to show that [tex]A(1, k + 1) \leq 2^{(k + 1)}[/tex]. Using the recursive definition of A(m, n), we have [tex]A(1, k + 1) = A(0, A(1, k)) = 2^{(A(1, k))}\leq 2^{(2^k)}[/tex] (by inductive hypothesis)[tex]< = 2^{(2^{(k + 1)})}[/tex].
Therefore, by regular induction, we have proved that [tex]A(1, n) \leq 2^n[/tex] for all positive integers n.
b.) A power tower with one level is defined as a, and a power tower with (k + 1) levels is defined as a raised to the power of a power tower with k levels.
c.) [tex]A(2, n) \leq 2[/tex] ↑↑ n for all positive integers n, where ↑↑ denotes power tower notation.
d.) The recursive definition of a triple arrow-up notation for power towers is:
a ↑↑↑ 1 = a (base case)
a ↑↑↑ (k + 1) = a ↑↑ (a ↑↑↑ k) (recursive step)
This definition states that a triple arrow-up notation with one level is equal to the base value "a", and a triple arrow-up notation with (k + 1) levels is equal to "a" raised to the power of a triple arrow-up notation with "k" levels.
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Complete Question: ( Refer to image)
Solve the following equations graphically. (x +1)(y − 2) = 0
Answer:
(-1, 2)
Step-by-step explanation:
When an equation is formatted like this, you can just reverse the operators (in this case +1 and -2) and you'll get your coordinates.
Question 19 You want to buy an ordinary annuity that will pay you R4,000 a year for the next 20 years. You expect annual interest rates will be 8 percent over that time period. The maximum price you would be willing to pay for the annuity is closest to [1] R32,000 [2] R39,272 [3] R40,000 [4] R80,000
The maximum price you should be willing to pay for the annuity, given the cash flow and the interest rates, would be 2. R 39, 272
How to find the maximum price ?The maximum price to be paid for the annuity would be the present value of the annuity which can be found by the formula :
= Annuity x Present value interest factor of annuity, 20 years, 8 %
The annuity = R 4, 000
Present value interest factor of annuity, 20 years, 8 % = 9. 81815
The maximum you should pay for the annuity is therefore:
= 4, 000 x 9. 81815
= R 39, 272 . 60
= R 39, 272
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what is the equation that best models the data from the table after the data has been linearized? a. log y = 0.116315x+0.249114
b. log y = 0.249114x+0.116315
c. log y = 0.0288761x+0.435269
d. log y = 0.435269x+0.0288761
Okay, let's analyze the linearized data options to determine which equation best models it:
a. log y = 0.116315x+0.249114
This has a positive slope coefficient of 0.116315, so it will model increasing data. But the y-intercept term 0.249114 is negative, so the model line would start below the origin. This does not seem to match the typical linear relationship we would expect.
b. log y = 0.249114x+0.116315
This also has a positive slope coefficient, but now the y-intercept term 0.116315 is positive. This could potentially model increasing data that starts above the origin. However, without seeing the data it's hard to definitively say if this is the best fit.
c. log y = 0.0288761x+0.435269
This has a positive but much smaller slope coefficient of 0.0288761. This would model increasing data at a much shallower rate. Again, without seeing the data we can't rule this out, but it seems less likely.
d. log y = 0.435269x+0.0288761
This has a larger positive slope coefficient of 0.435269, so it would model increasing data at a steeper rate. And the positive y-intercept term of 0.0288761 ensures the model line starts above the origin.
Of these 4 options, choice d (log y = 0.435269x+0.0288761) seems the most likely to best model increasing linear data that starts above the origin. However, without seeing the actual data points, we can't say that with certainty. The slope and intercept values would need to give the closest fit to the data for that to be the definitive choice.
Let me know if this helps explain the options, or if you have any other questions!
Solve each equation for y. Form the unlock code by putting a dash between each solution (e.g., 1-2-3). Hint: y<10 for all. y²- 1 = 80 (y - 4)÷ 4 = 1 10-63÷y = 1
The solution to the equations for y are y = 9, y = 8 and y = 7
Solving the equations for y.From the question, we have the following parameters that can be used in our computation:
y²- 1 = 80
(y - 4)÷ 4 = 1
10 - 63 ÷ y = 1
Solving the equations, we have
y²- 1 = 80
y² = 81
y = 9
Next, we have
(y - 4)÷ 4 = 1
(y - 4) = 4
y = 8
Lastly, we have
10 - 63 ÷ y = 1
-63 ÷ y = -9
-9y = -63
y = 7
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If X=4, Y=5 and Z=10 Solve (X-Y)+Z
Answer:
9
Step-by-step explanation:
All you have to do is replace the letters with numbers
= ( x - y) + z
= ( 4 - 5) + 10
= -1 + 10
= 10 - 1
= 9
Complete the following, using exact interest. (Use Days in a year table.)
Note: Do not round intermediate calculations. Round the "Interest" and "Maturity value" to the nearest cent.
A loan of $595 borrowed on June 15 and repaid on Dec 17 at an exact interest rate of 6%. The exact time between the two dates is 170 days, and the maturity value is $611.69 rounded to the nearest cent.
Using the Days in a year table, we can find the exact time between June 15 and December 17 as follows
June has 30 days in the table and July through November have 31 days each. December has 17 days until the loan is repaid. Therefore, the exact time is
30 + 31 + 31 + 30 + 31 + 17 = 170 days
Next, we can calculate the interest using the formula
interest = principal x rate x time / 365
where the principal is $595, the rate is 6%, and the time is 170 days.
Substituting these values, we get
interest = 595 x 0.06 x 170 / 365
interest = $16.69
Therefore, the exact interest is $16.69.
Finally, we can calculate the maturity value by adding the principal and the interest
maturity value = principal + interest
maturity value = $595 + $16.69
maturity value = $611.69
Therefore, the maturity value is $611.69 rounded to the nearest cent.
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